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#1
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What I gleaned from the excellent answers for the original "VSWR
Doesn't Matter?" thread is that high VSWR doesn't really matter in a lossless transmission line environment between a transmitter's antenna tuner and the antenna, since any reflected RF energy will simply continue to "bounce" back and forth between the tuner's output impedance and the antenna's input impedance until it is, finally, completely radiated from the antenna without loss. But then why does the concept of "mismatch loss" exist in reference to antennas? I have quickly calculated that if a transmitter outputs 100 watts, and the TX antenna has an impedance that will cause a VSWR of 10:1 -- using lossless transmission line -- that the mismatch loss in this "lossless" system would be 4.81dB! (Reflected power 66.9 watts, RL -1.74). Since mismatch loss is the "amount of power lost due to reflection", and is as if an "attenuator with a value of the mismatch loss where placed in series with the transmission line", then I would think that VSWR would *definitely* matter, and not just for highly lossy lines either. But here again, I'm probably not seeing the entire picture here. What am I missing?? Confused! -Bill |
#2
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billcalley wrote:
Since mismatch loss is the "amount of power lost due to reflection", and is as if an "attenuator with a value of the mismatch loss where placed in series with the transmission line", then I would think that VSWR would *definitely* matter, and not just for highly lossy lines either. But here again, I'm probably not seeing the entire picture here. What am I missing?? If the system is Z0-matched, e.g. antenna tuner, there is a mismatch gain at the tuner that offsets the mismatch loss at the load so, in a lossless system, nothing is lost. Wave cancellation toward the source is balanced by constructive interference toward the load. -- 73, Cecil, w5dxp.com |
#3
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On Mar 29, 1:34 pm, Cecil Moore wrote:
billcalley wrote: Since mismatch loss is the "amount of power lost due to reflection", and is as if an "attenuator with a value of the mismatch loss where placed in series with the transmission line", then I would think that VSWR would *definitely* matter, and not just for highly lossy lines either. But here again, I'm probably not seeing the entire picture here. What am I missing?? If the system is Z0-matched, e.g. antenna tuner, there is a mismatch gain at the tuner that offsets the mismatch loss at the load so, in a lossless system, nothing is lost. Wave cancellation toward the source is balanced by constructive interference toward the load. -- 73, Cecil, w5dxp.com Now my head *really* hurts! This is a VERY confusing subject, to say the least. (And I also thought antenna tuners actually had a *loss* due to their limited Q...I think I'm going to change careers now and just become a pet groomer; or perhaps simply give up completely and work at Radio Shack). -Bill |
#4
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billcalley wrote:
Now my head *really* hurts! This is a VERY confusing subject, to say the least. (And I also thought antenna tuners actually had a *loss* due to their limited Q...I think I'm going to change careers now and just become a pet groomer; or perhaps simply give up completely and work at Radio Shack). Real-world antenna tuners do have a loss but we previously specified a lossless system. Of course, real world tuners and transmission lines suffer losses but we all just live with those losses while striving to minimize them. The point is that an antenna tuner reflects most of the reflected energy back toward the load thus accomplishing a mismatch gain that offsets some, if not most, of the mismatch loss. High SWR transmission lines are indeed lossier than flat matched transmission lines of the same material. -- 73, Cecil, w5dxp.com |
#5
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Cecil Moore wrote:
billcalley wrote: Now my head *really* hurts! This is a VERY confusing subject, to say the least. (And I also thought antenna tuners actually had a *loss* due to their limited Q...I think I'm going to change careers now and just become a pet groomer; or perhaps simply give up completely and work at Radio Shack). Real-world antenna tuners do have a loss but we previously specified a lossless system. Of course, real world tuners and transmission lines suffer losses but we all just live with those losses while striving to minimize them. The point is that an antenna tuner reflects most of the reflected energy back toward the load thus accomplishing a mismatch gain that offsets some, if not most, of the mismatch loss. High SWR transmission lines are indeed lossier than flat matched transmission lines of the same material. -- 73, Cecil, w5dxp.com Close but no cigar. The (now often automatic) antenna tuner is used to transform the native impedance to the transmitter to match the conjugate transformed impedance of the antenna at the transmitter end of the transmission line. The effective result is that the incident energy arriving at the antenna "sees" a matched load and goes out to free space instead of bouncing off the transmission line to antenna interface. This is also why better antennas have reasonable (not far off matching impedance) characteristic impedances; they do not require matching networks physically placed at the antenna itself. -- JosephKK Gegen dummheit kampfen die Gotter Selbst, vergebens.Â*Â* --Schiller |
#6
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billcalley wrote:
On Mar 29, 1:34 pm, Cecil Moore wrote: billcalley wrote: Since mismatch loss is the "amount of power lost due to reflection", and is as if an "attenuator with a value of the mismatch loss where placed in series with the transmission line", then I would think that VSWR would *definitely* matter, and not just for highly lossy lines either. But here again, I'm probably not seeing the entire picture here. What am I missing?? If the system is Z0-matched, e.g. antenna tuner, there is a mismatch gain at the tuner that offsets the mismatch loss at the load so, in a lossless system, nothing is lost. Wave cancellation toward the source is balanced by constructive interference toward the load. -- 73, Cecil, w5dxp.com Now my head *really* hurts! This is a VERY confusing subject, to say the least. (And I also thought antenna tuners actually had a *loss* due to their limited Q...I think I'm going to change careers now and just become a pet groomer; or perhaps simply give up completely and work at Radio Shack). If you start considering loss in the tuner and the line then yes, a greater mismatch between the antenna and the line will result in more lost power (and more component heating in the tuner). You really want to leave that subject be until you understand the properties of a lossless system. -- Tim Wescott Wescott Design Services http://www.wescottdesign.com Posting from Google? See http://cfaj.freeshell.org/google/ Do you need to implement control loops in software? "Applied Control Theory for Embedded Systems" gives you just what it says. See details at http://www.wescottdesign.com/actfes/actfes.html |
#7
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![]() Yes, and it should hurt , because we are using English and text to show something that s/b shown in pictures . Im E.E. , KC7CC, and more.. i can simply show you with pictures. It will be instantly clear . ---BTW------ Im doin ARM computers , I will give a free Op System . It will NOT use English nor ASCII . No arbitrary definitions ... No C++ , No Linux , No M$ , no more "Free Lunch" ..... We use Coax for its isolation from nearby absorbers .. parallel line is much lower loss but absorbs into other objects close . We do not use caps , but stubs . But they are tuned ( freq dependent ) . The fast way to follow this , is to draw a picture , then edit it as you go . English will only get you a college degree and a free lunch ( Liberals ) . __________________________________ Now my head *really* hurts! This is a VERY confusing subject, to say the least. (And I also thought antenna tuners actually had a *loss* due to their limited Q...I think I'm going to change careers now and just become a pet groomer; or perhaps simply give up completely and work at Radio Shack). -Bill |
#8
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![]() "billcalley" wrote in message oups.com... What I gleaned from the excellent answers for the original "VSWR Doesn't Matter?" thread is that high VSWR doesn't really matter in a lossless transmission line environment between a transmitter's antenna tuner and the antenna, since any reflected RF energy will simply continue to "bounce" back and forth between the tuner's output impedance and the antenna's input impedance until it is, finally, completely radiated from the antenna without loss. That's basically true but ignores the stress that can be placed on the output circuit of the transmitter. Why do you think VSWR shut-down circuits are so popular? One can see rather high voltages or currents that are potentially damaging to the transistors and capacitors. Now, since "lossless" is an abstraction and all materials have voltage and current limits, just make this easy on yourself and always strive for a VSWR of 2:1 or less. It simply works better and is more reliable. |
#9
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Charles Schuler wrote:
Now, since "lossless" is an abstraction and all materials have voltage and current limits, just make this easy on yourself and always strive for a VSWR of 2:1 or less. It simply works better and is more reliable. But renders many all-HF-band dipoles useless. :-) I regularly run up to an 18:1 SWR on my 450 ohm ladder-line. Owen's transmission line calculator says I'm losing about 0.8 dB in 100' of line under those conditions on 40m. IMO, it's a small price to pay for all-HF-band operation. -- 73, Cecil, w5dxp.com |
#10
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![]() "Cecil Moore" wrote in message ... Charles Schuler wrote: Now, since "lossless" is an abstraction and all materials have voltage and current limits, just make this easy on yourself and always strive for a VSWR of 2:1 or less. It simply works better and is more reliable. But renders many all-HF-band dipoles useless. :-) I regularly run up to an 18:1 SWR on my 450 ohm ladder-line. Owen's transmission line calculator says I'm losing about 0.8 dB in 100' of line under those conditions on 40m. IMO, it's a small price to pay for all-HF-band operation. How many Ham transmitters have a balanced output? How are you feeding a balanced line? If you are using an antenna tuner with unbalanced in (50 ohms) and balanced out (variable impedance), you should be OK in most situations. |
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