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Old March 29th 07, 09:10 PM posted to sci.electronics.design,sci.electronics.basics,rec.radio.amateur.antenna
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Default VSWR doesn't matter? But how about "mismatch loss"?

What I gleaned from the excellent answers for the original "VSWR
Doesn't Matter?" thread is that high VSWR doesn't really matter in a
lossless transmission line environment between a transmitter's antenna
tuner and the antenna, since any reflected RF energy will simply
continue to "bounce" back and forth between the tuner's output
impedance and the antenna's input impedance until it is, finally,
completely radiated from the antenna without loss.

But then why does the concept of "mismatch loss" exist in
reference to antennas? I have quickly calculated that if a
transmitter outputs 100 watts, and the TX antenna has an impedance
that will cause a VSWR of 10:1 -- using lossless transmission line --
that the mismatch loss in this "lossless" system would be 4.81dB!
(Reflected power 66.9 watts, RL -1.74).

Since mismatch loss is the "amount of power lost due to
reflection", and is as if an "attenuator with a value of the mismatch
loss where placed in series with the transmission line", then I would
think that VSWR would *definitely* matter, and not just for highly
lossy lines either. But here again, I'm probably not seeing the
entire picture here. What am I missing??

Confused!

-Bill

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Old March 29th 07, 09:34 PM posted to sci.electronics.design,sci.electronics.basics,rec.radio.amateur.antenna
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Default VSWR doesn't matter? But how about "mismatch loss"?

billcalley wrote:
Since mismatch loss is the "amount of power lost due to
reflection", and is as if an "attenuator with a value of the mismatch
loss where placed in series with the transmission line", then I would
think that VSWR would *definitely* matter, and not just for highly
lossy lines either. But here again, I'm probably not seeing the
entire picture here. What am I missing??


If the system is Z0-matched, e.g. antenna tuner, there is
a mismatch gain at the tuner that offsets the mismatch
loss at the load so, in a lossless system, nothing is
lost. Wave cancellation toward the source is balanced
by constructive interference toward the load.
--
73, Cecil, w5dxp.com
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Old March 29th 07, 09:57 PM posted to sci.electronics.design,sci.electronics.basics,rec.radio.amateur.antenna
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Default VSWR doesn't matter? But how about "mismatch loss"?

On Mar 29, 1:34 pm, Cecil Moore wrote:
billcalley wrote:
Since mismatch loss is the "amount of power lost due to
reflection", and is as if an "attenuator with a value of the mismatch
loss where placed in series with the transmission line", then I would
think that VSWR would *definitely* matter, and not just for highly
lossy lines either. But here again, I'm probably not seeing the
entire picture here. What am I missing??


If the system is Z0-matched, e.g. antenna tuner, there is
a mismatch gain at the tuner that offsets the mismatch
loss at the load so, in a lossless system, nothing is
lost. Wave cancellation toward the source is balanced
by constructive interference toward the load.
--
73, Cecil, w5dxp.com


Now my head *really* hurts! This is a VERY confusing subject, to
say the least. (And I also thought antenna tuners actually had a
*loss* due to their limited Q...I think I'm going to change careers
now and just become a pet groomer; or perhaps simply give up
completely and work at Radio Shack).

-Bill


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Old March 29th 07, 10:09 PM posted to sci.electronics.design,sci.electronics.basics,rec.radio.amateur.antenna
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Default VSWR doesn't matter? But how about "mismatch loss"?

billcalley wrote:
Now my head *really* hurts! This is a VERY confusing subject, to
say the least. (And I also thought antenna tuners actually had a
*loss* due to their limited Q...I think I'm going to change careers
now and just become a pet groomer; or perhaps simply give up
completely and work at Radio Shack).


Real-world antenna tuners do have a loss but we previously
specified a lossless system. Of course, real world tuners
and transmission lines suffer losses but we all just live
with those losses while striving to minimize them. The point
is that an antenna tuner reflects most of the reflected
energy back toward the load thus accomplishing a mismatch
gain that offsets some, if not most, of the mismatch loss.
High SWR transmission lines are indeed lossier than flat
matched transmission lines of the same material.
--
73, Cecil, w5dxp.com
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Old April 5th 07, 09:56 AM posted to sci.electronics.design,sci.electronics.basics,rec.radio.amateur.antenna
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Default VSWR doesn't matter? But how about "mismatch loss"?

Cecil Moore wrote:

billcalley wrote:
Now my head *really* hurts! This is a VERY confusing subject, to
say the least. (And I also thought antenna tuners actually had a
*loss* due to their limited Q...I think I'm going to change careers
now and just become a pet groomer; or perhaps simply give up
completely and work at Radio Shack).


Real-world antenna tuners do have a loss but we previously
specified a lossless system. Of course, real world tuners
and transmission lines suffer losses but we all just live
with those losses while striving to minimize them. The point
is that an antenna tuner reflects most of the reflected
energy back toward the load thus accomplishing a mismatch
gain that offsets some, if not most, of the mismatch loss.
High SWR transmission lines are indeed lossier than flat
matched transmission lines of the same material.
--
73, Cecil, w5dxp.com

Close but no cigar. The (now often automatic) antenna tuner is used to
transform the native impedance to the transmitter to match the conjugate
transformed impedance of the antenna at the transmitter end of the
transmission line. The effective result is that the incident energy
arriving at the antenna "sees" a matched load and goes out to free space
instead of bouncing off the transmission line to antenna interface.
This is also why better antennas have reasonable (not far off matching
impedance) characteristic impedances; they do not require matching networks
physically placed at the antenna itself.
--
JosephKK
Gegen dummheit kampfen die Gotter Selbst, vergebens.Â*Â*
--Schiller


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Old March 29th 07, 11:48 PM posted to sci.electronics.design,sci.electronics.basics,rec.radio.amateur.antenna
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Default VSWR doesn't matter? But how about "mismatch loss"?

billcalley wrote:
On Mar 29, 1:34 pm, Cecil Moore wrote:
billcalley wrote:
Since mismatch loss is the "amount of power lost due to
reflection", and is as if an "attenuator with a value of the mismatch
loss where placed in series with the transmission line", then I would
think that VSWR would *definitely* matter, and not just for highly
lossy lines either. But here again, I'm probably not seeing the
entire picture here. What am I missing??

If the system is Z0-matched, e.g. antenna tuner, there is
a mismatch gain at the tuner that offsets the mismatch
loss at the load so, in a lossless system, nothing is
lost. Wave cancellation toward the source is balanced
by constructive interference toward the load.
--
73, Cecil, w5dxp.com


Now my head *really* hurts! This is a VERY confusing subject, to
say the least. (And I also thought antenna tuners actually had a
*loss* due to their limited Q...I think I'm going to change careers
now and just become a pet groomer; or perhaps simply give up
completely and work at Radio Shack).

If you start considering loss in the tuner and the line then yes, a
greater mismatch between the antenna and the line will result in more
lost power (and more component heating in the tuner). You really want
to leave that subject be until you understand the properties of a
lossless system.

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com

Posting from Google? See http://cfaj.freeshell.org/google/

Do you need to implement control loops in software?
"Applied Control Theory for Embedded Systems" gives you just what it says.
See details at http://www.wescottdesign.com/actfes/actfes.html
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Old March 30th 07, 05:05 PM posted to sci.electronics.design,sci.electronics.basics,rec.radio.amateur.antenna
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Posts: 4
Default VSWR doesn't matter? But how about "mismatch loss"?



Yes, and it should hurt , because we are using
English and text to show something that
s/b shown in pictures .

Im E.E. , KC7CC, and more..

i can simply show you with pictures.
It will be instantly clear .

---BTW------
Im doin ARM computers , I will give a free
Op System . It will NOT use English nor
ASCII . No arbitrary definitions ...
No C++ , No Linux , No M$ , no
more "Free Lunch" .....

We use Coax for its isolation from nearby
absorbers .. parallel line is much lower loss
but absorbs into other objects close .
We do not use caps , but stubs .
But they are tuned ( freq dependent ) .
The fast way to follow this , is to draw
a picture , then edit it as you go .
English will only get you a college degree
and a free lunch ( Liberals ) .


__________________________________


Now my head *really* hurts! This is a VERY confusing subject, to
say the least. (And I also thought antenna tuners actually had a
*loss* due to their limited Q...I think I'm going to change careers
now and just become a pet groomer; or perhaps simply give up
completely and work at Radio Shack).

-Bill



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Old March 29th 07, 10:10 PM posted to sci.electronics.design,sci.electronics.basics,rec.radio.amateur.antenna
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First recorded activity by RadioBanter: Mar 2007
Posts: 3
Default VSWR doesn't matter? But how about "mismatch loss"?


"billcalley" wrote in message
oups.com...
What I gleaned from the excellent answers for the original "VSWR
Doesn't Matter?" thread is that high VSWR doesn't really matter in a
lossless transmission line environment between a transmitter's antenna
tuner and the antenna, since any reflected RF energy will simply
continue to "bounce" back and forth between the tuner's output
impedance and the antenna's input impedance until it is, finally,
completely radiated from the antenna without loss.


That's basically true but ignores the stress that can be placed on the
output circuit of the transmitter. Why do you think VSWR shut-down circuits
are so popular? One can see rather high voltages or currents that are
potentially damaging to the transistors and capacitors.

Now, since "lossless" is an abstraction and all materials have voltage and
current limits, just make this easy on yourself and always strive for a VSWR
of 2:1 or less. It simply works better and is more reliable.


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Old March 29th 07, 10:26 PM posted to sci.electronics.design,sci.electronics.basics,rec.radio.amateur.antenna
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Posts: 3,521
Default VSWR doesn't matter? But how about "mismatch loss"?

Charles Schuler wrote:
Now, since "lossless" is an abstraction and all materials have voltage and
current limits, just make this easy on yourself and always strive for a VSWR
of 2:1 or less. It simply works better and is more reliable.


But renders many all-HF-band dipoles useless. :-) I regularly
run up to an 18:1 SWR on my 450 ohm ladder-line. Owen's
transmission line calculator says I'm losing about 0.8 dB
in 100' of line under those conditions on 40m. IMO, it's
a small price to pay for all-HF-band operation.
--
73, Cecil, w5dxp.com
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Old March 29th 07, 11:00 PM posted to sci.electronics.design,sci.electronics.basics,rec.radio.amateur.antenna
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Posts: 3
Default VSWR doesn't matter? But how about "mismatch loss"?


"Cecil Moore" wrote in message
...
Charles Schuler wrote:
Now, since "lossless" is an abstraction and all materials have voltage
and current limits, just make this easy on yourself and always strive for
a VSWR of 2:1 or less. It simply works better and is more reliable.


But renders many all-HF-band dipoles useless. :-) I regularly
run up to an 18:1 SWR on my 450 ohm ladder-line. Owen's
transmission line calculator says I'm losing about 0.8 dB
in 100' of line under those conditions on 40m. IMO, it's
a small price to pay for all-HF-band operation.


How many Ham transmitters have a balanced output?

How are you feeding a balanced line?

If you are using an antenna tuner with unbalanced in (50 ohms) and balanced
out (variable impedance), you should be OK in most situations.




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