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#11
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Not understanding some parts of wave refraction
On Apr 5, 11:33 am, "MRW" wrote:
On Apr 5, 1:44 pm, "K7ITM" wrote: Others have posted, correctly, that the propagation velocity is slower in some mediums than in others. I think it's a mistake, though, to say that c changes! c is supposed to be a constant, the speed of electromagnetic wave propagation in a vacuum--in fact, I suppose, in a vacuum with no gravitational fields in it. A description of fields in an electromagnetic wave often used the permittivity, epsilon, and permeability, mu, of the medium through which the wave is travelling. If it's through a vacuum, the values of epsilon and mu have values that are used often and have special notation--epsilon-sub-zero and mu- sub-zero. For convenience here, call them eo and uo. Then note that eo*uo = 1/c^2. As you might suspect, the propagation in a medium with larger values of e and u than eo and uo is slower than c. In fact, it should be velocity = sqrt(1/(e*u)). Note that e has the units of capacitance/length -- commonly farads/ meter -- and u has the units of inductance/length -- commonly henries/ meter. But a farad is an ampere*second/volt, and a henry is a volt*second/amp, so the units of sqrt(1/(e*u)) are sqrt(1/((A*sec/ V*meter)*(V*sec/A*meter))) = sqrt(meter^2/sec^2) = meters/sec. A unit analysis is often useful to insure you haven't made a mistake in your manipulation of equations. So...in summary, c = f*w is actually not quite correct. It should be wave_velocity = f*w. c should be reserved to mean only the speed of light in a vacuum. If you're in a non-vacuum medium, and measure very accurately, you'll measure the same frequency, but a shorter wavelength: the wave doesn't travel as far to push a cycle past you, as compared with in vacuum. It's going slower. If the propagation medium is, for example, solid polyethylene (the dielectric of most inexpensive coax cable), you'll find that w is about 0.66 times as much as it is in a vacuum, and the propagation velocity is similarly 0.66*c. Cheers, Tom Thank you everyone! I have a better understanding now. I guess part of my confusion is that on the same chapter thay have a table on the electromagnetic spectrum. In it, they list Radio Waves as having frquencies between 10kHz to 300Ghz and wavelengths of 30,000km to 1mm (I guess the 30,000 km is a typo in the book). Are these wavelength values based in a vacuum then? Clearly, the definition for the frequency range is somewhat arbitrary. The boundary between infra-red and radio waves will probably continue to be blurred as electronics advances further. Radio waves down to much lower frequencies than 10kHz have been used...the longer wavelengths penetrate water further, and are useful for communicating with submarines. So don't be surprised if you come across references to radio signals at 50Hz or so. Because communications with radio waves is almost always based on propagation through the vacuum of space, or through air which is only very slightly slower, yes, the values for wavelength are based on c being a constant, the speed of light in a vacuum. Once you figure out one wavelength-frequency relationship, decade (power-of-ten) values are easy: 1MHz = 300 meters (actually 299.792458, but almost universally taken to be 300...) 10MHz = 30 meters 100MHz = 3 meters etc... Cheers, Tom |
#12
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Not understanding some parts of wave refraction
K7ITM wrote: Hi Jim, Some people may use only c-sub-zero for the speed of light in a vacuum, but most commonly I see it simply as c, a fundamental physical constant. To avoid confusion, I would HIGHLY recommend that either you be very explicit that you're using co as the constant, and c as the speed of light in whatever medium you're dealing with -- OR that you're using c as the constant and whatever other notation for the speed elsewhere. NIST lists the constant both ways: c, c-sub-zero. SEVERAL other places I just looked (reference books from my bookshelf; a web survey including US, UK and European sites--mostly physics sites; several university sites) only used c as the constant, except the NIST site and one other, which both listed it as c or c-sub-zero with equal weight. It's clearly a matter only of notation, but I'll elect to stay with the most commonly used notation, and from what I've seen just now, most think c is a constant. Cheers, Tom Hi Tom - This is becoming circuitous. What you're saying is exactly what led the original correspondent to be confused in the first place. Since the relavant equation doesn't read c = f*w/n, the only way to explain the phenomenon is by using a value of c that varies with medium. That was the entire point. 73. Jim AC6XG |
#13
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Not understanding some parts of wave refraction
K7ITM wrote:
It's clearly a matter only of notation, but I'll elect to stay with the most commonly used notation, and from what I've seen just now, most think c is a constant. That's why I put it in quotes - to signify an unusual notation. -- 73, Cecil, w5dxp.com |
#14
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Not understanding some parts of wave refraction
MRW wrote:
Thank you everyone! I have a better understanding now. I guess part of my confusion is that on the same chapter thay have a table on the electromagnetic spectrum. In it, they list Radio Waves as having frquencies between 10kHz to 300Ghz and wavelengths of 30,000km to 1mm (I guess the 30,000 km is a typo in the book). Are these wavelength values based in a vacuum then? Yes. And it's very, very nearly the same for air. The 30,000 km would be a typo -- the wavelength in a vacuum at 10 kHz would be 30 km. Roy Lewallen, W7EL |
#15
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Not understanding some parts of wave refraction
On Apr 5, 1:14 pm, Jim Kelley wrote:
K7ITM wrote: Hi Jim, Some people may use only c-sub-zero for the speed of light in a vacuum, but most commonly I see it simply as c, a fundamental physical constant. To avoid confusion, I would HIGHLY recommend that either you be very explicit that you're using co as the constant, and c as the speed of light in whatever medium you're dealing with -- OR that you're using c as the constant and whatever other notation for the speed elsewhere. NIST lists the constant both ways: c, c-sub-zero. SEVERAL other places I just looked (reference books from my bookshelf; a web survey including US, UK and European sites--mostly physics sites; several university sites) only used c as the constant, except the NIST site and one other, which both listed it as c or c-sub-zero with equal weight. It's clearly a matter only of notation, but I'll elect to stay with the most commonly used notation, and from what I've seen just now, most think c is a constant. Cheers, Tom Hi Tom - This is becoming circuitous. What you're saying is exactly what led the original correspondent to be confused in the first place. Since the relavant equation doesn't read c = f*w/n, the only way to explain the phenomenon is by using a value of c that varies with medium. That was the entire point. 73. Jim AC6XG Hi Jim, OK, but I still say that, in that case, the equation (c=f*w) uses c in a way that's inconsistent with common usage of c. I don't know if the article quoted by the OP mentions that, or if somewhere it adds other qualification, but if it's not out of context, then it would confuse me, too, if I were trying to understand it for the first time. At the very least, the article should say somewhere that c is the speed of propagation in whatever medium we're dealing with, and if it did, perhaps the OP wouldn't have been confused about it in the first place. His posting makes it very clear to me that HE thought c was a constant, as I would if the author didn't tell me otherwise. Cheers, Tom |
#16
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Not understanding some parts of wave refraction
On 5 Apr 2007 18:15:30 -0700, "K7ITM" wrote:
HE thought c was a constant, as I would if the author didn't tell me otherwise. Hi Tom, The speed of light is always constant - within its frame of reference. It is only for those that inhabit a different frame that it "appears" to be different. By Lorentzian laws, there is no time at the speed of light and everything is simultaneous - source and load are inseparable. To illustrate at a slightly slower speed (from Feynman): "A very interesting example of the slowing of time with motion is furnished mu-mesons (muons), which are particles that disintegrate spontaneously after an average lifetime of 2.2 µS. They come to earth in cosmic rays.... It is clear that in its short lifetime a muon cannot travel, even at the speed of light, much more than 600 meters. But although the muons are created at the top of the atmosphere, some 10 kilometers up, yet they are actually found in a laboratory down here, in cosmic rays. How can that be? The answer is that .... While from OUR own point of view they live considerably longer ... time is increased ... by 1/SQRT(1-(u²/v²))." 73's Richard Clark, KB7QHC |
#17
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Not understanding some parts of wave refraction
Richard Clark wrote:
While from OUR own point of view they live considerably longer ... time is increased ... by 1/SQRT(1-(u²/v²))." I wonder what that implies about the alleged age of the universe? -- 73, Cecil http://www.w5dxp.com |
#18
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Not understanding some parts of wave refraction
On Apr 6, 12:08 am, Richard Clark wrote:
On 5 Apr 2007 18:15:30 -0700, "K7ITM" wrote: HE thought c was a constant, as I would if the author didn't tell me otherwise. Hi Tom, The speed of light is always constant - within its frame of reference. It is only for those that inhabit a different frame that it "appears" to be different. By Lorentzian laws, there is no time at the speed of light and everything is simultaneous - source and load are inseparable. To illustrate at a slightly slower speed (from Feynman): "A very interesting example of the slowing of time with motion is furnished mu-mesons (muons), which are particles that disintegrate spontaneously after an average lifetime of 2.2 µS. They come to earth in cosmic rays.... It is clear that in its short lifetime a muon cannot travel, even at the speed of light, much more than 600 meters. But although the muons are created at the top of the atmosphere, some 10 kilometers up, yet they are actually found in a laboratory down here, in cosmic rays. How can that be? The answer is that .... While from OUR own point of view they live considerably longer ... time is increased ... by 1/SQRT(1-(u²/v²))." 73's Richard Clark, KB7QHC Seems to me you're way off point here, Richard. I'm in my lab, my inertial frame of reference. I send some EM waves through my vacuum chamber and I measure their speed as 2.997...*10^8 meters/second. The same waves continue on through the glass of the bell jar keeping air out of my vacuum, and I happen to notice that their speed through that glass is1.684*10^8 meters/second. I notice that light from my hydrogen light source contains certain well-defined spectral lines, but each of those passes through my vacuum at the same speed. However, I notice that those lines, in a short pulse of light, come out of the glass separated in time slightly, implying that they took different times to get through the glass, and were therefore not even travelling through the glass at the same velocity; I notice no such separation for the light passing through the vacuum. Further, I notice that light from a distant star has apparently the same set of spectral lines, but they are shifted to slightly longer wavelengths. However, they take the same time to pass through the vacuum as my locally-generated hydrogen light. All my measurements are in the same frame of reference, and IN VACUUM the speed of em radiation appears from all my measurements to be the same, no matter its wavelength, even for very long wavelengths, but in other media, still the same inertial reference frame, it's different. I also happen to notice that the light from the distant star was created in a different inertial frame of reference... OK, I'll shut up on this now. Cheers, Tom |
#19
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Not understanding some parts of wave refraction
K7ITM wrote:
I also happen to notice that the light from the distant star was created in a different inertial frame of reference... Not to mention being created in a different medium. -- 73, Cecil http://www.w5dxp.com |
#20
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Not understanding some parts of wave refraction
On Apr 5, 4:40 pm, Roy Lewallen wrote:
Yes. And it's very, very nearly the same for air. The 30,000 km would be a typo -- the wavelength in a vacuum at 10 kHz would be 30 km. Roy Lewallen, W7EL Thanks again everyone! It makes sense to me to just treat c, in this case, as a relative speed dependent on the medium. |
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