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I am skimming thru the Propagation chapter of the ARRL handbook, and I
am having a difficult time understanding the shortening of wavelength and the retainment of frequency. They have an equation showing that wave velocity is: c = f*w (c = m/s, f = frequency, w = wavelength). It also states that during refraction "the wavelength is simultaneously shortened, but the wave frequency (number of crests that pass a certain point in a given unit of time) remains constant." I don't understand. If the wavelength is shortened, then shouldn't the frequency increase instead of remaining constant? |
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