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Analyzing Stub Matching with Reflection Coefficients
Jim Kelley wrote:
It certainly is an interesting way of looking at things, Cecil. It's certainly true that equal and opposite fields cancel. When that's the case though it becomes problematic arguing that there are waves there. The waves are certainly there and are measured in the process of determining the values of the s-parameters. That's enough proof of their existence for me. If you deny their existence, you are denying that the s-parameter measurement procedure is valid. Jim, what happens to the ExB power density in the equal and opposite fields that cancel? -- 73, Cecil, w5dxp.com |
Analyzing Stub Matching with Reflection Coefficients
On Apr 18, 9:19 pm, Cecil Moore wrote:
Dr. Honeydew wrote: Cecil Moore wrote: A Bird wattmeter reads 100 watts forward and 100w reflected. The current in the source is zero. The source is not only not sourcing any forward power, it is also not sinking any reflected power. What complete and utter Texas-size bullsh*t. It's obvious that the source is sourcing the forward voltage wave, and it's sucking up entire reverse voltage wave from the line. And doing it while magically expending zero energy. Perpetual motion is possible, after all. If zero power is being dissipated in the source, it cannot be sourcing the forward voltage wave and it cannot be sucking up the reverse voltage wave. -- 73, Cecil http://www.w5dxp.com Ah, I can see you didn't take me seriously. But I was dead serious. It is absolutely not necessary for the source to be dissipating the reverse wave it sucks up as heat. A challenge: given a linear system consisting of a source of impedance Z1, connected to a line (any length you want; any loss you want) of impedance Z2, and the far end of the line connected to a load of impedance Z3, or even to a different source of impedance Z3 (possibly different frequency, phase, and/or amplitude from the first source). Give us one example, even one, that's not accurately described by source Z1 launching waves into impedance Z2 in the "forward" direction, plus whatever "reverse" wave is on the line doing exactly the expected things at the Z2:Z1 boundary. In other words, viewed from both sides, show us even one instance where the system is not correctly analyzed with your S11--S12 equations for the Z1--Z2 interface. Show us even one instance where those equations will not tell you exactly what happens to waves coming into that interface from either direction, and in fact from both directions at once. What the source does with the incoming wave is another matter, independent of the Z1--Z2 interface. Whether it causes increased or decreased dissipation of heat in the source depends on how the source is made, and the characteristics (phase, amplitude, frequency, ...) of the incoming wave. From the labs, Bunsen |
Analyzing Stub Matching with Reflection Coefficients
Cecil Moore wrote: Gene Fuller wrote: Do you see the common factor in your response about "wave interaction"? In all of your examples there is an interface or some sort of discontinuity. Nobody argues that waves are forever unchanging. However, those changes take place only through interaction with interfaces or other discontinuities. I don't disagree and I have gone on record as saying that reflections only occur at physical impedance discontinuities. You have also gone on record as saying is this: 4/19/07 6:12 AM "The only thing s11(a1) and s12(a2) encounter are each other and that interaction completely changes those two waves. The two waves cancel and their energy components are re-distributed in the opposite direction. s11(a1) and s12(a2) never encounter an impedance discontinuity." 73, ac6xg |
Analyzing Stub Matching with Reflection Coefficients
Cecil Moore wrote: Jim, what happens to the ExB power density in the equal and opposite fields that cancel? Let's see E=0, and B=0; what power density, Cecil? 73, Jim AC6XG |
Analyzing Stub Matching with Reflection Coefficients
Cecil Moore wrote:
That is the nature of EM waves, Gene. EM waves flowing in opposite directions do NOT interact. However, their reflected and transmitted components traveling in the same direction can and do interact at an impedance discontinuity. Actually it's even more straightforward than that. They do interact with a physical impedance discontinuity, and don't interact with each other no matter which way they are traveling. 73, Jim AC6XG |
Analyzing Stub Matching with Reflection Coefficients
Richard Clark wrote:
On Thu, 19 Apr 2007 14:56:33 GMT, Gene Fuller wrote: Do you have any connection with "optical physicists" beyond your reading of Hecht and the Melles Griot website? Hi Gene, Aside from the number of us that have experience in the practice? 73's Richard Clark, KB7QHC Hi Richard, I have not seen an optical physicist since I looked in the mirror this morning. 8-) 73, Gene W4SZ |
Analyzing Stub Matching with Reflection Coefficients
Cecil Moore wrote:
Gene Fuller wrote: Help me out. How can we have scalars flowing in opposite directions? If the waves can interact, as you claim, why does the associated energy fail to interact and merely pass like ships in the night? That is the nature of EM waves, Gene. EM waves flowing in opposite directions do NOT interact. However, their reflected and transmitted components traveling in the same direction can and do interact at an impedance discontinuity. Cecil, Progress! All we need now is that you also understand that waves flowing in the SAME direction do NOT interact unless there is an interface or other discontinuity. All sorts of things can happen at discontinuities. The detailed physical mechanisms and the models are well understood. 73, Gene W4SZ |
Analyzing Stub Matching with Reflection Coefficients
On Apr 19, 12:27 pm, Cecil Moore wrote:
Richard Harrison wrote: How much energy will continue to enter the stub? Practically none because there is no difference of potential between the source and the reflection. In a lossless stub, zero energy will continue to enter the stub. In fact, in a lossless stub, the source can theoretically be completely disconnected and everything remains the same including 100% re-reflection of reflected waves by the new open circuit. I've always liked this example. By extension, on a line multiple quarter wavelengths long, you can disconnect the line at ANY of the voltage maxima and see exactly the same result as you describe above. Are those travelling waves really crossing the voltage maxima? Or are they being reflected? Or are they just reflected at the maxima that actually occur at a discontinuity? But there is no discontinuity at the source, so why would they be reflected there? But if they are reflected at the non-discontinuity at the source, then they should be reflected at the non-discontinuities in the line as well. But wait, those non-discontinuities are virtual opens and shorts, so maybe they reflect at virtual ones as well. But no, it has been agreed that reflections only happen at physical discontinuities. And what if the stub is not a quarter (or multiple) wavelength long? Then where does the reflection at the source occur? At the last maximum or minimum along the line? Inside the generator? It works for any length of line. Somehow the generator knows exactly what reactance to supply? It is definitely best to recognize that when the source impedance is equal to the line impedance, there is no reflection at the source. And it does not matter if the source impedance is achieved with a circulator, a resistor, a multiplicity of resistors, feedback, or what have you; there is no reflection if the impedance is the same as the line. No discontinuity, no reflection. A simple rule. Works at a load. Works at a generator. Works along the line. Always works. ....Keith |
Analyzing Stub Matching with Reflection Coefficients
Dr. Honeydew wrote:
Ah, I can see you didn't take me seriously. But I was dead serious. It is absolutely not necessary for the source to be dissipating the reverse wave it sucks up as heat. Can a wave exist without energy? Where does the energy in the sucked up wave go since it doesn't go into the source. In other words, viewed from both sides, show us even one instance where the system is not correctly analyzed with your S11--S12 equations for the Z1--Z2 interface. Show us even one instance where those equations will not tell you exactly what happens to waves coming into that interface from either direction, and in fact from both directions at once. You must have me confused with someone else. I'm a supporter of the s-parameter analysis. It's others who have called it "Gobbledegook" (sic). -- 73, Cecil, w5dxp.com |
Analyzing Stub Matching with Reflection Coefficients
Jim Kelley wrote:
Cecil Moore wrote: ... I have gone on record as saying that reflections only occur at physical impedance discontinuities. You have also gone on record as saying is this: 4/19/07 6:12 AM "The only thing s11(a1) and s12(a2) encounter are each other and that interaction completely changes those two waves. The two waves cancel and their energy components are re-distributed in the opposite direction. s11(a1) and s12(a2) never encounter an impedance discontinuity." There's no conflict between those two statements. s11(a1) and s12(a2) indeed *NEVER* encounter an impedance discontinuity since they originate already flowing *away from* the impedance discontinuity. Any interference between two coherent collinear EM waves traveling in the same path is a permanent interaction. -- 73, Cecil, w5dxp.com |
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