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Analyzing Stub Matching with Reflection Coefficients
Cecil Moore wrote:
Gene Fuller wrote: * Does your IEEE dictionary have an entry for "stationary"? I'm afraid you have been taken in by my devil's advocate argument based on Keith's faulty concepts. If what he says is true about standing waves, then the same concepts apply to traveling waves. If there are no traveling wave energy components being transferred when two traveling waves are flowing in opposite directions, then it logically follows that there can be no traveling wave energy component being transferred when one traveling wave is flowing in one direction. The *NET* energy flow is zero in a standing wave. But the component energy flow in the underlying EM waves is alive and well and flowing right through those current and voltage nodes without even knowing that they are there. The illusion of zero energy flow in EM traveling waves is one of the problems with shortcuts. EM waves have a set of boundary conditions that must be satisfied for them to exist. One of those conditions is that they must necessarily travel at c(VF). "Stationary" is not possible for any single EM wave. Nobody has been able to provide an example of a standing wave without the underlying forward and reverse EM traveling wave components (not even you) :-). Another condition for the existence of an EM traveling wave is that it has an associated energy level without which it cannot exist. A stationary EM wave is a contradiction in terms, an oxymoron. EM waves cannot stand still and exist only as a concept in the human mind. It is an illusionary temporarily superposed profile of two waves that, in reality, are moving in opposite directions at c(VF) and have absolutely *NO* effect on each other. The forward EM wave possesses direction and momentum that doesn't change until it encounters a physical impedance discontinuity. The reverse EM wave possesses direction and momentum that doesn't change until it encounters a physical impedance discontinuity. Anything else would violate the laws of physics. -- 73, Cecil, w5dxp.com Cecil, Nobody said the "wave" was stationary, only the point of zero energy is stationary. You have again demonstrated that you are not reading and understanding. The *NET* paragraph above is simply unmitigated nonsense. It appears that mistaken notion is one of the root causes of your continuing confusion. Until you get over this bogus idea of colliding energy flows there is no hope for further enlightenment. 73, Gene W4SZ |
Analyzing Stub Matching with Reflection Coefficients
Cecil Moore wrote:
Gene Fuller wrote: I did not say the graphic was incorrect, but rather that it is irrelevant. It correctly shows the addition of two sine waves. OK, if it is irrelevant, why did they publish it? Why do they talk about "redistribution" of energy in other directions during a destructive interference event? Doesn't changing the direction and momentum of a wave qualify as "interaction"? And when those two sine waves are coherent, of equal amplitude, and opposite phase, they permanently *CANCEL* each other. Doesn't that satisfy the definition of "interacting"? I see you have been strangely silent on my example of s11(a1) originating and flowing away from the impedance discontinuity only to be canceled by s12(a2) when it flows through the impedance discontinuity and encounters the s11(a1) wave flowing away from the impedance discontinuity. How can the effect of one wave on the other not be interaction when both are flowing away from the impedance discontinuity and are *NEVER* incident upon any impedance discontinuity? Cecil, I did respond to your example. I referred you to the message from K7ITM. The answer is contained in his quote. Since you seemed to have missed that one, here is the conclusion. The waves you are trying to create and then quickly cancel, in delta-t, simply never existed. Problem solved. 73, Gene W4SZ |
Analyzing Stub Matching with Reflection Coefficients
On Apr 23, 7:56 am, Cecil Moore wrote:
Gene Fuller wrote: * Does your IEEE dictionary have an entry for "stationary"? I'm afraid you have been taken in by my devil's advocate argument based on Keith's faulty concepts. If what he says is true about standing waves, then the same concepts apply to traveling waves. It becomes clear from your posts that you have a wave centric view of these behaviours. It is often valuable to have more than one way to view a situation. Let me offer you another. While I will describe this view only for transmission lines, its equivalent in free space would be the Maxwell equations, so, knowing your support for Maxwell, you should find it attractive. The voltages and currents on a transmission line can be described with a collection of differential equations. When these differential eqations are solved for a set of boundary conditions, the results describe the voltage and current on the line as a function of time and location along the line. Were one to set up an ideal line (for simplicity), terminated in its characteristic impedance, the functions that describe the voltage and current on the line can be derived. Plugging in the time and location one can determine the voltage at that place and instance. The curious investigator will be tempted to plot the voltage for a particular time as a function of location. The resulting plot will be nicely sinusoidal. Were one to plot the result for deltaT later, one finds a plot with exactly the same shape, but slightly shifted. A movie would show this nice sinusoid shifting its location at a constant velocity. And our intrepid investigator names this a travelling wave, a convenient moniker. Let us consider another line. This one is open circuited. Solving the diffential equations that describe the line for these new boundary conditions produces a different set of functions of time and location. Plotting the function of voltage with respect to location again produces a sinusoid, but the amplitude depends on the selected time. This plot, when played as a movie, shows no sign of moving and our intrepid investigator names it a standing wave, another convenient moniker. But just because they are both called waves does not make them the same. One always has the same shape and amplitude and appears to move. The other shares the shape, does not move and has an amplitude that varies. Fundamentally, they are both just convenient visualizations of solutions from the same set of differential equations with different boundary conditions. For the standing wave, further arithmetic reveals that the function that expresses the voltage as a function of time and location can be simplified and made more useful if it is expressed in terms of two travelling waves, one from the left and one from the right. But this is just an alternate expression of the function that resulted from the solution of a set of differential equations. While the initial differential equations express voltage and current, one could certainly derive equations that expressed power, or energy storage, or whatever happened to be of interest. One could then solve these and the expression that results would be a function of time and location. Were one to solve the differential equation for power on the open circuited line at a location of a voltage null, the answer would be zero. And all computed without the need for forward and backward waves. --- So which is the truth? The differential equations or the forward and backward waves? Which analysis technique is more complete? And which is the alternative view that makes the problems solvable in reasonable time? It is clear to me that the differential equations rule, much as Maxwell's equations are considered the root for electric and magnetic fields. Travelling and standing waves are mere visualizations, though that visualization simplifies solving many problems. But forward and reverse waves are definitely not the foundation on which all else rests. ....Keith |
Analyzing Stub Matching with Reflection Coefficients
On Apr 23, 8:54 am, Gene Fuller wrote:
Cecil Moore wrote: Gene Fuller wrote: * Does your IEEE dictionary have an entry for "stationary"? I'm afraid you have been taken in by my devil's advocate argument based on Keith's faulty concepts. If what he says is true about standing waves, then the same concepts apply to traveling waves. If there are no traveling wave energy components being transferred when two traveling waves are flowing in opposite directions, then it logically follows that there can be no traveling wave energy component being transferred when one traveling wave is flowing in one direction. The *NET* energy flow is zero in a standing wave. But the component energy flow in the underlying EM waves is alive and well and flowing right through those current and voltage nodes without even knowing that they are there. The illusion of zero energy flow in EM traveling waves is one of the problems with shortcuts. EM waves have a set of boundary conditions that must be satisfied for them to exist. One of those conditions is that they must necessarily travel at c(VF). "Stationary" is not possible for any single EM wave. Nobody has been able to provide an example of a standing wave without the underlying forward and reverse EM traveling wave components (not even you) :-). Another condition for the existence of an EM traveling wave is that it has an associated energy level without which it cannot exist. A stationary EM wave is a contradiction in terms, an oxymoron. EM waves cannot stand still and exist only as a concept in the human mind. It is an illusionary temporarily superposed profile of two waves that, in reality, are moving in opposite directions at c(VF) and have absolutely *NO* effect on each other. The forward EM wave possesses direction and momentum that doesn't change until it encounters a physical impedance discontinuity. The reverse EM wave possesses direction and momentum that doesn't change until it encounters a physical impedance discontinuity. Anything else would violate the laws of physics. -- 73, Cecil, w5dxp.com Cecil, Nobody said the "wave" was stationary, only the point of zero energy is stationary. You have again demonstrated that you are not reading and understanding. I think he may be too busy having that strange kind of dream he talked about when he implicitly threw out at least 90% of all S-parameter analysis by saying that "reality requires complete reflection of the return wave at the interface between the [matched] source and the line." Either you believe in the superposition principle in linear systems, or you don't. He obviously doesn't. From the lab, Bunsen |
Analyzing Stub Matching with Reflection Coefficients
Gene Fuller wrote:
The *NET* paragraph above is simply unmitigated nonsense. It appears that mistaken notion is one of the root causes of your continuing confusion. Until you get over this bogus idea of colliding energy flows there is no hope for further enlightenment. If colliding energy doesn't flow, then waves interact away from an impedance discontinuity since the colliding energy components are in separate EM waves traveling in opposite directions. Which will it be? You cannot have it both ways. 1. The ExB joules/sec components in the forward wave and the reflected wave pass through each other with no interaction such that the *NET* energy flow is zero. 2. The ExB joules/sec components flowing in each direction cause all energy to stop flowing because of wave interaction. Please tell us which one is true and which one is false. -- 73, Cecil, http://www.qsl.net/w5dxp |
Analyzing Stub Matching with Reflection Coefficients
Gene Fuller wrote:
The waves you are trying to create and then quickly cancel, in delta-t, simply never existed. Problem solved. Problem solved by rendering an s-parameter analysis invalid? b1 = s11(a1) + s12(a2) = 0 So s11(a1) and s12(a2) in the s-parameter equations don't exist and never existed. Don't you think you should tell HP so they can change their Ap Notes? -- 73, Cecil, http://www.qsl.net/w5dxp |
Analyzing Stub Matching with Reflection Coefficients
Keith Dysart wrote:
Were one to solve the differential equation for power on the open circuited line at a location of a voltage null, the answer would be zero. And all computed without the need for forward and backward waves. The *NET* power at any point on a lossless stub is zero so that is no big deal. The standing wave current is always 90 degrees out of phase with the standing wave current so cos(90) = 0. At a voltage node, all of the energy has simply moved into the magnetic field. Calculate the number of electromagnetic joules in the line and get back to us on how they are reflected from your above purely virtual impedance at a voltage "null" and how they can even exist without a velocity of c(VF). -- 73, Cecil, http://www.qsl.net/w5dxp |
Analyzing Stub Matching with Reflection Coefficients
Dr. Honeydew wrote:
Either you believe in the superposition principle in linear systems, or you don't. He obviously doesn't. Superposition is known to fail in nonlinear systems. A source is obviously not linear. The V/I of an active dynamic source resists any attempt at linear superposition. How does your superposition work when you try to spit up a fire hose? -- 73, Cecil, http://www.qsl.net/w5dxp |
Analyzing Stub Matching with Reflection Coefficients
Cecil Moore wrote:
The *NET* power at any point on a lossless stub is zero so that is no big deal. The standing wave current is always 90 degrees out of phase with the standing wave current so cos(90) = 0. At a voltage node, all of the energy has simply moved into the magnetic field. With 4 amps of RF current at that voltage "null", how could zero joules/sec possibly exist at that point? Methinks there are some I^2*Z0 joules/sec in that 4 amps of RF EM current that necessarily must be traveling at c(VF). -- 73, Cecil, http://www.qsl.net/w5dxp |
Analyzing Stub Matching with Reflection Coefficients
Cecil Moore wrote:
Dr. Honeydew wrote: Either you believe in the superposition principle in linear systems, or you don't. He obviously doesn't. Superposition is known to fail in nonlinear systems. A source is obviously not linear. Sources are linear. Consider the classic voltage source.. it has zero impedance. You can stack as many voltage sources as you like, and the voltage at the top of the stack is the same as the sum of the individual voltages. The V/I of an active dynamic source resists any attempt at linear superposition. - a practical RF source, perhaps, might be nonlinear, although it's pretty easy to come close.. Consider an oscillator isolated by an isolator or a big pad. How does your superposition work when you try to spit up a fire hose? Just fine. No different than receiving a faint signal superimposed on a large interfering signal at a different frequency. |
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