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#431
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Rotational speed
Roy Lewallen wrote in
: A phasor is a replacement of cos(omega * t + phi) with cos(omega * t + phi) + j * sin(omega * t + phi) = exp(j * (omega * t + phi)) = exp(j * omega * t) * exp(j * phi). The first of those quantities is understood but not generally written in phasor analysis, but is nonetheless an essential part of the definition of a phasor. This shows that a phasor is a vector which rotates in the complex plane, with a rotational speed of omega * t radians/sec. The reason the time-dependent rotational term Should that be ...of omega radians/sec..., omega*t is the phase displacement, omega is the phase velocity? Owen |
#432
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Rotational speed
K7ITM wrote:
OK, noted, but your definition doesn't match what I was taught and what is in the Wikipedia definition at http://en.wikipedia.org/wiki/Phasor_(electronics). What I was taught, and what I see at that URL, is that the PHASOR is ONLY the representation of phase and amplitude--that is, ONLY the A*exp(j*phi). To me, what you guys are calling a phasor is just a rotating vector describing the whole signal. To me, the value of using a phasor representation is that it takes time out of the picture. See also http://people.clarkson.edu/~svoboda/.../Phasor10.html, which defines the phasor very clearly as NOT being a function of time (assuming things are in steady-state). But in my online search, I also find other sites that, although they don't bother to actually define the phasor, show it as a rotating vector. Grrrr. I'll try to remember to check the couple of books I have that would talk about phasors to see if I'm misrepresenting them, but I'm pretty sure they are equally explicit in defining a phasor as a representation of ONLY the phase and magnitude of the sinusoidal signal, and NOT as a vector that rotates synchronously with the sinewave. Tom, I'm sure a lot of people forget the derivation of a phasor after using it for a while, just as they do so many other things. Again, a phasor is a complex representation of a real sinusoidal function and, as such, definitely has a time varying component. That the component isn't written doesn't mean it's not there. By all means, check your texts. I'm sure that any decent circuit analysis text has a serviceable development of the subject. I always cringe when I see wikipedia quoted as a reference -- I was referred to an entry regarding transmission lines some time ago, and it contained some pretty major misconceptions. That leads me to mistrust it when looking up a topic which I don't have a good grasp of. I don't have a full understanding of the process by which it's written, but it seems that all participants in this newsgroup are equally qualified to create or modify a wikipedia entry. How could that result in a reliable reference? Roy Lewallen, W7EL |
#433
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Rotational speed
Owen Duffy wrote:
Roy Lewallen wrote in : A phasor is a replacement of cos(omega * t + phi) with cos(omega * t + phi) + j * sin(omega * t + phi) = exp(j * (omega * t + phi)) = exp(j * omega * t) * exp(j * phi). The first of those quantities is understood but not generally written in phasor analysis, but is nonetheless an essential part of the definition of a phasor. This shows that a phasor is a vector which rotates in the complex plane, with a rotational speed of omega * t radians/sec. The reason the time-dependent rotational term Should that be ...of omega radians/sec..., omega*t is the phase displacement, omega is the phase velocity? You're right. Thank you for the correction. My apology for the error. Roy Lewallen, W7EL |
#434
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Rotational speed
K7ITM wrote:
I expect the same to be true on a resonant antenna; the reflected wave is NOT the same amplitude as the forward, but is similar, so you'll find places where the phase change is quick but continuous as you move along the wire--this assumes that the antenna is long enough that you can find such places. On a 1/2WL standing wave antenna, the reflected current is within about 10% of the forward current. I think you will find that under those conditions, the phase change is NOT continuous. The total antenna current reported by EZNEC is the sum of the forward current and reflected current all up and down a 1/2WL dipole. With the feedpoint as the 0 deg reference, EZNEC reports only ~3 degree change between the feedpoint and the end segment of the dipole. The phase change is NOT quick and never exceeds ~3 degrees. A typical forward current at the feedpoint might be 1A @ 0 deg while the reflected current might be 0.9A @ 0 deg. That phase angle is obviously zero. 45 degrees out from the feedpoint, the forward current might be 0.975A @ -45 deg. The reflected current might be 0.925A @ 45 deg. Adding those two phasors gives a phase angle very close to zero. The phase angle does NOT change quickly - it changes hardly at all. Kraus agrees. On page 464 of "Antennas for all Applications", 3rd edition, Figure 14-2, he graphs the amplitude and phase of the current in a 1/2WL dipole. The current phase never exceeds ~3 degrees over the entire length of the dipole. The phase change is NOT quick. It is exceedingly slow. This has to do with how the forward current phasor and the reflected current phasor adding together to obtain a *constant* zero degrees of phase in a thin-wire dipole. Kraus shows both a thin-wire dipole and a dipole where the length to diameter ratio is 75. The length to diameter ratio of a 75m dipole is in the many thousands, closer to a thin wire than to 75. -- 73, Cecil http://www.w5dxp.com |
#435
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Analyzing Stub Matching with Reflection Coefficients
Gene Fuller wrote:
In the context of antenna and transmission line matters you have an interesting definition of "source" for an amateur transmitter. Why consider the source to be some place after the output conditioning, such as the output connector, when you can go all the way back to the wall plug? The RF source is obviously the point where DC is converted to RF. That's the point under discussion. -- 73, Cecil http://www.w5dxp.com |
#436
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Rotational speed
On Apr 27, 7:36 pm, K7ITM wrote:
Grrrr. I'll try to remember to check the couple of books I have that would talk about phasors to see if I'm misrepresenting them, but I'm pretty sure they are equally explicit in defining a phasor as a representation of ONLY the phase and magnitude of the sinusoidal signal, and NOT as a vector that rotates synchronously with the sinewave. My recollection is of being introduced to phasors with the study of electric machines which have real rotating magnetic fields. By jumping onto the rotor and rotating with those magnetic fields, solutions became trivial by allowing vector arithmetic on the now stationary phasors. ....Keith |
#437
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Rotational speed
Roy Lewallen wrote:
Cecil regularly confuses the change in phase angle of the phasor with position, with the rotation of the phasor with time. Everyone is wrong except you, huh? The fact still remains that your following assertion was wrong: Roy said: "This is the total current. It has magnitude and phase like any other phasor, and the same rotational speed as its components." Total current on a standing-wave antenna does NOT have the same rotational speed as its components. It hardly rotates at all up and down the entire 1/2WL dipole. EZNEC and Kraus agree with me on that fact. All you have to do is fire up EZNEC and prove it to yourself. That means that your and Tom's phase measurements through a loading coil were invalid. One cannot use a current with unchanging phase to measure a phase shift. -- 73, Cecil http://www.w5dxp.com |
#438
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Rotational speed
K7ITM wrote:
I'll try to remember to check the couple of books I have that would talk about phasors to see if I'm misrepresenting them, but I'm pretty sure they are equally explicit in defining a phasor as a representation of ONLY the phase and magnitude of the sinusoidal signal, and NOT as a vector that rotates synchronously with the sinewave. This brings up a point that I need to clarify. All my phasors are referenced to a phase angle of zero at the feedpoint. Take a snapshot when the feedpoint phasor is at zero degrees and then look at all the other phasors up and down the antenna. I hope that clears up any confusion I may have generated by not explaining my reference point earlier. -- 73, Cecil http://www.w5dxp.com |
#439
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Rotational speed
Keith Dysart wrote:
My recollection is of being introduced to phasors with the study of electric machines which have real rotating magnetic fields. By jumping onto the rotor and rotating with those magnetic fields, solutions became trivial by allowing vector arithmetic on the now stationary phasors. A most excellent description! Thanks for sharing it. Now if we could just get a certain individual to either stay on the rotor or the stator and not keep jumping back and forth without telling anyone or even realizing it himself. . . Roy Lewallen, W7EL |
#440
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Rotational speed
Cecil Moore wrote:
Total current on a standing-wave antenna does NOT have the same rotational speed as its components. It hardly rotates at all up and down the entire 1/2WL dipole. This is, of course, referenced to the feedpoint signal at zero degrees. The phase of a traveling wave changes 45 degrees in 45 degrees of wire. The phase of the standing wave changes no more than a couple of degrees in 45 degrees of wire. Sorry for any confusion that might have occurred because I neglected to explain my reference phasor. -- 73, Cecil http://www.w5dxp.com |
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