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#441
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Rotational speed
Roy Lewallen wrote:
Now if we could just get a certain individual to either stay on the rotor or the stator and not keep jumping back and forth without telling anyone or even realizing it himself. . . I apologize for any confusion I may have created. All of my phasors are referenced to the feedpoint current at zero degrees, which is what EZNEC does. If the feedpoint forward current is at zero degrees, the forward current 45 degrees away will lag by 45 deg. The reflected current 45 degrees away will lead by 45 deg. The forward current 90 degrees away will lag by 90 deg. The reflected current 90 degrees away will lead by 90 deg. Thus the forward current and reflected current phasors are rotating compared to the feedpoint reference. The standing wave current phase, referenced to the feedpoint phase, changes hardly at all. The standing wave current phase is essentially the same all up and down the dipole. The standing wave current phase is essentially the same at the bottom and top of a loading coil. The standing wave current phase is essentially unrelated to the position on the antenna or loading coil. Standing wave current cannot be used to determine the phase shift through a loading coil. -- 73, Cecil http://www.w5dxp.com |
#442
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Rotational speed
Roy Lewallen wrote in
: with a rotational speed of omega * t radians/sec. The reason the time-dependent rotational term Should that be ...of omega radians/sec..., omega*t is the phase displacement, omega is the phase velocity? You're right. Thank you for the correction. My apology for the error. And to correct myself, I really should have said angular displacement and angular velocity respectively. Owen |
#443
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Analyzing Stub Matching with Reflection Coefficients
Cecil Moore wrote:
Gene Fuller wrote: I heard a rumor that the FCC does not like people to inject class-C type pulses directly into an antenna from the output of an amateur transmitter. Perhaps that rumor is just an urban legend, however, and non-linear outputs are welcome. The subject is modeling a class-C source, Gene, not filtering a class-C source. We all know how to filter a class-C source. Do you have a model for a class-C source? Well, we used to have one waaay back in Non-linear Transistor Design. Done with harmonics and relatively simple math as I remember. Gave remarkably accurate answers only using the fundamental plus 2 or 3 of them. The course was mostly about tank circuits, doublers, triplers, PLLs, etc. though, since the non-linear stuff was so easy once learned. Of course it wasn't really a model of a class-C source, since it actually did anything you could think of. So I guess it wouldn't qualify. Sorry I mentioned the concept. tom K0TAR |
#444
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Rotational speed
Keith Dysart wrote in news:1177719266.182305.327520
@l77g2000hsb.googlegroups.com: On Apr 27, 7:36 pm, K7ITM wrote: Grrrr. I'll try to remember to check the couple of books I have that would talk about phasors to see if I'm misrepresenting them, but I'm pretty sure they are equally explicit in defining a phasor as a representation of ONLY the phase and magnitude of the sinusoidal signal, and NOT as a vector that rotates synchronously with the sinewave. My recollection is of being introduced to phasors with the study of electric machines which have real rotating magnetic fields. By jumping onto the rotor and rotating with those magnetic fields, solutions became trivial by allowing vector arithmetic on the now stationary phasors. Isn't hopping onto the rotor (assuming synchronous speed) to make your observations called moving from the time domain to the frequency domain, and all the mathematical shortcuts are only valid if all quantities share the same angular velocity (or frequency), implying sinusoidal waveform. I guess a departure from the strict phasor environment is for example when we consider a noise vector rotating about the end of a carrier phasor in exploring FM detector S/N vs C/N. Owen |
#445
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Analyzing Stub Matching with Reflection Coefficients
Tom Ring wrote:
Well, we used to have one waaay back in Non-linear Transistor Design. Yes, I remember one from college but would have trouble locating it 50 years later. :-) -- 73, Cecil http://www.w5dxp.com |
#446
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Rotational speed
Owen Duffy wrote:
Isn't hopping onto the rotor (assuming synchronous speed) to make your observations called moving from the time domain to the frequency domain, and all the mathematical shortcuts are only valid if all quantities share the same angular velocity (or frequency), implying sinusoidal waveform. Ever wonder which direction, clockwise or counter-clockwise, a standing-wave phasor is rotating? -- 73, Cecil http://www.w5dxp.com |
#447
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Rotational speed
On Apr 27, 4:01 pm, Roy Lewallen wrote:
K7ITM wrote: OK, noted, but your definition doesn't match what I was taught and what is in the Wikipedia definition athttp://en.wikipedia.org/wiki/Phasor_(electronics). What I was taught, and what I see at that URL, is that the PHASOR is ONLY the representation of phase and amplitude--that is, ONLY the A*exp(j*phi). To me, what you guys are calling a phasor is just a rotating vector describing the whole signal. To me, the value of using a phasor representation is that it takes time out of the picture. See alsohttp://people.clarkson.edu/~svoboda/eta/phasors/Phasor10.html, which defines the phasor very clearly as NOT being a function of time (assuming things are in steady-state). But in my online search, I also find other sites that, although they don't bother to actually define the phasor, show it as a rotating vector. Grrrr. I'll try to remember to check the couple of books I have that would talk about phasors to see if I'm misrepresenting them, but I'm pretty sure they are equally explicit in defining a phasor as a representation of ONLY the phase and magnitude of the sinusoidal signal, and NOT as a vector that rotates synchronously with the sinewave. Tom, I'm sure a lot of people forget the derivation of a phasor after using it for a while, just as they do so many other things. Again, a phasor is a complex representation of a real sinusoidal function and, as such, definitely has a time varying component. That the component isn't written doesn't mean it's not there. By all means, check your texts. I'm sure that any decent circuit analysis text has a serviceable development of the subject. I always cringe when I see wikipedia quoted as a reference -- I was referred to an entry regarding transmission lines some time ago, and it contained some pretty major misconceptions. That leads me to mistrust it when looking up a topic which I don't have a good grasp of. I don't have a full understanding of the process by which it's written, but it seems that all participants in this newsgroup are equally qualified to create or modify a wikipedia entry. How could that result in a reliable reference? Roy Lewallen, W7EL Hi Roy, Well, I did not forget the derivation. In Balabanian, "Fundamentals of Circuit Theory," (a book I have but didn't actually study from) he uses "sinor" instead of "phasor" but says they are the same, then in a convoluted way gets around to saying that it's just the phase and magnitude, and not the real(exp(jwt)) part. Smith, "Circuits, Devices, and Systems," (most likely the book from which I learned about phasors) is much clearer about it. Under "Phasor Representation" in my edition, "If an instantaneous voltage is described by a sinusoidal function of time such as v(t) = V cos (wt + theta) then v(t) can be interpreted as the "real part of" a complex function or v(t) = Re {V exp[j*(wt + theta)]} = Re {[V*exp(j*theta)]*[exp(j*wt)]} (eqn 3-18) In the second form of eqn 3-18, the complex function in braces is separated into two parts; the first is a complex constant, the second is a function of tiem which implies rotation in the complex plane. The FIRST PART we DEFINE [Tom's emphasis...] as the phasor (bold) V (/ bold), where (bold) V (/bold) = V*exp(j*theta) .... The phasor V is called a "transform" of the voltage v(t); it is obtained by transforming a function fo time into a complex constant which retains the essential information. ... " OK, so your definition is different from mine. So far, I've found two actual definitions of the phasor on-line, and both agree with my books and my own useage. But if it's common useage to consider a phasor to be a rotating vector, I'll defer to that at least in this discussion. So far, though, I haven't found a reason to give up my definition of a phasor. ;-) Cheers, Tom |
#448
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Rotational speed
Owen Duffy wrote:
Isn't hopping onto the rotor (assuming synchronous speed) to make your observations called moving from the time domain to the frequency domain, and all the mathematical shortcuts are only valid if all quantities share the same angular velocity (or frequency), implying sinusoidal waveform. I guess a departure from the strict phasor environment is for example when we consider a noise vector rotating about the end of a carrier phasor in exploring FM detector S/N vs C/N. That's why it's essential to not forget the implied exp(j * omega * t) term -- all waveforms in an analysis must include it, and it must be the same omega for all. In addition to inherently non-sinusoidal waveforms, waveforms resulting from any nonlinear operation, such as frequency modulation or multiplying or squaring waveforms, can't be analyzed in that environment. Roy Lewallen, W7EL |
#449
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Rotational speed
K7ITM wrote:
OK, so your definition is different from mine. So far, I've found two actual definitions of the phasor on-line, and both agree with my books and my own useage. But if it's common useage to consider a phasor to be a rotating vector, I'll defer to that at least in this discussion. So far, though, I haven't found a reason to give up my definition of a phasor. ;-) Cheers, Tom I find it's convenient to think of a phasor as rotating with respect to some other frequency, or stationary when you want to show the phase relation at some specific frequency in a circuit with complex impedances. For example, if you are discussing the phase relations in AM modulation, you can set the carrier as a vector pointing to the right, and the upper and lower sidebands rotating in opposite directions with their centers on the end of the carrier vector. The sidebands each have one half the amplitude of the carrier, so when they are aligned in the same direction as the carrier, the resulting vector is twice the amplitude, or length. When they oppose the carrier, the result is zero amplitude. So a phasor can be stationary or rotating depending on its relation to something else in the discussion. Regards, Mike Monett |
#450
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Rotational speed
On Apr 27, 9:15 pm, Owen Duffy wrote:
Keith Dysart wrote in news:1177719266.182305.327520 @l77g2000hsb.googlegroups.com: My recollection is of being introduced to phasors with the study of electric machines which have real rotating magnetic fields. By jumping onto the rotor and rotating with those magnetic fields, solutions became trivial by allowing vector arithmetic on the now stationary phasors. Isn't hopping onto the rotor (assuming synchronous speed) to make your observations called moving from the time domain to the frequency domain, I am not sure it is that; more like rotating the frame of reference to stabilize the view (or a stroboscope perhaps?). The time domain is now captured in the notation on the diagram that says it is all happening at 60 Hz, for example. and all the mathematical shortcuts are only valid if all quantities share the same angular velocity (or frequency), implying sinusoidal waveform. But I agree with this. If everything is not rotating with the same velocity (and not just frequency), then it is difficult to find a useful frame of reference to rotate. Which suggests that if there are two directions of rotation, phasors don't help much with the solution. I guess a departure from the strict phasor environment is for example when we consider a noise vector rotating about the end of a carrier phasor in exploring FM detector S/N vs C/N. ....Keith |
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