Richard Harrison wrote:
How much energy will re-enter the source? Practically none because there
is no difference of potential between the reflection and the source.

Yes, the reflected wave from 50 ohm coax trying to enter Keith's
50 ohm transmitter will be 100% re-reflected in a lossless stub
in complete violation of his assertions which proves that the
reflected wave doesn't see the source impedance and instead sees
the source load-line impedance.

How much energy will continue to enter the stub? Practically none
because there is no difference of potential between the source and the
reflection.

In a lossless stub, zero energy will continue to enter the stub.
In fact, in a lossless stub, the source can theoretically be
completely disconnected and everything remains the same
including 100% re-reflection of reflected waves by the new
open circuit.

Of course, if the stub is real, the losses will take everything
to zero if the stub is disconnected because the source is
supplying the small amount of power lost to dissipation in
a real-world stub which doesn't have an infinite impedance.
--
73, Cecil, w5dxp.com