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Gene Fuller wrote:
All we need now is that you also understand that waves flowing in the SAME direction do NOT interact unless there is an interface or other discontinuity. Please stop implying things that I have never said. When I asserted that reflections only happen at a physical impedance discontinuity, that implies that interaction can only happen at a physical impedance discontinuity. It is impossible to get two coherent waves flowing in the same direction except at a physical impedance discontinuity. Assume b1 = s11(a1) + a12(s2) = 0 What I have said is that s11(a1) and s12(a2) are wave components that cancel without ever being incident upon an impedance discontinuity. Those two wave components originate at the impedance discontinuity flowing *AWAY FROM* the impedance discontinuity. They are canceled in a delta-t, i.e. a very short time. Those two waves are the result of interaction at the impedance discontinuity but neither of them ever interacted with the impedance discontinuity because they originated at the impedance discontinuity. -- 73, Cecil, w5dxp.com |
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