"Cecil Moore" wrote in message
et...
Jim Kelley wrote:
Joules per second doesn't have phase, Cecil. Your claim was the value was
1 joule/sec. And the equation is stated pretty clearly in AN-95-1 as the
sum of the terms. It doesn't have a minus sign, and it there isn't a
cosine term in it. a1 and a2 are complex voltages, and their relative
phase take care of itself - unless of course you square the equation.
That's how you end up with nonsense like 0=4.

As you know, I have repeated all this to you before so
you cannot possibly still be confused. Why you continue
your obfuscation of the truth is really strange.

b1 = s11(a1@0deg) + s12(a2@180deg) = 0

1. When we square both sides of the equation, the
product of 2*s11(a1@0deg)*s12(a2@180deg) is at 180
degrees so the sign of the term is negative. (but you
already knew that)

2. Joules per second doesn't have phase. I have said that
over and over. The phase term in the power density
equation is the relative phase between the two associated
voltages. (but you already knew that)

3. The equation stated in AN-95-1 is a normalized voltage
equation which is the sum of phasors - no negative sign
required for phasor addition. (but you already knew that)

4. Phasor symbols don't have minus signs and the real value
of a phasor is understood to include a cosine term even
though it is omitted by convention. (but you already knew that)

5. The general case of the squared equation is the same
as the intensity (power density) equations from Hecht
and Born & Wolf. It doesn't contain a minus sign.

Ptot = P1 + P2 + 2*SQRT(P1*P2)cos(A)

A is the angle between the two associated normalized
phasor voltages, a1 and a2, and its cosine is sometimes
negative. (but you already knew that)

I did not end up with nonsense like 0=4. You ended up
with nonsense like 0=4 by engaging in deliberate
irrational obfuscation. Why you feel the need to
act that way is really strange.
--
73, Cecil http://www.w5dxp.com

Isnt it true the Cos of the phase term will always be equal to -1 or plus
1, -1 for any value of SWR except 1:1 and 1 for a 1:1 SWR value.
I hope this dosnt seem stupid tommorow as I am somewhat sedated and it is
late.

Jimmie

Jimmie D wrote:
Isnt it true the Cos of the phase term will always be equal to -1 or plus
1, -1 for any value of SWR except 1:1 and 1 for a 1:1 SWR value.

The context of the present discussion is a Z0-match point
at which reflections toward the source are eliminated.
For the case of a Z0-match, the cosine of the phase term
will indeed always be +1 or -1 as the fields are either
in phase or 180 degrees out of phase.

If the SWR is 1:1, there is no reflected voltage and
therefore a2 = 0 and there is no assignable phase angle
between the voltages.

In the general case, where reflections are allowed to
reach the source, the cosine value can be anything
between +1 and -1 as the angle between a1 and a2 can
have any value between zero degrees and 360 degrees.
--
73, Cecil http://www.w5dxp.com