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#1
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Gene Fuller wrote:
Why do you seem to believe that bringing photons into the discussion adds any light? (pun intended) Does the word "photon" sound more hifalutin than "wave"? Using "photons" instead of "EM waves" makes things a little more obvious. While "standing EM waves" may imply EM waves that are standing still, "standing photons" are obviously impossible. Photons cannot stand still. EM waves cannot stand still for the same reason. A "standing EM wave" is a human abstraction that doesn't really exist in reality. The only people with something to gain by objecting to the use of "EM waves" and "photons" interchangeably are the people trying to hoodwink the uninitiated into believing that photons can stand still. :-) -- 73, Cecil, w5dxp.com |
#2
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Cecil Moore wrote:
Gene Fuller wrote: Why do you seem to believe that bringing photons into the discussion adds any light? (pun intended) Does the word "photon" sound more hifalutin than "wave"? Using "photons" instead of "EM waves" makes things a little more obvious. While "standing EM waves" may imply EM waves that are standing still, "standing photons" are obviously impossible. Photons cannot stand still. EM waves cannot stand still for the same reason. A "standing EM wave" is a human abstraction that doesn't really exist in reality. The only people with something to gain by objecting to the use of "EM waves" and "photons" interchangeably are the people trying to hoodwink the uninitiated into believing that photons can stand still. :-) -- 73, Cecil, w5dxp.com Cecil, There seems to be a pretty fundamental disconnect here. Waves don't create radiation; photons don't create radiation; accelerating charges do create radiation. You seem to be placing some sort of restriction on the motion of those charges. They can move or stand still as they please. Some folks around here appear to think that standing waves are totally inert, and therefore totally useless or even fictitious. There are most definitely accelerating charges in a standing wave, and that accelerated charge generates the desired radiation. Call it "sloshing" if you wish, but it still works. What difference does it make if the wave on the antenna and the radiated wave in space can be defined as photons? Answer: None whatsoever, and there is not even any insight gained into the radiation mechanism at HF. In case there is any doubt, let me say it again; Adding photons into the discussion of HF radiation adds absolutely nothing but confusion. 73, Gene W4SZ |
#3
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On Thu, 10 May 2007 16:34:32 GMT, Gene Fuller
wrote: Adding photons into the discussion of HF radiation adds absolutely nothing but confusion. Hi Gene, I seriously doubt that, the confusion is already super-saturated. Perhaps you meant it might add more precipitate. 73's Richard Clark, KB7QHC |
#4
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Gene Fuller wrote:
There seems to be a pretty fundamental disconnect here. Waves don't create radiation; photons don't create radiation; accelerating charges do create radiation. Who cares? Photons can form standing waves in free space. Where are your accelerating charges in a vacuum? Everything that happens to EM waves in a wire, or a waveguide, also happen to EM waves in free space. You want to talk about the ocean and ignore the Tsunami. What difference does it make if the wave on the antenna and the radiated wave in space can be defined as photons? Answer: None whatsoever, ... That's your agenda and you're sticking to it. Like I said, some people apparently enjoy hoodwinking the uninitiated. What else do you have to gain by ignoring the photonic nature of EM waves? Accelerating charges do not morph into EM waves. Accelerating charges release photons that are the wave. Ignoring the photonic nature of EM waves is the cause of the present mass confusion about standing waves. Why on earth would you want that mass confusion to continue? -- 73, Cecil, w5dxp.com |
#5
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Cecil Moore wrote:
Gene Fuller wrote: There seems to be a pretty fundamental disconnect here. Waves don't create radiation; photons don't create radiation; accelerating charges do create radiation. Who cares? Photons can form standing waves in free space. Where are your accelerating charges in a vacuum? Everything that happens to EM waves in a wire, or a waveguide, also happen to EM waves in free space. You want to talk about the ocean and ignore the Tsunami. What difference does it make if the wave on the antenna and the radiated wave in space can be defined as photons? Answer: None whatsoever, ... That's your agenda and you're sticking to it. Like I said, some people apparently enjoy hoodwinking the uninitiated. What else do you have to gain by ignoring the photonic nature of EM waves? Accelerating charges do not morph into EM waves. Accelerating charges release photons that are the wave. Ignoring the photonic nature of EM waves is the cause of the present mass confusion about standing waves. Why on earth would you want that mass confusion to continue? -- 73, Cecil, w5dxp.com Cecil, So sorry. I thought that your 75m Bugcatcher Coil was a real, metallic object. If it is really nothing but free space, then I will agree with your assertions. The waves on your free space coil therefore have no connection to charges on a wire. I also forgot that all standing waves are identical, whether in free space or on a wire. I particularly love the wording you used, "Accelerating charges do not morph into EM waves. Accelerating charges release photons that are the wave." Did you ever hear of wave-particle duality? Did you ever read a serious treatment of radiation from antennas. Did you find lots of references to photon release, say, in Kraus or Balanis? Reversing the question you posed above, what do you gain by including the photonic nature of EM waves? I will try harder to follow the change of topic in the future. 8-) 73, Gene W4SZ |
#6
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Gene Fuller wrote:
"Waves don`t cause radiation." Waves induce current into an antenna. Any mismatched antenna reradiates most of the energy induced into it. A perfectly matched antnna only reradiates 50% of the energy it receives. Best regards, Richard Harrison, KB5WZI |
#7
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On 10 May, 13:38, (Richard Harrison) wrote:
Gene Fuller wrote: "Waves don`t cause radiation." Waves induce current into an antenna. Any mismatched antenna reradiates most of the energy induced into it. A perfectly matched antnna only reradiates 50% of the energy it receives. Best regards, Richard Harrison, KB5WZI Richard, Some time ago I stated that a yagi antenna operated under a mathematical binomial function. This was termed as junk science in this group which raises the question again as where does the energy that is not reradiated go ? " A perfectly matched antenna only reradiates 50 % of the energy that it receives" This also suggests that an array without parasitics required for reradiation is a lot more efficient than an antenna with parasitics. Seems like this group is going around in circles unless this 50% finds a way to radiate in some alternative way ! Is the 'perfectly matched' statement of any importance that demands it's inclusion with respect to re-radiation efficiency of an antenna? Regards Art |
#8
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On 10 May 2007 14:13:15 -0700, art wrote:
where does the energy that is not reradiated go ? Hi Art, Into the load. 73's Richard Clark, KB7QHC |
#9
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Richard Harrison wrote:
Gene Fuller wrote: "Waves don`t cause radiation." Waves induce current into an antenna. Any mismatched antenna reradiates most of the energy induced into it. A perfectly matched antnna only reradiates 50% of the energy it receives. Best regards, Richard Harrison, KB5WZI Richard, That is a well-known factoid. Do you think it differs from something I said? You note that current is involved in the reradiation. 73, Gene W4SZ |
#10
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Gene Fuller wrote:
Richard Harrison wrote: Gene Fuller wrote: "Waves don`t cause radiation." Waves induce current into an antenna. Any mismatched antenna reradiates most of the energy induced into it. A perfectly matched antnna only reradiates 50% of the energy it receives. That is a well-known factoid. Do you think it differs from something I said? You note that current is involved in the reradiation. Hint: If waves cause currents that in turn, cause re-radiation, then Richard has proved your, "waves don't cause radiation", assertion to be false. -- 73, Cecil http://www.w5dxp.com |
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