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Jim Higgins wrote: On Tue, 05 Jun 2007 15:16:34 -0000, Jim Kelley wrote: On Jun 5, 7:24 am, Jim Higgins wrote: It's induction coupled plasma, not arc discharge plasma. But let's explore the claim that the water is "burning." If water burns, what are the reactants and what are the reaction products? If it's hydrogen that's burning, then it was derived from the water by applying enough energy to split the water molecule... and if this is really the case then you've input as much energy in the form of RF as you get back by burning the (allegedly) produced hydrogen. Not necessarily. It could be more, less, or the same depending on the precise nature of the reaction. OK... so would you mind explaining one or more variations on "precise nature" that would make for a meaningful difference in energy? Here's the thing. You stated that "you've input as much energy in the form of RF as you get back by burning the (allegedly) produced hydrogen." I'm merely pointing out that there is nothing about the physics and chemistry here which makes that guarantee. As I went on to say, a complete energy analysis requires that the initial and final energy states must also be considered. If the final energy state is higher than the initial state, then more energy will be input than released in the reaction. If the final energy state is lower than the initial energy state then more energy is released than is input. Total energy is certainly conserved in any case. I'm sure you can see my point here. It's far from controversial. 73, ac6xg |
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Jim Higgins wrote: On Tue, 05 Jun 2007 11:45:42 -0700, Jim Kelley wrote: Here's the thing. You stated that "you've input as much energy in the form of RF as you get back by burning the (allegedly) produced hydrogen." I'm merely pointing out that there is nothing about the physics and chemistry here which makes that guarantee. As I went on to say, a complete energy analysis requires that the initial and final energy states must also be considered. If the final energy state is higher than the initial state, then more energy will be input than released in the reaction. If the final energy state is lower than the initial energy state then more energy is released than is input. Total energy is certainly conserved in any case. I'm sure you can see my point here. It's far from controversial. 73, ac6xg I guess I don't see your point. Whan I say energy I mean *all* energy, including any energy possibly stored as heat because the final products might remain hotter than the orginal products. If you have a point that overrides that trivial case I just used to guess at what you're talking about, then you need to explain it in more detail... not because I'm stupid, but because you're simply not presenting your case unless you do; you're just hand waving. If there is something specific in my comments above that you don't understand, please let me know what it is and I'll be happy to elaborate for you. 73, ac6xg |
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