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On 23 jun, 22:34, (Richard Harrison) wrote:
George, K6GW wrote: "What is the esiest/fastest way to calculate received power out of a very short non-resonant antenna?" Field strengths are given in volts per meter. This is related to power by e squared / r. The dissipationless resistance of free-space (a ratio between voltage and current) is 377 ohms. Attenuation due only to reduction of power per square meter as the radio wave envelope expands in space is 6 dB every time distance from the transmitter doubles. That means getting only 1/4 the previous power every time distance from the transmitter doubles. Volts per meter decline linearly with distance from the transmitter. At 10x the distance, the signal strength or volts per meter is 1/10 the previous value. 1/10 the voltage is 1/100 of the power. We have a participant in this newsgroup, Art Unwin, who disdains book contents, but the subject is not nearly exhausted and I don`t intend to exhaust it. Instead, I`ll recommend one of the best books: "Radio-Electronic Transmission Fundamentals" by B. Whitfield Griffith, Jr. Its 2nd edition has just been released by Scitech Publishing, Inc. Whatever it costs it is well worth the price. Best regards, Richard Harrison, KB5WZI Hi Richard, That E is proportional to 1/r is valid for free space propagation. George's question relates to the frequency range where there is no free space (obstacle free) propagation in most cases. For his case, the most important obstacle is mother earth. As in practical cases (distance about several miles, height of receiving antenna about 5 ft), the earth reflected ray cancels most part of the direct ray. Fast methods to get a result are the two-ray formula and/or propagation curves for frequency planning. Add about 10dB loss for heavily populated areas (buildings). Using one of the above methods, will result in E is proportional to 1/ r^3...to 1/r^4. This matches measurements I did myself. Therefore 1/r gives a far from realistic result (too optimistic). Best regards, Wim PA3DJS www.tetech.nl |
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