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#1
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Owen Duffy wrote:
"Sal M. Onella" wrote in : I mistakenly put a 2m antenna on my dual band HT and tried to use it for a short QSO on a nearby 440 repeater. The other ham said I was barely making the repeater, while my poor HT got so hot that I could barely hold it after a minute's use. The antenna was wrong and the heat was real -- whatever the theory behind it. Let the anecodotes flow... Your FM HT is a classic case than can be adequately represented by a steady state analysis. Your HT was operating into a load that increased its dissipation, but there would be almost certainly be other mismatched loads that would decrease its dissipation. The transmitter gets hot because it is operating into an incorrect load impedance, not the 50-ohm load for which it was designed. As far as the transmitter is concerned, that is the only problem. What caused that incorrect load impedance is a totally different topic. If you measured the impedance of that incorrect antenna, and then replaced the antenna with a dummy load of the same impedance (a resistor of the correct value, in series with an inductor/capacitor of the correct value) then your transmitter will not know the difference. The same value of load impedance will cause it to behave in exactly the same way. There are many different physical types of loads that could present exactly the same impedance to the transmitter. These include antennas, dummy loads and various combinations, with or without some length of transmission line involved. So long as the load impedance presented to the transmitter is exactly the same in all cases, the transmitter behaves exactly the same (once it has reached steady state, after the first few cycles of RF... more about that later). The amount of power that the transmitter can deliver into that incorrect load will depend on the transmitter circuit and on the value of the load impedance - but NOT on the physical type of load. You can measure the impedance of the load by disconnecting it from the transmitter and connecting it to an impedance meter. (Seems obvious? Think again - every time you make an impedance measurement, you are using the principle that impedances of the same value are interchangeable with no effect on steady-state operation.) If the load happens to be an antenna and transmission line, you can use programs like NEC and established transmission line theory to make an accurate prediction of the load impedance. If the system happens to include an ATU, that is just another device that modifies the load impedance presented to the transmitter. At that point, you're finished with antennas, transmission lines and ATUs - once you know the load impedance they present to the transmitter, everything else depends on the transmitter alone. In other words, the antenna/transmission-line/ATU system can - and wherever possible, SHOULD - be cleanly separated from transmitter design. The separation interface is the output connector at the rear of the transmitter. In the huge majority of applications, both amateur and professional, it IS possible to separate those two topics cleanly and completely. It seems perverse to tangle them together unnecessarily. All the above refers to the steady state, where the signal level is constant; and if a transmission line is involved, the pattern of standing waves is established and unchanging. For completeness, we now need to check if anything was different during the few moments after switch-on, while the steady-state pattern of standing waves was becoming established. Starting from switch-on, we need to look at each of the successive reflections and re-reflections along the transmission line, and see how the steady state came to be. The first thing to notice is that with the types of signals and lengths of transmission line that we amateurs use, the steady state is established within the first few cycles of RF, ie it all happens over timescales much shorter than the signal's own envelope rise/decay time. This means it is 'nice to know', but will seldom be of practical importance. A detailed analysis of the buildup of reflections along a transmission line will be forced to consider reflections at the transmitter as well as at the load - in other words, we have to specify a reflection coefficient at *both* ends of the line. Chipman's book [1] gives a very detailed analysis of this, and shows how the addition of voltages over multiple reflections gives rise to a standing wave. The amplitude of the standing wave builds up as mathematical series, in which each successive reflection and re-reflection contribute an additional term. Some terms add to the total while others subtract, and each successive term makes a smaller contribution than the one before, so the series will converge towards a constant value which represents the steady state. It should be absolutely no surprise that, when summed to an infinite number of terms, this series produces exactly the same results as the steady-state model - exactly the same pattern of standing waves, and exactly the same load impedance presented to the transmitter. The important conclusion from this more detailed time-dependent analysis is that re-reflections at the transmitter have NO effect on the final steady-state pattern of standing waves. The ONLY effect of re-reflections at the transmitter end was on the time-dependent details of how that pattern built up, and on the final steady-state signal levels. The magnitude of the standing waves depends on the transmitter characteristics (in other words, on the 'signal level') but the shape of the standing waves and their location along the transmission line depends only on the line and the load. There are no special cases he the same conclusion holds for all values of reflection coefficient at the transmitter end, including 1 and 0. Thus, even a detailed time-dependent analysis confirms that, once we have reached the steady state, we can indeed make a clean separation between the transmitter and its load. And since we can, we should. [1] R A Chipman, 'Theory and Problems of Transmission Lines, Schaum's Outline Series', McGraw-Hill. ISBN 0-07-010747-5. (Chipman isn't an easy read, because he is Mr Meticulous who wants to tell you everything; but you can rely on him not to cut corners.) I await the inevitable photon explanation. None needed. If anyone wishes to introduce additional complications where none are necessary, then of course they're at liberty to do so. But when invited to join in, everyone else is at liberty to decline. -- 73 from Ian GM3SEK 'In Practice' columnist for RadCom (RSGB) http://www.ifwtech.co.uk/g3sek |
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#2
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Ian White GM3SEK wrote:
If you measured the impedance of that incorrect antenna, and then replaced the antenna with a dummy load of the same impedance (a resistor of the correct value, in series with an inductor/capacitor of the correct value) then your transmitter will not know the difference. It is true that transmitters are dumb as a stump. However, a human being should be smart enough to realize that the virtual impedance, which is only a voltage to current ratio has been replaced by an impedor with a resistor, inductor, and/or capacitor. The impedor *causes* the load conditions. That virtual voltage to current ratio is a *result* and not the cause of anything. To get down to the actual cause of the conditions, the human being needs to know whether the load impedance is virtual or not. Why do you imply that a virtual impedance can *cause* the conditions seen by a source but deny that a virtual impedance can *cause* 100% re-reflection? Seems a contradiction. In fact, virtual impedances cannot cause anything. The voltage to current ratio associated with a virtual impedance is a *result* of something physical. Choosing to ignore that physical "something else" cause has gotten lots of folks into logical trouble. In the huge majority of applications, both amateur and professional, it IS possible to separate those two topics cleanly and completely. It seems perverse to tangle them together unnecessarily. It seems perverse to say the antenna system can be replaced by a resistor and inductor or capacitor and nothing changes. How about the radiation pattern? Does that change? It should be absolutely no surprise that, when summed to an infinite number of terms, this series produces exactly the same results as the steady-state model - exactly the same pattern of standing waves, and exactly the same load impedance presented to the transmitter. How about the total energy in the steady-state system? The number of joules pumped into the system during the transient state is *exactly* the amount required to support the forward and reflected power readings. The important conclusion from this more detailed time-dependent analysis is that re-reflections at the transmitter have NO effect on the final steady-state pattern of standing waves. This is based on a rather glaring rule-of-thumb assumption, that any standing wave energy dissipated in the source was never sourced to begin with. Born of necessity, that is a rather rash assumption. Thus some people sweep the reflected energy dissipated in the source under the rug and forget about it, hoping that nobody ever lifts the rug and points out the conservation of energy principle. I await the inevitable photon explanation. None needed. If anyone wishes to introduce additional complications where none are necessary, then of course they're at liberty to do so. But when invited to join in, everyone else is at liberty to decline. Optical physicists did not have the luxury of dealing with voltages. As a result of dealing with power densities, they learned a lot more than RF engineers know to this very day. Optical physicists have never asserted that reflected waves are devoid of ExB joules/sec or that EM waves are capable of "sloshing around". -- 73, Cecil http://www.w5dxp.com |
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#3
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Cecil Moore wrote:
Ian White GM3SEK wrote: If you measured the impedance of that incorrect antenna, and then replaced the antenna with a dummy load of the same impedance (a resistor of the correct value, in series with an inductor/capacitor of the correct value) then your transmitter will not know the difference. It is true that transmitters are dumb as a stump. However, a human being should be smart enough to realize that the virtual impedance, which is only a voltage to current ratio has been replaced by an impedor with a resistor, inductor, and/or capacitor. The impedor *causes* the load conditions. That virtual voltage to current ratio is a *result* and not the cause of anything. At the terminals of the load, both the voltage and current are physically real and physically measurable, as also is the phase angle between them. Their ratio is the (complex) load impedance as seen by the transmitter. Any device that creates those same electrical conditions possesses the same impedance; by definition. The transmitter affects the magnitude of the voltage and current in the load, but it categorically does NOT affect their ratio, or the phase angle. In other words, the transmitter has no effect on the value of the impedance that is connected to it as a load, That value is created exclusively by the load. To get down to the actual cause of the conditions, the human being needs to know whether the load impedance is virtual or not. I can see your underlying point, about the difference between a lumped impedance physically present at the transmitter output terminals, and an impedance created by 'action at a distance' through a transmission line. But if both kinds of load create the SAME steady-state voltage:current ratio and phase angle at the transmitter output terminals, then by definition they both have the SAME impedance, and the transmitter will respond in EXACTLY the same way. There is no steady-state measurement you can possibly make on the transmitter than can tell the difference between those two different kinds of load. That principle is absolutely fundamental. It underlies all steady-state impedance measurements using bridges, network analysers etc. Regardless of the nature of the DUT (device under test), you connect it to the meter, measure what you find, and that IS "the impedance of the DUT". The differences only appear if you change frequency, or if you make a time-dependent measurement, but there is never a difference in the steady state. Why do you imply that a virtual impedance can *cause* the conditions seen by a source but deny that a virtual impedance can *cause* 100% re-reflection? Seems a contradiction. In fact, virtual impedances cannot cause anything. The voltage to current ratio associated with a virtual impedance is a *result* of something physical. Choosing to ignore that physical "something else" cause has gotten lots of folks into logical trouble. I invite you to consider another possibility: that the people who have chosen to stick with the established textbook analyses are not ignoring anything, and they are in no kind of logical trouble because those analyses are both logical and consistent; and that the only person in logical trouble is actually yourself, because you are making distinctions between different varieties of impedance that do not exist. In the huge majority of applications, both amateur and professional, it IS possible to separate those two topics cleanly and completely. It seems perverse to tangle them together unnecessarily. It seems perverse to say the antenna system can be replaced by a resistor and inductor or capacitor and nothing changes. How about the radiation pattern? Does that change? Nothing changes in the part of the system I was talking about, namely AT the transmitter/load interface. (Lord, gimme strength...) It should be absolutely no surprise that, when summed to an infinite number of terms, this series produces exactly the same results as the steady-state model - exactly the same pattern of standing waves, and exactly the same load impedance presented to the transmitter. How about the total energy in the steady-state system? The number of joules pumped into the system during the transient state is *exactly* the amount required to support the forward and reflected power readings. If you say so; but nobody else feels the need to calculate those quantities. The important conclusion from this more detailed time-dependent analysis is that re-reflections at the transmitter have NO effect on the final steady-state pattern of standing waves. This is based on a rather glaring rule-of-thumb assumption, that any standing wave energy dissipated in the source was never sourced to begin with. Born of necessity, that is a rather rash assumption. Thus some people sweep the reflected energy dissipated in the source under the rug and forget about it, hoping that nobody ever lifts the rug and points out the conservation of energy principle. All valid solutions to the problem of AC/RF generators, transmission lines and loads will most assuredly comply with the conservation of energy! But countless textbooks show that it isn't necessary to invoke that principle in order to make a valid analysis. I await the inevitable photon explanation. None needed. If anyone wishes to introduce additional complications where none are necessary, then of course they're at liberty to do so. But when invited to join in, everyone else is at liberty to decline. Optical physicists did not have the luxury of dealing with voltages. As a result of dealing with power densities, they learned a lot more than RF engineers know to this very day. Optical physicists have never asserted that reflected waves are devoid of ExB joules/sec or that EM waves are capable of "sloshing around". But WE DO enjoy the luxury of having complete information on voltages, currents and phase angles, at any instant and at every point along a transmission line. That allows us to obtain complete solutions without dragging in unnecessary concepts from other disciplines. -- 73 from Ian GM3SEK 'In Practice' columnist for RadCom (RSGB) http://www.ifwtech.co.uk/g3sek |
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#4
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Ian White GM3SEK wrote:
Any device that creates those same electrical conditions possesses the same impedance; by definition. Sorry Ian, that's just not true. There are three separate definitions for impedance in "The IEEE Dictionary". If all those were the same impedance, they wouldn't need three definitions. A resistor has a resistance. The Z0 of a transmission line is a resistance. They are NOT the same impedance, by definition. The IEEE Dictionary says: "Definition (C) is a second use of "impedance" and is independent of definitions (A) and (B)." (C) is the definition of impedance associated with a resistor, inductor, or capacitor. (B) is the definition of impedance associated with a voltage to current ratio. The IEEE Dictionary goes out of its way to explain that there is a difference. The transmitter affects the magnitude of the voltage and current in the load, but it categorically does NOT affect their ratio, or the phase angle. Strawman But if both kinds of load create the SAME steady-state voltage:current ratio and phase angle at the transmitter output terminals, then by definition they both have the SAME impedance, and the transmitter will respond in EXACTLY the same way. Although they may have the same value of impedance components, they are NOT the same impedance, by IEEE definition. See above. That principle is absolutely fundamental. Too bad that your underlying absolutely fundamental principle is wrong according to the IEEE Dictionary. ... because you are making distinctions between different varieties of impedance that do not exist. I'm just following the IEEE lead. You, OTOH, are in logical trouble for disagreeing with the IEEE. All valid solutions to the problem of AC/RF generators, transmission lines and loads will most assuredly comply with the conservation of energy! But countless textbooks show that it isn't necessary to invoke that principle in order to make a valid analysis. Please show me a textbook that gives you permission to ignore the conservation of energy principle. But WE DO enjoy the luxury of having complete information on voltages, currents and phase angles, at any instant and at every point along a transmission line. That allows us to obtain complete solutions without dragging in unnecessary concepts from other disciplines. But you guys even ignore the laws of physics for electrical engineering, e.g. Vfor*Ifor=Pfor and Vref*Iref=Pref -- 73, Cecil http://www.w5dxp.com |
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#5
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Ian White GM3SEK wrote:
All valid solutions to the problem of AC/RF generators, transmission lines and loads will most assuredly comply with the conservation of energy! That's a valid assumption since nothing can violate the conservation of energy principle. But ignoring the conservation of energy principle under the assumption that the energy will take care of itself leaves one ignorant of where the energy goes. If one doesn't know where the energy goes, that's one's choice, but one shouldn't turn around and present one's self as an expert on the subject of where the energy goes. As someone said: 'I personally don't have a compulsion to understand where this power "goes"', as if understanding might be an undesirable thing. But countless textbooks show that it isn't necessary to invoke that principle in order to make a valid analysis. It's obvious that you have never perceived the need to know where the energy goes - that the energy will automatically take care of itself - and that's perfectly OK. I, OTOH, have spent considerable time and effort studying and tracking the energy through the system in order to understand how the energy balance is achieved and where the energy goes. So which of us would tend to know more about where the energy goes? I have discovered that there is always exactly the amount of energy in any transmission line needed to support the measured forward and reflected power. It seems illogical to me to argue that the energy is somewhere else besides in the forward and reflected waves. -- 73, Cecil http://www.w5dxp.com |
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#6
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Ian White GM3SEK wrote in
: Ian, an excellent and quite comprehensive treatment. Sal, Some folk will try to distract from an adequately accurate approximation (being the steady state solution) by wanting to descend to a time domain solution which as you note converges to the steady state solution in time, but is much more complex to solve. The relevance of steady state solutions is demonstrated by the traditional methods of designing transmission line transformers (eg quarter wave match), stub matching schemes, the application of the Smith chart etc. These things are only valid on applications where a steady state solution is valid, and the widespread use of them attests to the widespread existence of systems that are quite adequately analysed by steady state methods. Most ham applications are ones where the highest modulating frequency is very small wrt the carrier frequency, and are emminently suited to steady state analysis. Similarly, consider that when steady state analysis is not appropriate, then many of the devices mentioned above may be inappropriate as they will cause distortion of the signal. Owen |
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