Antonio Vernucci wrote:
Dave wrote:

You can do the same with DC - you don't need to use AC at all. Put a
50 V battery in series with the pure 50 Ohm load and it supplies 50
W. Put it in series with another load, consisting of a 50 Ohm voltage
source in
consisting of a 50 volt voltage source, not a 50 Ohm voltage source!
series with a 50 Ohm load, and it is no surprise it delivers a
different power. Depending on what way you connect the two batteries,
the current would be 0 A or 4 A, and so the power 0 or 200W.
As I said before, 0 or 2A, which gives 0 or 200 W.

Your example, though correct, has little to do with the case being
discussed.

In your example it is true that power varies depending on what way you
connect the two batteries, but in all cases the total power dissipated
in the loads remains equal to the total power delivered by the sources.

yes

In the case being discussed instead the power dissipated in the load
varies with NO CHANGE in total power delivered by the sources.

no way. Prove there is no change in the power delivered by the sources.