On Sun, 18 Nov 2007 12:05:05 -0500, "Stefan Wolfe"
wrote:


"Richard Clark" wrote in message
.. .
On Sun, 18 Nov 2007 00:16:47 -0500, "Stefan Wolfe"
wrote:

Let's rewind up that list of charades to revisit:
Well, power is a vector quanity subject to the rules of vector
math.
and ponder the implication of a negative power, for simplicity:
P1 = 50W @ 90deg
P2 = 50W @ 270deg
what does the math reveal?

I am not trying to define power as negative with respect to zero
Negative with respect to zero? What about with respect to positive?
Or even a smaller negative! How about half negative (only 90 degrees
shift instead of 180)?
What happened to:
Well, power is a vector quanity subject to the rules of vector
math.

I was so wanting to see your solution, much less how:
Ptotal = P1 + P2 + 2*SQRT(P1*P2)cos(A)
migrated into the negated sine in:
= (50 - 0) + (50 - 0) - 2SQRT P1*P2 sine(A)


Oh God this is getting frustrating!

You are lagging the community by at least 8 to 10 postings.

http://math2.org/math/integrals/more/restrig.htm

1. See top equation. THE INTEGRAL OF A COSINE IS A SINE.

What you published above is not the integral of the system and it has
problems even in isolation.

I added a minus
sign, I shouldn't have BUT IT DOESN'T MATTER.

As so many previous mistakes don't matter either. I also note (and I
am full aware of the math) that YOUR reference (see top equation)
solves with a constant added - as it should if this were a legitimate
exercise.

My students didn't get full credit for discarding constants,
especially when they didn't have the vaguest notion of how these
constants contribute to the outcome.

Let me guess, you will say "it doesn't matter" with emphasis. :-)

I think you are marginalizing your credibility with each succeeding post in
which you dispute freshman caluclus fundamentals. Depending upon your
education base, this could be quite a blow to you. I thought you knew
math...maybe it was just me getting the wrong impression. Are you pulling
our legs?

Well, I did think I had mined this troll to completion, but another
round may yet bring more fascinating entries.

73's
Richard Clark, KB7QHC