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#1
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Gene Fuller wrote:
"the intensity varies between a maximum value Imax = 4I1, and a minimum value Imin = 0" Yes, that's essentially what I have been saying. The peak intensity (irradiance) can be double the intensity of the combined intensity of both superposed waves. What B&W *don't* say is anything about two 1 watt waves interacting, waves exhibiting constructive and destructive interference, cause and effects relationships, or even energy conservation. Eugene Hecht calls the last term in the irradiance equation the "interference term". He talks about "total destructive interference" and "total constructive interference". The sign of the interference term indicates whether the interference is destructive (-) or constructive (+). All of those are things written by more casual writers, such as Hecht, Melles-Griot, and the FSU Java dudes. There is nothing wrong with that type of explanation for simple illustration, but it runs out of gas when trying to support detailed analysis. One quickly ends up with silliness such as waves that are launched and then cancel destructively within a short (but undefined) distance. None of that nonsense occurs if one simply applies the standard analysis techniques such as used by B&W. Exactly what nonsense are you referring to? Please be specific. It is difficult to defend myself from assertions of "nonsense" with no specific allegations. I gather from the above that wave cancellation due to superposition is against your religion. Since all impedance discontinuities cause reflections, exactly how and why do those reflected waves cease to exist? Please be specific. -- 73, Cecil http://www.w5dxp.com |
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#2
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Cecil Moore wrote:
Gene Fuller wrote: "the intensity varies between a maximum value Imax = 4I1, and a minimum value Imin = 0" Yes, that's essentially what I have been saying. The peak intensity (irradiance) can be double the intensity of the combined intensity of both superposed waves. What B&W *don't* say is anything about two 1 watt waves interacting, waves exhibiting constructive and destructive interference, cause and effects relationships, or even energy conservation. Eugene Hecht calls the last term in the irradiance equation the "interference term". He talks about "total destructive interference" and "total constructive interference". The sign of the interference term indicates whether the interference is destructive (-) or constructive (+). All of those are things written by more casual writers, such as Hecht, Melles-Griot, and the FSU Java dudes. There is nothing wrong with that type of explanation for simple illustration, but it runs out of gas when trying to support detailed analysis. One quickly ends up with silliness such as waves that are launched and then cancel destructively within a short (but undefined) distance. None of that nonsense occurs if one simply applies the standard analysis techniques such as used by B&W. Exactly what nonsense are you referring to? Please be specific. It is difficult to defend myself from assertions of "nonsense" with no specific allegations. I gather from the above that wave cancellation due to superposition is against your religion. Since all impedance discontinuities cause reflections, exactly how and why do those reflected waves cease to exist? Please be specific. Cecil, Waves are useful. However, they are not living objects. They have no will to survive. There is nothing in the standard E&M science based on Maxwell's laws that requires waves to be "canceled" if they no longer exist. There is no conservation law of wave-ality. If the proper equations are set up and the proper boundary conditions are applied (not always easy to do), then waves will exist where they are needed to describe the physical reality and they will not exist where they are not needed. There is no need to worry about waves that don't exist. As for the "nonsense", we had this discussion a few times, including a couple of months ago. I don't feel like finding the exact messages, but the gist was something like: "Wave 4 and wave 5 return toward the source from a match point, but they are opposite phase and therefore cancel after a short journey." If you don't recognize that exchange, let's just drop it. 73, Gene W4SZ |
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#3
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Gene Fuller wrote:
Cecil Moore wrote: Cecil, Waves are useful. However, they are not living objects. They have no will to survive. There is nothing in the standard E&M science based on Maxwell's laws that requires waves to be "canceled" if they no longer exist. There is no conservation law of wave-ality. If the proper equations are set up and the proper boundary conditions are applied (not always easy to do), then waves will exist where they are needed to describe the physical reality and they will not exist where they are not needed. There is no need to worry about waves that don't exist. As for the "nonsense", we had this discussion a few times, including a couple of months ago. I don't feel like finding the exact messages, but the gist was something like: "Wave 4 and wave 5 return toward the source from a match point, but they are opposite phase and therefore cancel after a short journey." If you don't recognize that exchange, let's just drop it. 73, Gene W4SZ Hi Gene, Yes. The short journey was described by the term "dt". According to Cecil, that is the amount of time after energy is reflected and before it 'turns around and goes the other way as it is required to do by the law of conservation of energy'. You may recall that it is forced to go the other way 'because there are only two directions in a transmission line'. 73, ac6xg |
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#4
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On Tue, 20 Nov 2007 14:37:41 -0800, Jim Kelley
wrote: The short journey was described by the term "dt". Ah, suffering the dt's. As Ed McMahon would prompt Johnny: "Just how short was that journey?" My guess it will either be too short to do the job, or much too large to be true. This thread should be called: "Supposition" or "Imposition" or "Superstition" 73's Richard Clark, KB7QHC |
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#5
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Jim Kelley wrote:
Yes. The short journey was described by the term "dt". According to Cecil, that is the amount of time after energy is reflected and before it 'turns around and goes the other way as it is required to do by the law of conservation of energy'. You may recall that it is forced to go the other way 'because there are only two directions in a transmission line'. So you don't even accept differential calculus? :-) Jim, you have never answered the tough questions so I will keep asking. I just posted an example with one question that should be easy for you to answer. In the example, what happens to the energy and momentum in Pref1 when the load is switched from 300 ohms to 50 ohms? It's a simple question. Please be specific in your answer. -- 73, Cecil http://www.w5dxp.com |
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#6
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Gene Fuller wrote:
Waves are useful. However, they are not living objects. They have no will to survive. There is nothing in the standard E&M science based on Maxwell's laws that requires waves to be "canceled" if they no longer exist. There is no conservation law of wave-ality. All EM waves must obey the conservation of energy and conservation of momentum principles. It is not a will to survive - it is simply the laws of physics. Here is an example for you to explain. The source is a signal generator equipped with an ideal circulator and a load resistor: Steady-state #1: Rho at '+' equals 0.7143. Load equals 300 ohms. 100w SGCL--50 ohm feedline--+--1/2WL 300 ohm feedline--300 ohm load Pfor1=100w-- Pfor2=49w-- --Pref1=51w --Pref2=0w Pref1 is an 51w EM wave whose energy and momentum must be conserved. Steady-state #2: Rho at '+' equals 0.7143. Load is switched to 50 ohms. 100w SGCL--50 ohm feedline--+--1/2WL 300 ohm feedline--50 ohm load Pfor1=100w-- Pfor2=204W-- --Pref1=0w --Pref2=104w *Note that Rho has NOT changed!* The only question that you need to answer is during the process that changes Pref1 from 51 joules/sec in the direction of the source to 0 joules/sec (canceled), *exactly* what happens to the energy and momentum? Please be specific. -- 73, Cecil http://www.w5dxp.com |
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#7
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On Wed, 21 Nov 2007 14:00:39 GMT, Cecil Moore
wrote: What is the momentum of 50.95 W? momentum? Please be specific. ditto. :-) |
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#8
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Richard Clark wrote:
On Wed, 21 Nov 2007 14:00:39 GMT, Cecil Moore wrote: What is the momentum of 50.95 W? momentum? Please be specific. ditto. :-) If 50.95 watts is the Poynting vector, actually watts/unit-area, then the momentum is 50.95/c^2. Please reference pages 56,57 of "Optics", by Hecht, 4th edition. -- 73, Cecil http://www.w5dxp.com |
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#9
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Cecil Moore wrote:
Richard Clark wrote: On Wed, 21 Nov 2007 14:00:39 GMT, Cecil Moore wrote: What is the momentum of 50.95 W? momentum? Please be specific. ditto. :-) If 50.95 watts is the Poynting vector, actually watts/unit-area, then the momentum is 50.95/c^2. Please reference pages 56,57 of "Optics", by Hecht, 4th edition. 50.95 divided by the speed of light squared? So, for all practical purposes - if that's right - it's zero. Why not just say so? 73, Tom Donaly, KA6RUH |
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#10
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Tom Donaly wrote:
Cecil Moore wrote: Richard Clark wrote: On Wed, 21 Nov 2007 14:00:39 GMT, Cecil Moore wrote: What is the momentum of 50.95 W? momentum? Please be specific. ditto. :-) If 50.95 watts is the Poynting vector, actually watts/unit-area, then the momentum is 50.95/c^2. Please reference pages 56,57 of "Optics", by Hecht, 4th edition. 50.95 divided by the speed of light squared? So, for all practical purposes - if that's right - it's zero. Why not just say so? The percentage difference between zero and that momentum is infinite. And whatever value it is must be conserved. Sweeping it under the rug in violation of the laws of physics is just not acceptable. -- 73, Cecil http://www.w5dxp.com |
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