Resontate frequency of parallel L/C
 

John Smith wrote:
Cecil Moore wrote:
John Smith wrote:

w5dxp wrote:
1/(2pi*sqrt(l*c))

= 1/(2.28318*100)

Hmmm. Seems as if my calculator is broken also ...

If your calculator says that pi = SQRT(2), it
is no doubt broken.

Well, I don't see that but ...

Ahhh, just a little fun with "paddin' the figures", heck others do it
here! ;-)

Regards,
JS


I prefer

4427007044615115050034854648525685871587
----------------------------------------
1409160108506276783085718440252375099653

as a rough approximation to Pi.

Resontate frequency of parallel L/C
 

Dave wrote:

I prefer

4427007044615115050034854648525685871587
----------------------------------------
1409160108506276783085718440252375099653

as a rough approximation to Pi.





For sqrt(2),


16801980213452902006767691473844047811063360557160 1
---------------------------------------------------
11880794146294742246965551933607978236747301359246 0

is good enough for most engineering applications.

Anyone care to tell me what well known number this is a reasonable
approximation to?

19078001745537814647816786923051094576738662184691 34974601281
-------------------------------------------------------------
70184046208162524076589093068072649877753883914468 2132979719

Resontate frequency of parallel L/C
 

Dave wrote:

Anyone care to tell me what well known number this is a reasonable
approximation to?

19078001745537814647816786923051094576738662184691 34974601281
-------------------------------------------------------------
70184046208162524076589093068072649877753883914468 2132979719






And for a bonus point, how good is the approximation?

Resontate frequency of parallel L/C
 

Tom Donaly wrote:
Cecil Moore wrote:
That's pretty interesting and not intuitively obvious.

Hi Cecil,
Reg Edward's favorite book _Communication Engineering_ by
William L. Everitt discusses constant resistance networks under the
Chapter entitled "Equalizers."

Thanks very much, Tom, I looked in Johnson's "T-lines &
Networks" and "Reference Data for RF Engineers" and didn't
find that particular design described.
--
73, Cecil http://www.w5dxp.com

Resontate frequency of parallel L/C
 

John Smith wrote:
Cecil Moore wrote:
John Smith wrote:

1/(2pi*sqrt(l*c))

= 1/(2.28318*100)

Hmmm. Seems as if my calculator is broken also ...

If your calculator says that pi = SQRT(2), it
is no doubt broken.

Well, I don't see that but ...

In your above equation pi = 2.28318/2 = 1.4159
--
73, Cecil http://www.w5dxp.com

Resontate frequency of parallel L/C
 

Dave wrote:
Anyone care to tell me what well known number this is a reasonable
approximation to?

19078001745537814647816786923051094576738662184691 34974601281
-------------------------------------------------------------
70184046208162524076589093068072649877753883914468 2132979719

http://en.wikipedia.org/wiki/Natural_logarithm
--
73, Cecil http://www.w5dxp.com

Resontate frequency of parallel L/C
 

Cecil Moore wrote:
In your above equation pi = 2.28318/2 = 1.4159

Sorry, that's wrong - I should have used a calculator
instead of my brain before my first cup of java.
--
73, Cecil http://www.w5dxp.com

Resontate frequency of parallel L/C
 

Cecil Moore wrote:
Dave wrote:
Anyone care to tell me what well known number this is a reasonable
approximation to?

19078001745537814647816786923051094576738662184691 34974601281
-------------------------------------------------------------
70184046208162524076589093068072649877753883914468 2132979719

http://en.wikipedia.org/wiki/Natural_logarithm


Correct, but to what accuracy?

Resontate frequency of parallel L/C
 

Cecil Moore wrote:

Well, I don't see that but ...

In your above equation pi = 2.28318/2 = 1.4159

Hmmm, pi = ~3.14159, 2pi = ~6.28318

Why the redirected output, into thunderbird, came out like that (the
2.28318)--I don't know.

Ruined it, huh? :-(

Regards,
JS

Resontate frequency of parallel L/C
 

Cecil Moore wrote:
Cecil Moore wrote:
In your above equation pi = 2.28318/2 = 1.4159

Sorry, that's wrong - I should have used a calculator
instead of my brain before my first cup of java.

I knew what you meant ... ;-)

Regards,
JS