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"Richard Harrison" wrote in message
... [...] Steve also wrote: "Also ok, but not sure how it plays into the RMS discussion." My speculation is that the effective value of a nonsinusoidal waveform could be found by summation of its sinusoidal constituents. That's what I thought you were going for. My gut feel is that this must be valid, otherwise "Fourier ain't an exact solution after all". But it sounds like a lot of work and you have to be able to extract all the significant Fourier components (harmonics) and there is an element of approximation here, just like my "mathematicall function" method, no? ....Of course doing the integration on the waveform takes some time to crank through the math and get all the quantities collected correctly. But, it`s not difficult to find an effective value for ... nonsinusoidal periodic waveforms as well. One can graphically take For what I wanted to do, the integration was easier. I may be wrong, but Fourier also needs a function and you still need to integrate, no? Now, to answer Richard Clark's comments about accuracy in another post... I did assume that the wave shapes I was interested in were defined (I think the word is) explicitly. I assumed a mathematical function. When I compared the three waveforms which were appropriate (sine, triangle, trapezoid) the results were very much the same (for ratio of RMS to Average). (gotta remember to keep my sentences shorter). From this I came to the conclusion that for wave shapes which differed slightly from the ideal (assumed shapes) the values would be well within acceptable bounds. Easily 5%. Yes, not exact, but much better than Bob Shrader had assumed. large number of equally spaced ordinates of the form, using at least one complete alternation, Richard Clark. I don't think they have to be equally spaced since the actual time enters into the calculation (as you described later). This would make long sections with a constant value easier. Both alternations are not needed but could be used as a minus times a minus is a plus and each of the This assumes that the waveform is symmetrical around zero. I think in general, one whole period is required. or[...] using a planimeter. Richard H. clearly prefers graphical solutions and that's ok. Unless I`ve opened a new can of worms with this posting, I don`t know of any difference of opinion I have with Steve. Best regards, Richard Harrison, KB5WZI Right now it appears that this half vs. full period is the only difference I can see. -- Steve N, K,9;d, c. i My email has no u's. |
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