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#821
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Gene Fuller wrote:
Cecil Moore wrote: Gene Fuller wrote: Cecil Moore wrote: You missed the point. A terminating capacitor is a two terminal network. The point where two pieces of feedline are connected is a four-terminal network. A two-terminal network is different from a four-terminal network. This appears to be an unusual definition. Not unusual at all, Gene. The two input terminals to the black box are on one side. The two output terminals from the black box are on the other side. The impedance discontinuity is inside the box. The black box is extremely small. Give me the four s-parameters, s11, s12, s21, and s22 and I can tell you virtually everything about what is inside the black box without even applying a signal. BZZZT! Wrong answer. Nobody ever said anything about the "other side" of the black box. That's obviously a lie. I said something about the other side of the black box. Yet by your models and math the black boxes don't behave the same in your test circuit. That's another lie. All my models and math show the black boxes all behaving exactly the same external to the two input terminals. In fact, I have said it is impossible for it to be any other way. Is there no limit to how dishonest you will be? -- 73, Cecil http://www.w5dxp.com |
#822
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![]() As for your last sentence. The "he" is rather unspecific as two correspondents made a promise (perhaps not so well timed as to fit your observation here). However, I too will sit on the edge of my seat in wonderment to that outcome. 73's Richard Clark, KB7QHC Didn't read your last (promise) until after I sent that. You know who I meant. BTW, did you just by any chance ever work for me at the PME Lab in Hawaii ? W4ZCB |
#823
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Roy Lewallen wrote:
I see that the smudge pots have been lit and the hand waving, misdirection, and desperate attempts at changing the subject begins. As they have so many times before. What a waste of all that alleged IQ. Do you think that waving your hands and posting gobblegook like the above is any better? Please, please, make a technical statement with which you know I disagree and let's discuss it like mature individuals. -- 73, Cecil http://www.w5dxp.com |
#824
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Harold E. Johnson wrote:
I do believe that someone may have inadvertently added 100 to that IQ. Everyone on here with the exception of the gifted one has known for the last 3 days that Richard has been just pulling his bobber under. He finally picked up on it this morning and decided to stop wasting his time. Now if he would only make that a promise! I'm a simple trusting person who tries to see the good in everyone, even Richard C. Please pick a technical subject upon which we disagree and let's discuss it like technical gentlemen. -- 73, Cecil http://www.w5dxp.com |
#825
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Roy Lewallen wrote:
I see that the smudge pots have been lit and the hand waving, misdirection, and desperate attempts at changing the subject begins. As they have so many times before. What a waste of all that alleged IQ. Roy, you are always saying I should be using voltages for my calculations and that's exactly what I did. --43.4 deg 600 ohm line--+--10 deg 100 ohm line--open Vfor1--|--Vfor2 With 100 volts at zero degrees incident upon the open end of the stub, I get: Vfor1 = 143.33 volts at -46.6 deg Vfor2 = 110 volts at -10 deg for a phase shift through the impedance discontinuity of 36.6 degrees. What do you get? Don't anybody hold his breath waiting for an answer. The Emperor has no clothes. -- 73, Cecil http://www.w5dxp.com |
#826
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Cecil Moore wrote:
Jim Kelley wrote: Cecil Moore wrote: I(x,t) = Imax sin(kx) cos(wt) Standing-wave current phase changes hardly at all up and down a stub with losses or a wire 1/2WL dipole. That is correct to the same extent that t in the equation above "changes hardly at all" with time. 73, ac6xg |
#827
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Roy Lewallen wrote:
I see that the smudge pots have been lit and the hand waving, misdirection, and desperate attempts at changing the subject begins. As they have so many times before. What a waste of all that alleged IQ. Please note: This is pure unadulterated political power in action devoid of any technical content. Roy is trying to use his guru status, devoid of any technical argument, to try to discredit someone. If I am so obviously technically wrong, why doesn't he just prove me wrong with mathematics and formulas? (Because he cannot?) -- 73, Cecil http://www.w5dxp.com |
#828
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On Mon, 17 Dec 2007 21:02:16 GMT, "Harold E. Johnson"
wrote: Didn't read your last (promise) until after I sent that. You know who I meant. BTW, did you just by any chance ever work for me at the PME Lab in Hawaii ? Hi Howard, Hmmm, how to answer that. Did that fellow remind you of me? Well, to cut to the chase, I was SUBLANT, USS Holland AS-32, Nuclear Navy; and as far as I know, the closest point of approach would have been Guam (aside from our time in the yards at Bremerton, across the water from where I live now). 73's Richard Clark, KB7QHC |
#829
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Jim Kelley wrote:
Cecil Moore wrote: Jim Kelley wrote: Cecil Moore wrote: I(x,t) = Imax sin(kx) cos(wt) Standing-wave current phase changes hardly at all up and down a stub with losses or a wire 1/2WL dipole. That is correct to the same extent that t in the equation above "changes hardly at all" with time. t changes hardly at all referenced to the source current phase which is what we are talking about. Please don't try to feign ignorance of that fact. What I don't get is why people like you have to distort the technical facts. What do you possibly have to gain through distortion and diversion? -- 73, Cecil http://www.w5dxp.com |
#830
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Jim Kelley wrote:
Cecil Moore wrote: Jim Kelley wrote: Cecil Moore wrote: I(x,t) = Imax sin(kx) cos(wt) Standing-wave current phase changes hardly at all up and down a stub with losses or a wire 1/2WL dipole. That is correct to the same extent that t in the equation above "changes hardly at all" with time. The phase is referenced to the source phase, as it is in EZNEC, but you already knew that and just want to perform your usual diversions away from the technical facts. I have said at least a dozen times that the current phase I am talking about is the same as EZNEC reports. If you don't like what EZNEC reports, take it up with Roy. For those who don't understand Jim's diversion above, EZNEC sets t=zero as a reference and then reports the phase. Jim knows that and is just trying to hoodwink the uninitiatated. His motives for such remain a mystery. -- 73, Cecil http://www.w5dxp.com |
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