On 27 Nov, 06:18, Cecil Moore wrote:
John Smith wrote:
1/2 wave monopoles
have little dependence of a full counterpoise or ground for, at least,
acceptable performance.

The Zepp antenna is a 1/2WL monopole with no
counterpoise.
--
73, Cecil http://www.w5dxp.com

That makes sense. Physically it is half wave
but electrically it is a full wave antenna.
It is able to radiate on its surface and is unable to radiate
as it returns down the center of the wire.
(assuming the antenna is not tubular)
The path on the outside is helical which promotes a slow wave
so the physical wavelength has to be increased slightly to
compensate.When JS made his Vincent model the physical
length was slightly longer than a electrical half wave length
because of this so it still was not quite balanced.
To bring the antenna into balance there must be a contrawound
widing put into place such that the radiating current on the
return path is exposed and not enclosed. Doing this will not
correct the slow wave phenomina but will neutralise the
increased inductance created by the windings and at the same time
bring the radiator back to equilibrium where the correct LC ratio
is maintained and the radiator is a full electrical wavelength in
equilibrium and of variable shape and elevation.
Sound familiar?
Art Unwin.....KB9MZ...xg
Note the wire center contains no inductive or capacitive
properties, only resistive. Thus radiation will be slightly
over 50% of a full wave radiator.

On Tue, 27 Nov 2007 07:31:55 -0800 (PST), art
wrote:

It is able to radiate on its surface and is unable to radiate
as it returns down the center of the wire.
(assuming the antenna is not tubular)

Hi Arthur,

Very interesting assumption. I suppose (and that is always a risk
with a renowned theoretician such as yourself) that you have an
instrument that can detect the difference in radiation between a solid
wire and a tubular one - all other externalities being the same?

No, I suppose not. You've been burnt too many times with your own
results confounding your expectations. However, putting that grief
aside (and it must be a terrible burden to endure), if a hollow
element were filled with a custard center so that it was in
equilibrium, would it radiate?

73's
Richard Clark, KB7QHC

On 27 Nov, 08:54, Richard Clark wrote:
On Tue, 27 Nov 2007 07:31:55 -0800 (PST), art
wrote:

It is able to radiate on its surface and is unable to radiate
as it returns down the center of the wire.
(assuming the antenna is not tubular)

Hi Arthur,

Very interesting assumption. I suppose (and that is always a risk
with a renowned theoretician such as yourself) that you have an
instrument that can detect the difference in radiation between a solid
wire and a tubular one - all other externalities being the same?

No, I suppose not. You've been burnt too many times with your own
results confounding your expectations. However, putting that grief
aside (and it must be a terrible burden to endure), if a hollow
element were filled with a custard center so that it was in
equilibrium, would it radiate?

73's
Richard Clark, KB7QHC

The material is diamagnetic which means that it has the ability to
levitate particles of like form. Levitation is the result of a
particle
escaping from its immediate gravitational pull and where it can exist
unharmed by surrounding gravitational action which by its very nature
has voids in gravitational action. In the case of a Gaussian
field that means to escape to beyond the arbitary border.
It is this very movement of particles without regard to gravitational
forces that allows for straight line actions inspite of the spherical
surface of the earth
Where material is solid then the internal surfaces of the skin depth
which is also the external surface of current flow cannot levitate any
part of the intervening structure.
Levitation is created by a magnetic field where escape from the parent
structure is possible.On the inside levitation since particles
concerned
are part and parcel of the material without freedom levitation is not
possible.
By the same token inductance and capacitance cannot exist on the
internal
path since another skin depth cannot exist.

If a radiator is made of a tube of minimal thickness with respect to
skin
depth and the ends filled with the same diamagnetic
material where a fuse connects them, the fuse will blow when RF is
applied to the external surface

On Tue, 27 Nov 2007 10:32:46 -0800 (PST), art
wrote:

On 27 Nov, 08:54, Richard Clark wrote:
On Tue, 27 Nov 2007 07:31:55 -0800 (PST), art
wrote:

It is able to radiate on its surface and is unable to radiate
as it returns down the center of the wire.
(assuming the antenna is not tubular)
....
you have an
instrument that can detect the difference in radiation between a solid
wire and a tubular one - all other externalities being the same?
....
If a radiator is made of a tube of minimal thickness with respect to
skin
depth and the ends filled with the same diamagnetic
material where a fuse connects them, the fuse will blow when RF is
applied to the external surface

Hi Arthur,

Let's make this practical for 2M. The skin depth there is all of 30
millionths of an inch and we can talk about a tube with maybe 100
millionths of an inch wall thickness, so let's make it a tube with a 1
thousandth inch diameter with the conventional length of 39 inches.

What size fuse will blow?

73's
Richard Clark, KB7QHC

On 27 Nov, 10:48, Richard Clark wrote:
On Tue, 27 Nov 2007 10:32:46 -0800 (PST), art
wrote:







On 27 Nov, 08:54, Richard Clark wrote:
On Tue, 27 Nov 2007 07:31:55 -0800 (PST), art
wrote:

It is able to radiate on its surface and is unable to radiate
as it returns down the center of the wire.
(assuming the antenna is not tubular)
...
you have an
instrument that can detect the difference in radiation between a solid
wire and a tubular one - all other externalities being the same?
...
If a radiator is made of a tube of minimal thickness with respect to
skin
depth and the ends filled with the same diamagnetic
material where a fuse connects them, the fuse will blow when RF is
applied to the external surface

Hi Arthur,

Let's make this practical for 2M. The skin depth there is all of 30
millionths of an inch and we can talk about a tube with maybe 100
millionths of an inch wall thickness, so let's make it a tube with a 1
thousandth inch diameter with the conventional length of 39 inches.

What size fuse will blow?

73's
Richard Clark, KB7QHC- Hide quoted text -

- Show quoted text -

What ever you want.There is nothing more to discuss
with you. Send what you refee to as your missives elswhere

On Tue, 27 Nov 2007 14:08:39 -0800 (PST), art
wrote:

On 27 Nov, 10:48, Richard Clark wrote:
On Tue, 27 Nov 2007 10:32:46 -0800 (PST), art
wrote:
If a radiator is made of a tube of minimal thickness with respect to
skin
depth and the ends filled with the same diamagnetic
material where a fuse connects them, the fuse will blow when RF is
applied to the external surface

Let's make this practical for 2M. The skin depth there is all of 30
millionths of an inch and we can talk about a tube with maybe 100
millionths of an inch wall thickness, so let's make it a tube with a 1
thousandth inch diameter with the conventional length of 39 inches.

What size fuse will blow?

What ever you want.There is nothing more to discuss
with you. Send what you refee to as your missives elswhere

Hi Arthur,

So basically you are telling us you don't know how to distinguish a
hollow conductor from a solid one based on practical testing
demonstrating how an hollow conductor will "blow a fuse when RF is
applied to it." [No one is surprised you can't perform this.]

73's
Richard Clark, KB7QHC

"art" wrote in message
...
On 27 Nov, 06:18, Cecil Moore wrote:
John Smith wrote:
1/2 wave monopoles
have little dependence of a full counterpoise or ground for, at least,
acceptable performance.

The Zepp antenna is a 1/2WL monopole with no
counterpoise.
--
73, Cecil http://www.w5dxp.com

That makes sense. Physically it is half wave
but electrically it is a full wave antenna.
It is able to radiate on its surface and is unable to radiate
as it returns down the center of the wire.
(assuming the antenna is not tubular)
The path on the outside is helical which promotes a slow wave
so the physical wavelength has to be increased slightly to
compensate.When JS made his Vincent model the physical
length was slightly longer than a electrical half wave length
because of this so it still was not quite balanced.
To bring the antenna into balance there must be a contrawound
widing put into place such that the radiating current on the
return path is exposed and not enclosed. Doing this will not
correct the slow wave phenomina but will neutralise the
increased inductance created by the windings and at the same time
bring the radiator back to equilibrium where the correct LC ratio
is maintained and the radiator is a full electrical wavelength in
equilibrium and of variable shape and elevation.
Sound familiar?
Art Unwin.....KB9MZ...xg
Note the wire center contains no inductive or capacitive
properties, only resistive. Thus radiation will be slightly
over 50% of a full wave radiator.



To put it mildly:
The biggest crock of sheeeet yet!

bada BUm

Yuri Blanarovich wrote:

...
To put it mildly:
The biggest crock of sheeeet yet!

bada BUm



Could you possibly lighten up on the intellectual content of your
posts--some of are "Yuri Challenged" yanno?

JS