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#1
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Keith Dysart wrote:
So sometimes a 600 to 100 ohm discontinuity produces a 36.6 degree phase shift and sometimes it produces a 22.7 degree phase shift (and probably any value in between). Yes, of course - nobody said the phase shift wasn't a variable. Why would you expect it to be a constant? It is a variable that depends upon the phase of the component forward and reflected waves. I suggest that "work[ing] up the phasor diagrams of the component voltages (or currents) at the junction where rho = (600-100)/(600+100) = 0.7143" will not be useful for predicting the phase shift. It will be useful for reporting that particular phase shift. If other conditions change, that phase shift will change. What is unexpected about that? -- 73, Cecil http://www.w5dxp.com |
#2
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On Dec 7, 4:09 pm, Cecil Moore wrote:
Keith Dysart wrote: So sometimes a 600 to 100 ohm discontinuity produces a 36.6 degree phase shift and sometimes it produces a 22.7 degree phase shift (and probably any value in between). Yes, of course - nobody said the phase shift wasn't a variable. Why would you expect it to be a constant? It is a variable that depends upon the phase of the component forward and reflected waves. I suggest that "work[ing] up the phasor diagrams of the component voltages (or currents) at the junction where rho = (600-100)/(600+100) = 0.7143" will not be useful for predicting the phase shift. It will be useful for reporting that particular phase shift. If other conditions change, that phase shift will change. What is unexpected about that? You implied that you were going to compute it using just rho, which would mean it would be constant for any pair of impedances. With more inputs, it might be possible to compute a number that, when added to the actual electrical lengths of the lines, will result in 90 degrees. I expect the algorithm to be fairly complicated. Of course, one can always just say it is equal to 90 minus the sum of the electrical lengths of the lines, though if there were two or more impedance discontinuities, it might be difficult to apportion the difference between them. I await the algorithm. ....Keith |
#3
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Keith Dysart wrote:
You implied that you were going to compute it using just rho, which would mean it would be constant for any pair of impedances. No, I did not. Rho can be constant but the phase angle of the incident voltage changes with position. Therefore, the phase angle of the reflected voltage changes with position. This subject is already covered in my energy analysis article at: http://www.w5dxp.com/energy.htm -- 73, Cecil http://www.w5dxp.com |
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