Cecil Moore wrote:
Keith Dysart wrote:
So the next question is: What is the phase change
at the terminals of the black box?

It just occurred to me that you and I may be talking
about two different phases.

---Z01---+---Z02---

Vfor1--|--Vfor2

Vref1--|--Vref2

Continuing: What is the phase shift between Vfor1 and
Vfor2 for example:
(1) a capacitor with -j567 ohms impedance
(2) a 600 to 100 ohm dual-Z0 stub
(3) a single 600 ohm stub

I hope you are not going to tell us it's the same in
each case.
--
73, Cecil http://www.w5dxp.com

On Sun, 16 Dec 2007 19:17:48 GMT, Cecil Moore
wrote:

Cecil Moore wrote:
It just occurred to me that you and I may be talking
about two different phases.
Continuing: What is the phase shift

When you acknowledge there is some confusion as to which phase is
being talked about. Do you suppose you know enough to tell us which
phase you are talking about?

More to the matter, what TWO phases do you suppose there are to be
confused between?

At 800+ postings, you could continue to sail right on past these
questions in your cloud of netzheimer bliss and leave us with a 50%
risk -um- chance; answer your challenge; and watching you trying to
sort it out. Again.

Richard Clark wrote:
On Sun, 16 Dec 2007 19:17:48 GMT, Cecil Moore
wrote:

Cecil Moore wrote:
It just occurred to me that you and I may be talking
about two different phases.
Continuing: What is the phase shift

When you acknowledge there is some confusion as to which phase is
being talked about. Do you suppose you know enough to tell us which
phase you are talking about?

Funny. In the part you deleated, I said it was the phase
shift between Vfor1 and Vfor2. Your sneaky underhanded
deletion trick is noted.
--
73, Cecil http://www.w5dxp.com

On Sun, 16 Dec 2007 22:14:49 GMT, Cecil Moore
wrote:

Richard Clark wrote:
On Sun, 16 Dec 2007 19:17:48 GMT, Cecil Moore
wrote:

Cecil Moore wrote:
It just occurred to me that you and I may be talking
about two different phases.
Continuing: What is the phase shift

When you acknowledge there is some confusion as to which phase is
being talked about. Do you suppose you know enough to tell us which
phase you are talking about?

Funny. In the part you deleated, I said it was the phase
shift between Vfor1 and Vfor2. Your sneaky underhanded
deletion trick is noted.

You still show signs of confusion. Phase shift in what?

Richard Clark wrote:
You still show signs of confusion. Phase shift in what?

I have explained it twice already. Given the following
4-terminal network impedance discontinuity at '+':

---43.4 deg 600 ohm line---+---10 deg 100 ohm line---open
Vfor1--|--Vfor2

What is the phase shift in the forward voltage at the
impedance discontinuity? The forward voltage on each
side of the impedance discontinuity , '+', is not
equal in magnitude or phase.

We know the stub causes a 90 degree phase shift end to
end. Since there is 43.4 deg phase shift in the 600 ohm
line and 10 deg phase shift in the 10 ohm line, guess
what the phase shift in the forward voltage has to be
at the impedance discontinuity?

Also previously explained, if you prefer - in s-parameter
terms: What is the phase shift between a1 and b2 in the
s-parameter equation:

b2 = s21*a1 + s22*a2
--
73, Cecil http://www.w5dxp.com

On Mon, 17 Dec 2007 15:11:36 GMT, Cecil Moore
wrote:

Richard Clark wrote:
You still show signs of confusion. Phase shift in what?

I have explained it twice already.

You have many explanations that don't actually answer questions. Your
confusion, as evidenced in the sudden realization:
It just occurred to me that you and I may be talking
about two different phases.
doesn't really tell us what phase shift. Perhaps if you could state
what the two are, and which you are using, the rest of us would be
satisified you are no longer confused.

Or maybe everyone is actually on the same page with only one phase
being mentioned, and some alternate phase expression (yet to be
revealed by you) is tormenting your imagination and corrupting your
answers with their math errors.

Richard Clark wrote:
Perhaps if you could state
what the two are, and which you are using, the rest of us would be
satisified you are no longer confused.

I've done that four times now, Richard. I even did
the math for you. I'm not going to waste any further
time on you.
--
73, Cecil http://www.w5dxp.com