Gene Fuller wrote:
As usual you have twisted the question so that you can provide some type
of answer. You still have not answered the original question posed by
Keith.

What was that question? I suspect the question was irrelevant
because Keith didn't understand what phase shift I was talking
about. I also suspect that Keith is beginning to understand
what I am talking about. His silence seems a little strange.
What are you going to do when your realize you are on the
wrong side of the technical argument? Sandbag - like some
others have done and try to obscure the technical facts?

How about an answer from you? What is the phase shift through
the impedance discontinuity between Vfor1 and Vfor2 below?

--43.4 deg 600 ohm line--+--10 deg 100 ohm line--open
Vfor1--|--Vfor2

I doubt that you even know how to solve the problem. Your lack
of an answer will speak volumes.
--
73, Cecil http://www.w5dxp.com

Cecil Moore wrote:
Gene Fuller wrote:
As usual you have twisted the question so that you can provide some
type of answer. You still have not answered the original question
posed by Keith.

What was that question? I suspect the question was irrelevant
because Keith didn't understand what phase shift I was talking
about. I also suspect that Keith is beginning to understand
what I am talking about. His silence seems a little strange.
What are you going to do when your realize you are on the
wrong side of the technical argument? Sandbag - like some
others have done and try to obscure the technical facts?

How about an answer from you? What is the phase shift through
the impedance discontinuity between Vfor1 and Vfor2 below?

--43.4 deg 600 ohm line--+--10 deg 100 ohm line--open
Vfor1--|--Vfor2

I doubt that you even know how to solve the problem. Your lack
of an answer will speak volumes.


Twist, twist, twist.

Do you also open the (black) box to see how Schroedinger's cat is doing?

73,
Gene
W4SZ

Gene Fuller wrote:
Do you also open the (black) box to see how Schroedinger's cat is doing?

I do whatever I need to do to solve the problem, Gene.
If I have to open the box to see if the cat is dead
or alive, that's what I will do. I do not believe in
erecting silly artificial barriers in the quest for
knowledge - and we are not talking about a quantum
physics paradox.

So let me repeat: The phase shifts at the -j567 points
in the two following 1/4WL stubs are not the same.

--43.4 deg 600 ohm line--+--46.6 deg 600 ohm line--open

--43.4 deg 600 ohm line--+--10 deg 100 ohm line--open

The phase shift at '+' in the 1st example is zero.

The phase shift at '+' in the 2nd example is 36.6 deg.
--
73, Cecil http://www.w5dxp.com

On Dec 17, 7:10 pm, Cecil Moore wrote:
Gene Fuller wrote:
As usual you have twisted the question so that you can provide some type
of answer. You still have not answered the original question posed by
Keith.

What was that question? I suspect the question was irrelevant
because Keith didn't understand what phase shift I was talking
about. I also suspect that Keith is beginning to understand
what I am talking about. His silence seems a little strange.

Snow storm - ski
ski - sleep
ISP then breaks DSL - no conectivity
ISP breaks PC IP stack while restoring connectivity - time spent
fixing IP stack
time spent fixing IP stack - employer's work not getting done
employer's work not getting done - reduction of free time
reduction of free time - no r.r.a.a

....Keith