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Tom Donaly wrote:
Keith Dysart wrote: On Dec 4, 9:06 pm, "Tom Donaly" wrote: 50 ohm Shorted line 8.5655 meters long. Frequency = 7 Mhz. 2 volt 50 ohm generator. Current at input = 12.361 milliamps. Current at short = 40 milliamps. Divide the current at the imput of the line by the current at the short and take the arc sine (in radian mode) arc cosine, perhaps? of the result. This is 1.2566. Now take Beta = .14671 and multiply it by the length 8.5655. This also equals 1.2566, which is the angular length of the shorted line. Will someone explain how this works to Cecil? Cecil either knows this, in which case it is unnecessary to explain it, or he does not, in which case it will be impossible. ...Keith Right. I lied. 73, Tom Donaly, KA6RUH To amplify: Arc Cosine is correct. And the comment on Cecil is right on the mark. The same thing can be accomplished, above, using an open stub and measuring the voltage at both ends. All this is just theoretical, though, because line loss will skew the results. Besides, why try to measure current or voltage when all you have to do is measure length and frequency? 73, Tom Donaly, KA6RUH |
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