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On Dec 5, 10:01 am, Cecil Moore wrote:
Keith Dysart wrote: I thought that when you specified 5 and 10 degrees in your problem statement, you meant electrical degrees. That is, the phase shift encountered by the forward travelling wave. That specification is the same for physical and electrical degrees because we are dealing with a single Z0 piece of transmission line. The 100 ohm line is indeed 10 degrees long both physically and electrically. Certainly, the answer was in terms of electrical degrees. That is, the phase shift encountered by the forward travelling wave. You, and others, are going to be surprised to find out the 600 ohm section is only 43 degrees of physical length. Hardly surprised. After all, the same can be achieved with an inductor and/or capacitor which has essentially 0 physical (or electrical) length. How can 43 degrees of 600 ohm line add to 10 degrees of 100 ohm line to equal 90 electrical degrees of stub? Hint: Like I told Roy and Tom years ago, there's a 37 degree phase shift at the impedance discontinuity between the 600 ohm line and the 100 ohm line. 43+37+10 = 90 electrical degrees. So the important take-away is that the system phase shift is NOT equal to the sum of the phase shifts of the components. This then begs the question, is the physical (or electrical) phase shift in the components of much interest? |
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