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Tom Donaly wrote:
O.k., Cecil, you said it, now prove it. There's no requirement for a 90 degree phase shift when you do the math. Are you using the equation for forward and reflected current? If not, you need to do so. The phase shift is not in the standing-wave current. Standing-wave current phase is fixed with respect to the source. Absolutely *nothing* happens to the standing-wave current at the impedance discontinuity. The reflected current is known to be in phase with the forward current at the feedpoint. The forward current is reflected at the tip of the antenna and undergoes a 180 degree phase shift. Something must account for the other 180 degrees or else the feedpoint impedance would not be resistive. I am working on a graphic that illustrates what happens at the impedance discontinuity. Please enlighten us on how the reflected current gets back in phase with the forward current without undergoing a phase shift of 180 degrees in its round-trip path. It is my understanding that the forward phasor rotates in one direction while the reflected phasor rotates in the opposite direction. The key concept there is that a phasor is always rotating. I have waded through the math before but I cannot locate my notes after moving. If you can figure out a reasonable answer to the above question, I will certainly consider it. -- 73, Cecil http://www.w5dxp.com |
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