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![]() "Denny" wrote in message ... On The voltage is indeed real, as i have said. you can measure the 'standing' wave voltage, that has been known for a long time... but the effects are NOT due to power in standing waves.- 1. A standing wave is not 'standing' in time... It phase rotates at the same rate as the excitation frequency... If the phase is rotating then V and I are changing - else Feynman is rotating in his grave... true, it is 'standing' in space. it does not move along the line. your requirement that the 'phase rotates' is another example of why a 'standing' wave is not the same as a real wave. note the point in the standing wave where the voltage is zero. it is always zero, there is no 'phase rotation' at that point. now, if this was a real wave then there would be 'phase rotation' all along the wave in both time and space. 2. It is real because I can measure it with a volt meter and I can extract power from it with a lamp, simultaneously.. you can measure the superimposed voltage of the two real waves, the Vf+Vr at each point on the line. and you can extract power from the superimposed combination of those waves. Also: it will perforate the insulating jacket on the line if the power level is high enough... I used to maintain a herd of 100KW RF generators, and they would blow a hole through the side of a quarter inch thick copper bar in an instant when the load failed in my youthfull ignorance, I thought it was the standing wave RATIO that blew the line, silly me ... yep, silly you. it is the superposition of the forward and reflected waves that can create hot spots in the line. where the moving waves happen to always be in phase you get peak voltage in the standing wave, where they always are out of phase you get no voltage. why do i even bother... time to start plonking more of the ones who refuse to learn and reduce the noise level on here even more. |
#2
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Dave wrote:
"Denny" wrote: 1. A standing wave is not 'standing' in time... It phase rotates at the same rate as the excitation frequency... If the phase is rotating then V and I are changing - else Feynman is rotating in his grave... true, it is 'standing' in space. it does not move along the line. How can such a signal be used to measure the delay through a mobile loading coil? why do i even bother... time to start plonking more of the ones who refuse to learn and reduce the noise level on here even more. What you have to do is overcome their programming - that math models dictate reality, not vice versa. Just keep dripping on that stone - someday it will wear away. -- 73, Cecil http://www.w5dxp.com |
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