| Home |
| Search |
| Today's Posts |
|
#11
|
|||
|
|||
|
Keith Dysart wrote:
The impedance of the Thevenin/Norton equivalent source is not V/I but rather the slope of the line representing the relationship of the voltage to the current. However, after the interference patterns have been established, the reflected waves do not encounter that source impedance. That is why the reflection coefficient seen by the reflected waves is relatively unrelated to the value of resistance in a Thevenin equivalent circuit. You need to complete step 3 of the superposition process to realize exactly what is happening. Reference the irradiance equation from the field of EM wave optics to ascertain the interference levels. What do you have to lose by alleviating your ignorance? Keith, until you take time to understand destructive and constructive interference, you will never understand what is happening inside a source and will be forever confused by your blinders-on-come-hell-or-high-water method of thinking. Optical physicists figured out a couple of centuries ago exactly what you are wrestling with now. Your present problem was already solved before your grandfather was born. -- 73, Cecil http://www.w5dxp.com |
| Thread Tools | Search this Thread |
| Display Modes | |
|
|
Similar Threads
|
||||
| Thread | Forum | |||
| Standing Wave Phase | Antenna | |||
| Standing wave on feeders | Antenna | |||
| Dipole with standing wave - what happens to reflected wave? | Antenna | |||
| Newbie ?: I've Built A Simple 1/4 Wave Dipole for 2 Mtrs. Could IMake a1/2 Wave? | Homebrew | |||
| What is a traveling-wave antenna? | Antenna | |||