Keith Dysart wrote:
When the pulses are not identical, the energy that crosses
the point is exactly sufficient to turn one pulse
into the other. The remainder of the energy must bounce
because it does not cross the mid-point.

All you have proved is that you cannot tell one photon
from another. Your whole charge repulsion argument
falls apart when dealing with photons (which constitute
EM waves). I suggest you study and discover what is
possible with photons and what is not possible. You
seem to be concentrating on the carriers of the waves
rather than the EM waves themselves. Photons do NOT
and cannot bounce off of each other under ordinary
circumstances. You are simply illustrating the limitations
of ignoring the basic physics of the situation and wasting
a lot of time and effort in the process.

I have sat on a cliff overlooking the Pacific Ocean
at Fitzgerald's Marine Reserve north of Santa Cruz, CA
and have seen waves rolling in, reflecting off the beach,
and rolling back out to sea. Those waves pass through
each other as if the other wasn't there. The wave energy
is moving in both directions. The H2O carriers move
hardly at all. You can argue that the energy in the
waves is equal and therefore no average energy is being
transferred, but I still see the waves with people
riding on those waves. I do not see waves bouncing off
of each other although one could, as you have, delude
oneself into creating a mental illusion of such.

When I look out into my back yard, I am seeing reflections.
If there were a thousand people here, they would all be
seeing different reflections all passing through each other.
Photonic waves pass through each other unimpeded. It would
be a weird looking world if they bounced off each other.

In a wire, photons do not bounce off each other. However,
superposition can cause a redistribution of photon energy
at an impedance discontinuity. We call that redistribution
of energy a "reflections".
--
73, Cecil http://www.w5dxp.com