Home |
Search |
Today's Posts |
#11
![]() |
|||
|
|||
![]()
On Jan 15, 6:03*am, Roy Lewallen wrote:
Comments interspersed. . . Keith Dysart wrote: [snip] I take this to imply that you are not happy with the simple "like charge repels"? That's right. Although it's a true statement, I haven't seen any explanation of why it would cause waves to bounce off each other. And Roger suggested the counter-example which may mark the end of the line for "bounce". [snip] I would really appreciate seeing some other possible explanations. How about this: During the initial turn-on of the system, energy does cross the magic node. It's only in the theoretical limiting case of steady state that the energy goes into and out of the node but doesn't cross it. I'll argue that the limiting case can never be reached -- since this whole setup is a perfect construct to begin with. Or, if that's not adequate by itself, what's the problem with energy being trapped between nodes once the line is charged and steady state is reached? I do use the view that the energy is trapped. The difficulty is: What is the mechanism that traps the energy? [snip] With this explanation, P(t) is definitely equal to V(t) time I(t), which I do appreciate. The weakness of this explanation is that it seems to deny that the wave moves energy. And yet before the pulses collide it is easy to observe the energy moving in the line, and if a pulse was not coming in the other direction, there would be no dispute that the energy travelled to the end of the line and was absorbed in the load. Yet when the pulses collide, no energy crosses the middle of the line. Yet energy can be observed travelling in the line before and after the pulses collide. I think the basic problem here is assigning energy to each traveling wave. I agree. And when looking at sinusoidal excitation with "standing waves", it easy not to assign energy. But when looking at pulses, the energy in the pulse seems to jump out at me, and it is hard to ignore. It's taking you into exactly the same morass that Cecil constantly finds himself in. I know. And I definitely do not want to go there. And yet, when I look at pulses, where the energy is clearly visible, I develop some sympathy for Cecil's position. He also concluded some time back that two waves which collide had to reverse direction in order to conserve power, energy, momentum, or something. Energy in the system is conserved; but nowhere is it written that each wave has to have individually conserved energy. [snip] I think you need to take a closer look at what it's getting you out from. I believe the problem lies there. Possibly. [snip] So I am not convinced that it any way goes against established theory. I have not seen established theory attempt an explanation of how the waves can both transport energy as well as not do so when waves of equal energy collide. Perhaps that's because individual waves don't transport energy that has to be conserved? Possibly, but the energy is so clearly visible in the pulses before and after they collide. [snip] The same concern that arises for pulses of equal voltage also occurs for pulses of different voltage. While the mid-point no longer has zero current, the actual current is only the difference of the two currents in the pulses, the charge that crosses is only the difference in the charge between the two pulses, and the power at the mid-point is exactly the power that is needed to move the difference in the energy of the two pulses. Sorry, I'm having trouble following that. Voltage, current, charge, and energy all in two sentences has too high a concept density for me to handle. I'll try with a better description. Consider a line 4 sec long with a matched pulse generator at each end. There is an instantaneous power (p(t)=v(t)*i(t)) meter at the 1, 2 and 3 sec points on the line. Call them the left, middle and right meters. The left generator launches a 1 sec pulse of 100 volts and 2 amps (it is 50 ohm line). This pulse is 200 W and contains 200 J. Simultaneously the right generator launches a 1 sec pulse of 50 volts and 1 amp (50 W and 50 J). At 1 sec the left power meter reads 200 W for 1 sec as 200 J pass, then at 3 sec the right power meter reads 200 W for 1 sec as 200 J pass. It sure looks like the pulse has travelled down the line. At 1 sec the right power meter reads -50 W for 1 sec as 50 J pass, then at 3 sec the left power meter reads -50 W for 1 sec as 50 J pass. It sure looks like this pulse has travelled up the line. The total energy transfer measured by the left meter is 150 J and by the right meter is also 150 J. At second 2, when the pulses collide in the middle, the middle meter reads 150 W for 1 second. So the total energy transfer at the middle is 150 J, which is good since it agrees with the totals in the other meters. So the middle meter reads 150 W. The left meter reads 200 W and later -50 W. And the right meter reads -50 W and later 200 W. So how does a pulse that measurably is 200 W (measured at both right and left meters) move through a point that only measures 150 W. Numerologically it surely does appear that one can superpose powers since 200+(-50) is 150. The main difference between this experiment and one with steady state sinusoidal waves is that in the latter the component forward and reverse waves in are derived by arithmetic from the actual conditions on the line and it is easy to wave the issues away by saying that the component waves have no reality. They are just intermediate results in some arithmetic. This waving away is much harder to do for the pulse case because the pulses can be individually observed as actual conditions on the line. So the challenge is not so starkly obvious as it is when the power at the mid-point is always 0, but P(t) = V(t) * I(t) can still be computed and it will not be sufficient to allow the energy in the two pulses to cross the mid-point (unless one likes superposing power, in which case it will be numerologically correct). No, it'll have to be done without superposing power. Simple calculations clearly show where the power is and where the energy is going, without the need to superpose power or assign power or energy to individual waves. Yes. And I find it easy to obscure for the sinusoid case. But the pulses seem to make it easy to measure and not so easy to refrain from assigning energy and power to the pulses. [snip] But if one conceives waves as also including energy, then it seems that the question 'where does the energy go' is valid and the common explanations do not seem to hold up well. I think you're partially right about that. Partially, because I think there's an underlying assumption that the power in an individual wave has to be conserved. If you do insist on assigning energy to individual traveling waves, I think you have to be willing to deal with the fact that the energy can be swapped and shared among different waves, and stored and returned as well. But then, what is the mechanism that swaps the power between the pulses and changes the direction of the energy flow? Our common analytical techniques deal with E and H fields which we can superpose. In a transmission line, these are closely associated with voltages and currents. They add nicely to make a total with properties we can measure and characterize, and the total can neatly be created as the sum of individual traveling waves from turn on until steady state. It all works very well. Two fields, voltages or currents can easily add to zero simply by being oriented in opposite directions -- and they do, all along a transmission line. But how are the energies they supposedly contain going to add to zero? You'll have to construct a whole new model if you're going to require conservation of energy of individual traveling waves. I agree. And it especially will fail if instead of dealing with the sum of the reflected waves, we try to sum the power of each reflection individually. And yet, the power and energy are so visible when looking at pulses. I'm absolutely certain that after all the work of developing a self-consistent model with all interactions quantitatively and mathematically explained and accounted for, we'll find a testable case where some measurable result will be different from the conventional viewpoint. (Google "ultraviolet catastrophe".) That would then establish the validity of the new model. But I'm just as certain that no such mathematical model will ever be forthcoming. The advantage to the non-interacting traveling wave model is that it so neatly predicts transient phenomena such as TDR and run-up to steady state. I spent a number of years designing TDR circuitry, interfacing with customers, and on several occasions developing and teaching classes on TDR techniques, without ever encountering any phenomena requiring explanations beyond classical traveling wave theory.. So you can understand my reluctance to embrace it based on a problem with energy transfer across a single infinitesimal point in an ideal line. Yes, indeed. Though any (new) explanation would have to remain consistent with the existing body of knowledge which works so well. Either that, or be able to demonstrate where the existing knowledge fails. I'm not holding my breath. I do not expect that to happen. But how is the energy in the left travelling 50 W pulse turned around at the middle to add to the 150 W that is let through to complete the 200 W right travelling pulse? ...Keith |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Standing Wave Phase | Antenna | |||
Standing wave on feeders | Antenna | |||
Dipole with standing wave - what happens to reflected wave? | Antenna | |||
Newbie ?: I've Built A Simple 1/4 Wave Dipole for 2 Mtrs. Could IMake a1/2 Wave? | Homebrew | |||
What is a traveling-wave antenna? | Antenna |