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Old January 22nd 08, 11:16 PM posted to rec.radio.amateur.antenna
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Default Standing-Wave Current vs Traveling-Wave Current WAS rraa LaughRiot continues

Jim Kelley wrote:
Just cut the BS, Cecil. In order to prove your assertion you must first
be able to describe how two co-linear, coherent waves that are 180
degrees out of phase at every point along their path and traveling in
the same direction can under those circumstances at any time produce
measureable energy. In addition, you must be able to measure it. Let
me know when you do.


It is an indirect measurement, Jim. Given the s-parameter
equation, b1 = s11*a1 + s12*a2 = 0, s11 is not zero, a1
is not zero, s12 is not zero, and a2 is not zero. Although
HP cannot measure those quantities either, they tell us
that |s11*a1|^2 is in watts, e.g. 100 watts. They tell us
that |s12*a2|^2 is in watts, e.g. 100 watts. When all energy
is accounted for, it is obvious that those 200 watts are no
longer in the direction of the source but have changed
direction toward the load. This ain't rocket science.

If reflections are eliminated toward the source by wave
cancellation, the reflected energy is redistributed back
toward the load just as explained on the Melles-Groit and
FSU web pages. If it weren't headed for the source in the
first place, they wouldn't say it was "REDISTRIBUTED". If
200 joules/sec disappear toward the source and there are
only two directions in a transmission line, do you really
want to tell us that you can't figure out in which
direction those joules go? Do you need help from my
10 year old grandson?

You clearly fail to understand the process defined by the
wave reflection distributed network model. Until you are
in a position to discredit that model, you are just blowing
smoke.
--
73, Cecil http://www.w5dxp.com
 
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