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"John KD5YI" wrote in
news:Z2srj.1036$qw4.677@trnddc02: I must be doing something wrong. 276log(2)=83 but looks like about 150 on your graph. No? Sorry, that expression should be 276log(2D/d) for a consistent meaning of D and d. (Some people use wire radius and some, diameter... so D here is centre to centre distance, and d is diameter.) Owen |
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