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While working on an energy-based presentation of W7EL's
data from the following web page, I came across an instance where my energy analysis differed from W7EL's results under the "Food for Thought: Forward and Reverse Power" section. Assuming Roy was correct, I attempted to find my error and failed to do so. http://eznec.com/misc/Food_for_thought.pdf **********begin quote********** Zl fPa rPa Pa(tx) Pa(src) Pa(R0) Pa(Rl) frac R0 frac Rl 0 + j0 100 100 0 0 0 0 - - infinite 100 100 0 0 0 0 - - Not only that, but notice the last two cases. Here, the reverse power is a full 100 watts. The source match is 1:1. Yet *none* of this reverse power is dissipated in the source resistance. In fact, no power at all is dissipated in the source resistance. ANY MODEL PRESENTED TO ACCOUNT FOR WHAT HAPPENS TO "FORWARD" AND "REVERSE" POWER AT TRANSMISSION LINE ENDS HAD BETTER GIVE RESULTS THAT AGREE WITH THE ABOVE TABLE. **********end quote********** Unfortunately, my results do not agree. In the line where ZL is zero, i.e. a short-circuit, the dissipation in the source resistance is 400 watts, i.e. all of the forward power and reflected power is dissipated in the source resistor plus an additional 200 watts associated with constructive interference. All 400 watts must be supplied by the source so Pa(src) must also be 400 watts. It should read: Zl fPa rPa Pa(tx) Pa(src) Pa(R0) Pa(Rl) frac R0 frac Rl 0 + j0 100 100 0 400 400 0 1.0 - infinite 100 100 0 0 0 0 - - For the ZL=0 case: Pa(R0) = fPa + rPa + 2*SQRT(fPa*rPa) = 400 watts This is *total constructive interference* as defined by Hecht in "Optics". For the ZL=infinite case: Pa(R0) = fPa + rPa - 2*SQRT(fPa*rPa) = 0 watts This is *total destructive interference* as defined by Hecht in "Optics". Since Roy doesn't read my postings or emails, could someone please pass this information on to him. -- 73, Cecil http://www.w5dxp.com |
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