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March 6th 08, 05:12 PM
posted to rec.radio.amateur.antenna
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The Rest of the Story
Keith Dysart wrote:
So using the same 12.5 ohm example, X.inst = 50 + 50 cos(2wt) Y.inst = 18 + 18 cos(2wt) X.inst + Y.inst = 68 + 68 cos(2wt) Where do you take into account that the forward wave is 90 degrees out of phase with the reflected wave? Z.inst = 68 + 68 cos(2wt - 61.9degrees) Where does the 61.9 degrees come from? -- 73, Cecil http://www.w5dxp.com |
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