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#1
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Keith Dysart wrote:
If the instantaneous power is not dissipated in the source resistor, then neither is the average of the instantaneous power. Let's see what happens when we use that same logic with my AC wall sockets: If the instantaneous AC voltage at my QTH is ever non-zero, then the average voltage cannot be zero. Agree? Disagree? -- 73, Cecil http://www.w5dxp.com |
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#2
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On Mar 13, 7:02*pm, Cecil Moore wrote:
Keith Dysart wrote: If the instantaneous power is not dissipated in the source resistor, then neither is the average of the instantaneous power. Let's see what happens when we use that same logic with my AC wall sockets: If the instantaneous AC voltage at my QTH is ever non-zero, then the average voltage cannot be zero. Agree? Disagree? Agree with what? That it is the same logic? You will have to expand on your question. Regardless, the average voltage is zero. ...Keith |
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#3
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Keith Dysart wrote:
Regardless, the average voltage is zero. No, that contradicts what you said before which was, if it ever wasn't zero instantaneously, it cannot possibly average out to zero. I'm sorry, Keith. Your assertions have gotten just as irrational as my 96 year old aunt's. -- 73, Cecil http://www.w5dxp.com |
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#4
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On Mar 13, 10:33*pm, Cecil Moore wrote:
Keith Dysart wrote: Regardless, the average voltage is zero. No, that contradicts what you said before which was, if it ever wasn't zero instantaneously, it cannot possibly average out to zero. If you could kindly point out which of my previous writings you misinterpreted to be say this, I will gladly correct your misunderstanding. ...Keith |
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#5
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Keith Dysart wrote:
On Mar 13, 7:02 pm, Cecil Moore wrote: Keith Dysart wrote: If the instantaneous power is not dissipated in the source resistor, then neither is the average of the instantaneous power. Let's see what happens when we use that same logic with my AC wall sockets: If the instantaneous AC voltage at my QTH is ever non-zero, then the average voltage cannot be zero. Agree? Disagree? Agree with what? That it is the same logic? You will have to expand on your question. Regardless, the average voltage is zero. ...Keith Keith; Put your fingers across the bare wires and then tell me the results, if you are still around that is. ;^) Dave N |
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#6
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On Mar 13, 11:48*pm, "David G. Nagel"
wrote: Keith Dysart wrote: On Mar 13, 7:02 pm, Cecil Moore wrote: Keith Dysart wrote: If the instantaneous power is not dissipated in the source resistor, then neither is the average of the instantaneous power. Let's see what happens when we use that same logic with my AC wall sockets: If the instantaneous AC voltage at my QTH is ever non-zero, then the average voltage cannot be zero. Agree? Disagree? Agree with what? That it is the same logic? You will have to expand on your question. Regardless, the average voltage is zero. ...Keith Keith; Put your fingers across the bare wires and then tell me the results, if you are still around that is. ;^) Dave N- Hide quoted text - - Show quoted text - The average of a sine wave is 0. Positive half the time, negative half the time, sums to 0. Perhaps you are confusing average with root-mean-square? ...Keith |
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