Keith Dysart wrote:
On Mar 14, 7:59 am, Cecil Moore wrote:
P(t).reactance = [V(t).reactance][I(t).reactance]
Where is that term in your equations?

It is unnecessary. But if you believe me wrong, show me
where it goes, compute the values, and show how it
accounts for the energy that is not dissipated in the
source resistor.

It is unnecessary to account for all of the instantaneous
power???? Your problem is greater than just a simple
misunderstanding of the laws of physics by which we must
all abide.

The DC energy is stored in your vehicle's battery until
it is needed to start your vehicle. That delay between
stored energy and needed energy is related to the
(undefined) wavelength. Think about it.

In an AC circuit, the reactance has no say as to when
to store the energy and when it is delivered back to the
system. It is also related to wavelength which is defined.

When the source voltage is zero at its zero crossing
point/time, the instantaneous power dissipation in
the source resistor is NOT zero! Doesn't that give
you pause to wonder where the instantaneous power
is coming from when the instantaneous power delivered
by the source is zero???? Why do you ignore that power
and try to sweep it under the rug?

You are making the mistakes that your EE 201 professor
warned you not to make. You are superposing powers,
something that all the gurus on this newsgroup will
condemn. Until you learn not to superpose powers, you
will remain forever ignorant. Richard C. made the same
mistake when he declared that the reflections from non-
reflective thin-film coatings on glass are "brighter
than the surface of the sun". If one ignores the laws
of physics, anything is possible.

There is a condition where it is valid to superpose
powers. That is when (V1^2 + V2^2) = (V1 + V2)^2
You have obviously not satisfied that condition and
are paying for your violations of those laws of physics.
Until you give up on your superposition of powers, I
cannot help you.
--
73, Cecil http://www.w5dxp.com