| Home |
| Search |
| Today's Posts |
|
#11
|
|||
|
|||
|
On Mar 21, 5:03*pm, Roger Sparks wrote:
On Fri, 21 Mar 2008 19:43:12 GMT Cecil Moore wrote: Roger Sparks wrote: Cecil Moore wrote: Roger, do you understand why EE201 professors admonish their students not to try to superpose powers? No, I really don't. * It is because (V1 + V2)^2 usually doesn't equal V1^2+V2^2 because of interference. Keith's addition of powers without taking interference into account is exactly the mistake that the EE201 professors were talking about. One cannot validly just willy-nilly add powers. It is an ignorant/sophomoric thing to do. If we add two one watt coherent waves, do we get a two watt wave? Only in a very special case. For the great majority of cases, we do *NOT* get a two watt wave. In fact, the resultant wave can be anywhere between zero watts and four watts. The concepts behind Keith's calculations are invalid. If you are also trying to willy-nilly add powers associated with coherent waves, your calculations are also invalid. -- 73, Cecil *http://www.w5dxp.com OK, yes, I agree. *It is OK to add powers when you are adding the power used by light bulbs. *It is not OK to willy nilly multiply the voltage or current by the number of bulbs to learn the power used. *You must carefully consider the circuit that connects the bulbs before selecting the proper method of calculating power, especially the possibility that the bulbs may be connected to phased power as in 3 phase or in traveling waves. My analysis used voltages, currents and impedances to compute all the voltages and currents within the circuit. Some were derived using superposition of voltages and currents but most were derived using basic circuit theory (E=IR, Ztot=Z1+Z2, etc.) Having done that, the powers for the three components (the voltage source, resistor, and entrance to the transmission line) in the circuit were computed. These powers were not derived using superposition but by multiplying the current through the component by the voltage across it. This is universally accepted as a valid operation. Having the power functions for each of the component, we can then turn to the conservation of energy principle: The energy in a closed system is conserved. This is the basis for the equation Ps(t) = Prs(t) + Pg(t) This equation says that for the system under consideration (Fig 1-1), the energy delivered by the source is equal to the energy dissipated in the resistor plus the energy delivered to the line. This is extremely basic and satisfies the conservation of energy principle. This is not superposition and any inclusion of cos(theta) terms would be incorrect. The equation Pg(t) = Pf.g(t) + Pr.g(t) is more interesting. The basis for this is superposition. The forward and reverse voltage and current are superposed to derive the actual voltage and current. It would seem invalid to also sum the powers. To me it was a complete surprise that summing the voltages produces the correct total voltages and, at the same time, summing the powers (which are a squared function of the voltage) also produce the correct result. But by starting with the equations used to derive forward and reverse voltage and current, it can be easily shown with appropriate substitution that Ptot is always equal to Pforward + Preverse (Or Pf - Pr if you use the other convention for the direction of the energy flow)s. It simply falls out from the way that Vf and Vr are derived from Vactual and Iactual. So Pg(t) = Pf.g(t) + Pr.g(t) is always true. For any arbitrary waveforms. Inclusion of cos(theta) terms would be incorrect. ...Keith |
| Thread Tools | Search this Thread |
| Display Modes | |
|
|
Similar Threads
|
||||
| Thread | Forum | |||
| Now for the rest of the story! | General | |||
| Now for the rest of the story! | Policy | |||
| Now for the rest of the story! | General | |||
| Now for the rest of the story! | Policy | |||
| WTD: Paul Harvey Rest of the Story broadcasts from Sep 1 thru 6 | Broadcasting | |||