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On Sun, 23 Mar 2008 19:57:24 GMT
Cecil Moore wrote: Roger Sparks wrote: (the reflected voltage should ADD to the source voltage) If you graph the two voltages you will find that half the time the reflected voltage adds to the source voltage and half the time the reflected voltage subtracts from the source voltage. Both are true half the time. You can point out either case on the graph. That's why the average interference term is zero for this special case and therefore why 100% of the average reflected power is dissipated in the source resistor for this special case. You might wonder why I would consider this alternative. If the destructive interference included a 90 degree delay, how would I know whether the 30v was the delayed voltage or exactly in phase with the source? By looking at the graphs? Where is the power stored for 90 degrees? In the equivalent reactance of the transmission line. That's what reactances do in AC circuits. They store energy and deliver it back to the system some time later. -- 73, Cecil http://www.w5dxp.com I did not use a graph, but created a spreadsheet that calculated Vrs for the short circuit, 45 degree long line. It shows the 90 degree transfer of power that you described. I posted the spreadsheet in PDF format at http://www.fairpoint.net/~rsparks/Reflect_short.pdf. To me, this shows that my traveling wave analysis on an instant basis is not correct because the energy can not be located precisely on a degree-by-degree scale. Yes, it is correct on the average over 360 degrees, but not instantaneously. We are missing something. Central to traveling waves is the assumption that the wave is not compressable. The energy is assumed to flow in a consistantly predictable mannor that is linear and described by a sine wave. That assumption is violated when energy is delayed for reasons other than distance of travel, which is demonstrated in this example. I am not ready to suggest a cure for my traveling wave analysis. I only see that it does not work to my expectations. Thanks for providing the examples and comments. -- 73, Roger, W7WKB |
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#2
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Roger Sparks wrote:
To me, this shows that my traveling wave analysis on an instant basis is not correct because the energy can not be located precisely on a degree-by-degree scale. Yes, it is correct on the average over 360 degrees, but not instantaneously. We are missing something. What you are missing is the localized interference patterns within the individual cycles. The interference changes from destructive to constructive every 90 degrees. For every negative (destructive) interference term, there is an equal magnitude positive (constructive) interference term 90 degrees later. These, of course, average out to zero. Exactly the same thing happens when a coil or capacitor is present in a circuit. When the instantaneous voltage of a source is zero and thus delivering zero instantaneous power, a circuit capacitor is delivering energy back into the circuit that can be dissipated by a resistor. Central to traveling waves is the assumption that the wave is not compressable. The energy is assumed to flow in a consistantly predictable mannor that is linear and described by a sine wave. That assumption is violated when energy is delayed for reasons other than distance of travel, which is demonstrated in this example. Power is certainly compressible. One can stuff 100 amphere- hours into a battery in 2 hours and take 20 hours to remove it. Why can't 60 watts of instantaneous power be stuffed into a reactance and be removed 90 degrees later? I am not ready to suggest a cure for my traveling wave analysis. I only see that it does not work to my expectations. Your expectations seem to be based on a conservation of power principle which doesn't exist. There is no violation of linearity if the energy dissipation is delayed by 90 degrees or by ten billion years. I don't recall any published material where anyone tried to explain where the instantaneous energy goes while at the same time denying the possibility of interference. -- 73, Cecil http://www.w5dxp.com |
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#3
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On Mon, 24 Mar 2008 16:15:21 GMT
Cecil Moore wrote: Roger Sparks wrote: To me, this shows that my traveling wave analysis on an instant basis is not correct because the energy can not be located precisely on a degree-by-degree scale. Yes, it is correct on the average over 360 degrees, but not instantaneously. We are missing something. What you are missing is the localized interference patterns within the individual cycles. The interference changes from destructive to constructive every 90 degrees. For every negative (destructive) interference term, there is an equal magnitude positive (constructive) interference term 90 degrees later. These, of course, average out to zero. Exactly the same thing happens when a coil or capacitor is present in a circuit. When the instantaneous voltage of a source is zero and thus delivering zero instantaneous power, a circuit capacitor is delivering energy back into the circuit that can be dissipated by a resistor. Central to traveling waves is the assumption that the wave is not compressable. The energy is assumed to flow in a consistantly predictable mannor that is linear and described by a sine wave. That assumption is violated when energy is delayed for reasons other than distance of travel, which is demonstrated in this example. Power is certainly compressible. One can stuff 100 amphere- hours into a battery in 2 hours and take 20 hours to remove it. Why can't 60 watts of instantaneous power be stuffed into a reactance and be removed 90 degrees later? I am not ready to suggest a cure for my traveling wave analysis. I only see that it does not work to my expectations. Your expectations seem to be based on a conservation of power principle which doesn't exist. There is no violation of linearity if the energy dissipation is delayed by 90 degrees or by ten billion years. I don't recall any published material where anyone tried to explain where the instantaneous energy goes while at the same time denying the possibility of interference. -- 73, Cecil http://www.w5dxp.com Hi Cecil, I feel better today. I think I have connected the dots and now have the spreadsheet showing that we really can use the traveling waves to solve the shorted transmission line problem on a instantaneous basis without the delay of energy into the next half cycle. Here is a link to the new spreadsheet. http://www.fairpoint.net/~rsparks/Sm...Reflection.pdf I used the logic and formula presented in my post "Subject: The Rest of the Story Date: Thu, 20 Mar 2008 10:07:44 -0700" You called it interference. Keith used your power equation and called the interference term a mathematical correction. It looks to me like the correction can be avoided by choosing the correct sin wave offset. Ultimately, the waves can be resolved into one more powerful wave carrying the power described by Keith's "false power" equation. This is demonstrated in a spreadsheet found at http://www.fairpoint.net/~rsparks/Re...em%20Power.pdf You need to take a look at the spreadsheets. I think they support the theory that we can track the power on an instant basis using traveling waves. -- 73, Roger, W7WKB |
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#4
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Roger Sparks wrote:
You need to take a look at the spreadsheets. Roger, in a nutshell, what is the bottom line? -- 73, Cecil http://www.w5dxp.com |
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#5
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Cecil Moore wrote:
Roger Sparks wrote: You need to take a look at the spreadsheets. Roger, in a nutshell, what is the bottom line? The bottom line in a nutshell? I'll try. First, I added a note to both spreadsheets indicating that zero degrees is CURRENT zero degrees. This because the source turns out to be reactive, with current peak 45 degrees from voltage peak. http://www.fairpoint.net/~rsparks/Sm...Reflection.pdf The spreadsheet addresses the following issues: Does the traveling wave carry power? Yes. The spreadsheet was built assuming that power is carried by traveling waves. Because the resulting wave form and powers seem correct, the underlaying assumption seems correct. Is power conserved on the transmission line, meaning, can the energy contained in power be conserved and located over time on the transmission line? Yes, the spreadsheet was built assuming that power could be conserved and traced over time so the underlaying assumption seems correct. Does interference occur in this example? The spreadsheet was built assuming that voltage and currents from superpose in a manner consistent with constructive and destructive interference, so the underlaying assumption seems correct. Is power stored in the reactive component for release in later in the cycle or during the next half cycle? Yes, power is stored on the transmission line during the time it takes for power to enter the line, travel to the end and return. The time of wave travel on the transmission line is related to the value of the reactive component. Does the direction of wave travel affect the measurement of voltage and the application of power to a device? Yes. A wave loses energy (and therefore voltage) as it travels through a resistance. As a result, power from the prime source is ALWAYS applied across the sum of the resistance from the resistor AND transmission line. The spreadsheet was built using this assumption and seems correct. (At times during the cycle, the forward and reflected waves oppose, resulting in very little current through the resistor. During those times, the power applied to the transmission line is much HIGHER because the reflected wave reflects from the load and source, and merges/adds to the forward wave from the source.) Is the power interference equation Ptot = P1 + P2 + 2*SQRT(P1*P2)cos(theta) valid? The equation was not reviewed on this spreadsheet. The bottom line, but maybe not in a nutshell. 73, Roger, W7WKB |
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#6
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Roger Sparks wrote:
The bottom line in a nutshell? I'll try. Thanks Roger, good stuff and much appreciated. My digesting of your spread sheets is about to be interrupted by surgery. During those times, the power applied to the transmission line is much HIGHER because the reflected wave reflects from the load and source, and merges/adds to the forward wave from the source.) May I suggest that you use the word "redistributed" instead of "reflected" as does the FSU web page at: http://micro.magnet.fsu.edu/primer/j...ons/index.html For the purposes of this discussion, I would suggest that the word "reflection" be reserved for something that happens to a single wave. When two waves are superposed, energy can be redistributed but technically it is not an ordinary reflection. I once used the word "reflection" to describe both phenomena and it confused people. Now I am careful to call the reversal of energy flow due to superposition a "redistribution" instead of a "reflection". For instance, the multi-colored patterns seen when a thin film of oil is on top of a puddle of water is not an ordinary reflection but a combination of multiple reflections and interference. In addition, the reflection coefficient seen by the reflected wave in our examples is 0.0 since the source impedance equals the characteristic impedance of the transmission line. There are no ordinary reflections when the reflection coefficient is zero. -- 73, Cecil http://www.w5dxp.com |
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#7
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On Thu, 27 Mar 2008 11:49:03 GMT
Cecil Moore wrote: Roger Sparks wrote: The bottom line in a nutshell? I'll try. Thanks Roger, good stuff and much appreciated. My digesting of your spread sheets is about to be interrupted by surgery. Thanks for the kind words. Sorry to hear about your surgery. I hope it goes well and you have a quick recovery. During those times, the power applied to the transmission line is much HIGHER because the reflected wave reflects from the load and source, and merges/adds to the forward wave from the source.) May I suggest that you use the word "redistributed" instead of "reflected" as does the FSU web page at: http://micro.magnet.fsu.edu/primer/j...ons/index.html Clip I think "redistributed" would be the word if the discontinuity included a resistance. "Reflection" is the historical word for wave reversal and implies a "mirror image", which is not the same as the forward image. I hope the surgery does not take you away from the discussion for long. -- 73, Roger, W7WKB |
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#8
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On Mar 27, 2:06 am, Roger Sparks wrote:
Cecil Moore wrote: Roger Sparks wrote: You need to take a look at the spreadsheets. Roger, in a nutshell, what is the bottom line? The bottom line in a nutshell? I'll try. First, I added a note to both spreadsheets indicating that zero degrees is CURRENT zero degrees. This because the source turns out to be reactive, with current peak 45 degrees from voltage peak. http://www.fairpoint.net/~rsparks/Sm...Reflection.pdf I was not able to discern the derivation of the various equations though the data in the columns looked somewhat reasonable. Were the equation really based on the opening paragraph statement of 100 Vrms, or is it scaled to a different source voltage. The sin functions have an amplituted of 100, which suggests a source of 200 volts or Vrms of 141.4 volts. The spreadsheet addresses the following issues: Does the traveling wave carry power? Yes. The spreadsheet was built assuming that power is carried by traveling waves. Because the resulting wave form and powers seem correct, the underlaying assumption seems correct. It was not obvious which columns were used to draw this correlation. However, even if this experiment is consistent with the hypothesis it only takes one experiment which is not to disprove the hypothesis. Is power conserved on the transmission line, meaning, can the energy contained in power be conserved and located over time on the transmission line? Yes, the spreadsheet was built assuming that power could be conserved and traced over time so the underlaying assumption seems correct. Does interference occur in this example? The spreadsheet was built assuming that voltage and currents from superpose in a manner consistent with constructive and destructive interference, so the underlaying assumption seems correct. Is power stored in the reactive component for release in later in the cycle or during the next half cycle? Yes, power is stored on the transmission line during the time it takes for power to enter the line, travel to the end and return. The time of wave travel on the transmission line is related to the value of the reactive component. Does the direction of wave travel affect the measurement of voltage and the application of power to a device? Yes. A wave loses energy (and therefore voltage) as it travels through a resistance. As a result, power from the prime source is ALWAYS applied across the sum of the resistance from the resistor AND transmission line. I am not sure that I would describe this as the wave losing energy, but rather as the voltage dividing between the two impedances. If the source resistance was replaced by another transmission, which could easily be set to provide a 50 ohm impedance, would you still describe it as the wave losing energy? The spreadsheet was built using this assumption and seems correct. (At times during the cycle, the forward and reflected waves oppose, resulting in very little current through the resistor. During those times, the power applied to the transmission line is much HIGHER because the reflected wave reflects from the load and source, and merges/adds to the forward wave from the source.) I am not convinced. When there is very little current through the resistor, there is also very little current into the transmission line. This suggests to me that the power applied to the transmission line is low. ....Keith |
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#9
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On Sat, 29 Mar 2008 12:45:48 -0700 (PDT)
Keith Dysart wrote: On Mar 27, 2:06 am, Roger Sparks wrote: Cecil Moore wrote: Roger Sparks wrote: You need to take a look at the spreadsheets. Roger, in a nutshell, what is the bottom line? The bottom line in a nutshell? I'll try. First, I added a note to both spreadsheets indicating that zero degrees is CURRENT zero degrees. This because the source turns out to be reactive, with current peak 45 degrees from voltage peak. http://www.fairpoint.net/~rsparks/Sm...Reflection.pdf I was not able to discern the derivation of the various equations though the data in the columns looked somewhat reasonable. Were the equation really based on the opening paragraph statement of 100 Vrms, or is it scaled to a different source voltage. The sin functions have an amplituted of 100, which suggests a source of 200 volts or Vrms of 141.4 volts. I simplified and changed the phase for the equation in column C from '100sin(wt-90) + 100sin(wt-180)' to '100sin(wt+90) + 100sin(-wt)' so that the total voltage in column D better matches with the voltages from my formula in column G. The equation for column B is just the sine wave for the base wave, showing the voltage resulting to the source resistor from the peak current. The equation in column C is the same (from current) but recognizes that current from the reflected wave will cancel the current from the forward wave coming through Rs. The two waves are traveling in opposite directions so one angle must be labeled with a negative sign so that it will rotate in the opposite direction. In column C, the first term is the reflected wave and the second term is the base wave. My formula, displayed in column G, uses the applied voltage of 141.4 volts. I thought it would be easier to see how the spreadsheet was built using current to find the voltages. You can see how the results of column D match well with those from column G. The spreadsheet addresses the following issues: Does the traveling wave carry power? Yes. The spreadsheet was built assuming that power is carried by traveling waves. Because the resulting wave form and powers seem correct, the underlaying assumption seems correct. It was not obvious which columns were used to draw this correlation. Column E and column F display power. Column F recognizes that if 100 watts is applied continueously (on the average) over an entire 360 degree cycle, the final power applied over time would be 360 * 100 = 36000 watt-degrees. Part of the power comes from the reflection, part comes directly. Obviously, interference is very much at work in this example. However, even if this experiment is consistent with the hypothesis it only takes one experiment which is not to disprove the hypothesis. True! Is power conserved on the transmission line, meaning, can the energy contained in power be conserved and located over time on the transmission line? Yes, the spreadsheet was built assuming that power could be conserved and traced over time so the underlaying assumption seems correct. Does interference occur in this example? The spreadsheet was built assuming that voltage and currents from superpose in a manner consistent with constructive and destructive interference, so the underlaying assumption seems correct. Is power stored in the reactive component for release in later in the cycle or during the next half cycle? Yes, power is stored on the transmission line during the time it takes for power to enter the line, travel to the end and return. The time of wave travel on the transmission line is related to the value of the reactive component. Does the direction of wave travel affect the measurement of voltage and the application of power to a device? Yes. A wave loses energy (and therefore voltage) as it travels through a resistance. As a result, power from the prime source is ALWAYS applied across the sum of the resistance from the resistor AND transmission line. I am not sure that I would describe this as the wave losing energy, but rather as the voltage dividing between the two impedances. If the source resistance was replaced by another transmission, which could easily be set to provide a 50 ohm impedance, would you still describe it as the wave losing energy? It should be OK to think of the voltage dividing between two impedances. The important thing is to consider how the reflected voltage sums with the forward voltage where it is measured. Because the two waves are traveling in opposite directions, the measured voltage is not the voltage applied to either Rs or the transmission line. This is why columns B and C must be added to find the total voltage across Rs. The spreadsheet was built using this assumption and seems correct. (At times during the cycle, the forward and reflected waves oppose, resulting in very little current through the resistor. During those times, the power applied to the transmission line is much HIGHER because the reflected wave reflects from the load and source, and merges/adds to the forward wave from the source.) I am not convinced. When there is very little current through the resistor, there is also very little current into the transmission line. This suggests to me that the power applied to the transmission line is low. I don't follow you here. Right, power into the transmission line is low when the current in is low, and it is high when the current is high. It is clear that peak current and peak voltage do not occur at the same time except when measured across the resistor in column D. ...Keith This is just one example, but it seems like the power is accounted for here. We need another example where power can NOT be accounted for. -- 73, Roger, W7WKB |
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