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On Apr 1, 8:08 am, Cecil Moore wrote:
Keith Dysart wrote: Cecil Moore wrote: If the average interference is zero, the average reflected power is dissipated in the source resistor. All of your unethical lies, innuendo, and hand-waving will not change that fact of physics. More precisely, the average value of the imputed reflected power is numerically equal to the increase in the average power dissipated in the source resistor. More precisely, at the *exact* time of arrival of the reflected wave, the average power dissipated in the source resistor increases by *exactly* the magnitude of the average reflected power. Do you think that is just a coincidence? Not quite, but close. And averages can not change instantly. But your phraseology suggests another way to approach the problem. Let us consider what happens just after the arrival of the reflected wave. For computational convenience, we'll use a frequency of 1/360 hertz so that 1 degree of the wave is one second long. The reflected wave arrives at 90 seconds (or 90 degrees) after the source is turned on. If the line is terminated in 50 ohms, then no reflection arrives and during the one second between degree 90 and degree 91, the source resistor dissipates 0.01523 J of energy. The line also receives 0.01523 J of energy and the source provides 0.03046 J. Esource.50[90..91] = 0.03046 J Ers.50[90..91] = 0.01523 J Eline.50[90..91] = 0.01523 J Esource = Ers + Eline as expected. Efor = Eline since Eref is 0. Now let us examine the case with a 12.5 ohm load and a non-zero reflected wave. During the one second between degree 90 and degree 91, the source resistor dissipation with no reflection is still 0.01523 J and the imputed reflected wave provides 99.98477 J for a total of 100.00000 J. But the source resistor actually absorbs 98.25503 J in this interval. Ooooopppps. It does not add up. So the dissipation in the source resistor went up, but not enough to account for all of the imputed energy in the reflected wave. This does not satisfy conservation of energy, which should be sufficient to kill the hypothesis. But Esource = Ers + Eline as expected. Esource.12.5[90..91] = -1.71451 J Ers.12.5[90..91] = 98.25503 J Eline.12.5[90..91] = -99.96954 J Note that in the interval 90 to 91 degrees, the source is absorbing energy. This is quite different than what happens when there is no reflected wave. You said earlier "Do you think that is just a coincidence?" It is to be expected that the dissipation in the source resistor changed; after all, the load conditions changed. But it is mere happenstance that the average of the increase in the dissipation is the same as the average power imputed to the reflected wave; an ideosyncratic effect of the selection of component values. It is not obvious why you reject this more precise, less misleading description. Why do you use such unfair ill-willed debating techniques based on innuendo and not on facts in evidence? IMO, our two statements above say the same thing with mine being the more precise and detailed. I don't reject yours - I just prefer mine. Authors often do have difficulties detecting when their words mislead. Excellent authors, and there are not many, use the feedback from their readers to adjust their wording to eliminate misleading prose. If the source of the increased dissipation in the source resistor is not the reflected energy, exactly where did that "extra" energy come from at the exact time of arrival of the reflected wave? Exactly. This is what calls into question the notion that the reflected wave is transporting energy. This imputed energy can not be accounted for. Now the energy that can be accounted for is the energy that flows in or out of the line. This energy, along with the energy dissipated in the source resistor will *always*, no matter how you slice and dice it, be equal to the energy being delivered by the source; completely satisfying the requirements of conservation of energy. The best that can be said for the imputed power in the reflected wave is that when it is subtracted from the imputed power in the forward wave, the result will be the actual energy flow in the line. But this is just a tautology; a result from the very definition of Vforward and Vreflected. Hint: Since the only other source of energy in the entire system is the reflected wave, any additional source would violate the conservation of energy principle. Alternatively, since it turns out that trying to use this imputed power to calculate the power dissipated in the source resistor results in a violation of conservation of energy, this energy flow imputed to the reflected wave is a figment. The only thing that is real is the total energy flow. Now you have asked repeatedly about the reflection from the mirror because you are sure that this is proof of the energy in the reflected wave. The energy in the light entering your eye is the total energy; it is not imputed energy of a wave that is a partial contributor to the total. If the eye were also a source, such that there was a Pfor to go along with Pref, then your question would align with the situation under discussion. But when the energy flow is only in one direction, that flow is a total flow and it definitely contains energy. To recap, it is when a total flow is broken into multiple non-zero constituent flows that energy flow imputed to the constituents is a dubious concept. ....Keith |
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