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Old April 6th 08, 12:02 PM posted to rec.radio.amateur.antenna
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First recorded activity by RadioBanter: Mar 2008
Posts: 6
Default The Rest of the Story

Lets put the 'Rest of the Story' to bed before it becomes 'The Never Ending
Story' or are we too late already.
Mike. VK6MO
"Cecil Moore" wrote in message
. ..
Roger Sparks wrote:
Pfor1 + Pref2 + P.Rs = Pfor2 + Pref1 (all average)


Sorry for the obvious typo. The sign of P.Rs should
have been minus.

This equation seems to assume that the power to the resistor is zero.


No, these are really basic concepts. The energy flow away
from a junction is equal to the energy flow into the
junction minus the dissipation in the junction.

(Pfor1 + Pref2) is the energy flow into the junction

P.Rs is the dissipation in Rs

(Pfor2 + Pref1) is the energy flow away from the junction.

(Pfor1 + Pref2) - P.Rs = (Pfor2 + Pref1) or

(Pfor1 + Pref2) = (Pfor2 + Pref1) + P.Rs

There will never be one answer for your equation, unless, as you suggest,
a1 and a2 are given.


a1 and a2 *are* given - at least indirectly so they can be
calculated. Since we know Vs, Rs, and ZL, and given the two
1WL feedlines, we can easily calculate a1 and a2.
--
73, Cecil http://www.w5dxp.com



 
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