Roger Sparks wrote:
While it can be argued that the ideal voltage source would
have zero internal resistance, that argument does not address
the fact that power flowing in the reverse direction (into the
source, against the source supplied voltage) delivers power
into the source.

I thought I had already addressed that topic when I added the
one-wavelength of transmission line to the example in between
the source and source resistance.

But here's an example that may allow better tracking
of the energy flow. Let's modify my Part 1, Fig. 1-1
to add a 50 ohm circulator and load to the ground
leg of the source. Everything else remains the same.

Gnd--1---2---Vs---Rs-----45 deg 50 ohm----------RL
\ /
3
|
50 ohms
|
GND

How much power is dissipated in the circulator
resistor?

How much power does the source have to supply to
maintain 50 watts of forward power on the transmission
line?

Does this example answer your questions?
--
73, Cecil http://www.w5dxp.com