Roger Sparks wrote:
Pf1-- 50 ohm Pf2=50w--
+----x-----/\/\/\/\-------45 deg 50 ohm-----+
| --Pr1 Rs --Pr2=50w |
| 100w |
Vs=100v |
| |
Gnd--------------------------Braid------------+

The coax is shorted at the end, and Gnd is 45
degrees away from the short.

What is the impedance of the voltage delivered from Vs before the wave encounters the resistor Rs?

Assume that Rs is 100% of the source impedance.

What reflection characteristics should we assume for the voltage source Vs?

Assuming that Rs is 100% of the source impedance
should answer that question.
--
73, Cecil http://www.w5dxp.com

On Apr 23, 12:03*pm, Cecil Moore wrote:
Roger Sparks wrote:
* * * Pf1-- * 50 ohm * * Pf2=50w--
* *+----x-----/\/\/\/\-------45 deg 50 ohm-----+
* *| *--Pr1 * * Rs * * * --Pr2=50w * * * * * |
* *| * * * * * *100w * * * * * * * * * * * * * |
*Vs=100v * * * * * * * * * * * * * * * * * * * |
* *| * * * * * * * * * * * * * * * * * * * * * |
*Gnd--------------------------Braid------------+

The coax is shorted at the end, and Gnd is 45
degrees away from the short.

What is the impedance of the voltage delivered from Vs before the wave encounters the resistor Rs?

Assume that Rs is 100% of the source impedance.

What reflection characteristics should we assume for the voltage source Vs?

Assuming that Rs is 100% of the source impedance
should answer that question.

Is this a standard ideal voltage source which provides energy
to the circuit when the product of its voltage and current is
positive and removes energy from the circuit when the product
of its voltage and current is negative?

Or have you assigned it some other non-standard definition?

...Keith

Keith Dysart wrote:
Is this a standard ideal voltage source ...

Let's save that discussion for later by dropping
Vs out of the example. The specific characteristics
of the source need not be known for the following
subset problem which, I believe, is the source of
our disagreement, having nothing to do with Vs.
In fact, Vs can be located one wavelength away from
Rs and steady-state conditions will be the same.
Let's take a close look at what is happening only
on each side of Rs in this previous example.

100v Vg
Gnd---Vs--x--Rs--+----45deg-50ohm---------short

The following are given:

A 100% 50 ohm environment by definition.
Reference Voltage = 100v RMS at point 'x'
Rho = 0.4472 @ 63.4 deg at point 'x'

Rho^2 = 0.2 and an ideal 50 ohm directional wattmeter
will provide the following indications.

100v Rs=50ohms Vg
------------x---/\/\/\/\/---+--------------
Pf1=125w-- Prs=100w Pf2=50w--
--Pr1=25w --Pr2=50w

These are the energy components that you say do not
balance. But I didn't see Pf1(t) or Pr1(t) in any
of your previous equations. I suggest you will
discover that the destructive interference on one
side of Rs is exactly balanced by the constructive
interference on the other side.
--
73, Cecil http://www.w5dxp.com