Gene Fuller wrote:
If you read what I wrote you will note that I said any purported waves
traveling in the reverse direction have zero amplitude. In other words
they do not exist.

So you disagree with "Wave Mechanics of Transmission Lines, Part 3:"
by S. R. Best, QEX Nov/Dec 2001?

Your statement denies reality. In the following system, 178 joules/sec
are rejected by the load and thus flow back toward the source. You can
measure it with a wattmeter. The very first thing you need to prove is
that standing waves can exist without two waves flowing in opposite
directions. Anything short of that proof is just handwaving and gum
flapping on your part.

278W forward--
100W XMTR---50 ohm feedline---x---1/2WL 450 ohm feedline---50 ohm load
--178W reflected

You appear to misunderstand that it is essentially impossible to do
anything with all of your interfering component waves except wave your
hands and flap your gums about them.

If that is beyond your comprehension, just say so but, in reality, those
interfering component waves obey the laws of physics as explained in _Optics_,
by Hecht and on the Melles-Groit web page:

http://www.mellesgriot.com/products/optics/oc_2_1.htm

"Clearly, if the wavelength of the incident light and the thickness of the
film are such that a phase difference exists between reflections of p, then
REFLECTED WAVEFRONTS INTERFERE DESTRUCTIVELY, and overall reflected intensity
is a minimum. If the TWO REFLECTIONS are of equal amplitude, then this amplitude
(and hence intensity) minimum will be ZERO.

In the absence of absorption or scatter, the principle of CONSERVATION OF
ENERGY indicates all "lost" reflected intensity will appear as ENHANCED
INTENSITY [constructive interference] in the transmitted beam."

That's pretty clear - 100% destructive interference between the two rearward-
traveling reflected wave components - 100% of the energy involved in the destructive
interference is not lost and joins the forward-traveling wave since it has no
other possible direction.

FYI, the equations governing the irradiance involving a perfect non-glare
thin film a Ir1+Ir2-2*SQRT(Ir1*Ir2) = reflected irradiance = 0 and
If1+If2+2*SQRT(If1*If2) = total forward irradiance Page 388 of _Optics_.
--
73, Cecil http://www.qsl.net/w5dxp



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