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Richard Clark June 14th 08 08:42 PM

Efficiency and maximum power transfer
 
On Sat, 14 Jun 2008 09:40:26 -0700 (PDT),
wrote:

On Jun 14, 8:46*am, "Walter Maxwell" wrote:

I don't understand how my statement in the email above indicates that I^2*R and
V*R could be zero. The simple ratio of E/I is not zero, yet it defines a
resistance that is non-dissipative because a ratio cannot dissipate power.


Walt


Hi Walt -

If E and I are not zero, then E*I is not zero. But you are correct
that the equations themselves do not dissipate power. :-) Resistors
do, however. If there isn't an actual resistor located where you make
your measurement, then of course there's no power being dissipated
there.


Hi All,

It has taken considerable restraint not to ask some pointed questions:

1. Is a metal wire wound resistor NOT a resistance because it is not
carbon?

2. Is a carbon resistor NOT a resistance because it is not metal
wire-wound?

3. Is a Tube NOT a resistance because it contains no metal?

4. Is a Tube NOT a resistance because it contains no carbon?

5. Is a cathode resistor NOT a resistance when the tube conduction is
zero?

6. Is that same cathode resistor NOT a resistance because it conducts
non-linearly for some speciously constrained (and myopically chosen)
incomplete cycle of time?

finally, and possibly the only compelling logic that seems to flow
from this thread:

7. Is a Tube NOT a resistance simply because it lacks the familiar
shape of an axial lead resistor? (Or, rather, that a familiar axial
lead resistor cannot be found soldered between cathode and plate
within the vacuum?)

I have offered a spectrum of questions guaranteed to be accessible to
the buffet style of responding to cosmetic issues instead of
substance.

As this is all Rhetoric, I will take the author's prerogative to
short-cut the anticipated sputterings of denial, condemnation,
damnation, and outrage.

1. 2. 3. and 4. Carbon is a metal.

3. and 4. Plate dissipation bears scant relation to Ohmic Loss. And
yet there is heat there that is correlatably and causally related to
match, loss, and drive - from any "source."

4. there are many power tubes with Graphite (carbon) plates. The
original 813B comes to mind. Some power tubes have their screen grids
graphite (carbon) coated too! (Ohm's law still does not appreciably
account for plate dissipation.)

5. and 6. are sucker bait for those who would prove the world is
non-linear because of the discontinuity at the time of the big-bang
(or creation, take your pick).

7. Is, as I intimated, the implicit populist choice (masked as a
question) for those who cannot say what the source resistance IS, but
are over fulsome by half to say what it is NOT.

Describing what source resistance is NOT is like moving the stacks of
brass disks between the Towers of Hanoi. You can do that forever
without really coming to any conclusion. Given the length of many
threads that imitate this behavior, its popularity marks its less than
stupendous insights. But lest I interrupt the modern interpretation
of that game as it is played here, I would point out that parsing
"ratio" is even more funny. It sure beats Brett dragging the cesspool
for newspaper reports of cures for cancer.

-Phew-

73's
Richard Clark, KB7QHC

Owen Duffy June 14th 08 10:28 PM

Efficiency and maximum power transfer
 
"Walter Maxwell" wrote in
:


"Owen Duffy" wrote in message
...
(Richard Harrison) wrote in news:23000-
:

Jim Lux wrote:
"in a linear system"

It produces no significant harmonics, so the system is linear.


That is a new / unconventional definition of 'linear'.

The term is usually used in this context to mean a linear transfer
characteristic, ie PowerOut vs PowerIn is linear.

Considering a typical valve Class C RF amplifier with a resonant
load:

Conduction angle will typically be around 120°, and to achieve that,
the grid bias would be around twice the cutoff voltage.

If you attempted to pass a signal such as SSB though a Class C
amplifier that was biased to twice the cutoff value, there would be
no output signal when the peak input was less than about 50% max
drive voltage, or about 25% power, and for greater drive voltage
there would be output. How could such a transfer characteristic be
argued to be linear?

Owen


Owen, 'linear transfer characteristic' isn't the only context for the
use of the word 'linear'. Even though the input circuit of a Class C
amplifier is non-linear, the output is linear due to the energy
storage of the tank circuit that isolates the input from the output,
therefore, the output is linear. Proof of this is that the output
signal is a sine wave. In addition, the voltage and current at the
output terminals of the pi-network are in phase. Furthermore, the
ratio E/I = R appearing at the network output indicates that the
output source resistance R is non-dissipative, because a ratio cannot
dissipate power. This resistance R is not a resistor.


Hi Walt,

A few issues....

Yes, I understand the context in which you mean linear (though I have
issues with your proposition)... but my comment was referring to the
assertion that 'no harmonics' relates to linear operation which seems to
me to refer to the transfer characteristic linearity context.

I do have issue with your stated 'proof'. Firstly, I must qualify that we
are talking steady state... the mention of resonant loads means we are in
the frequency domain. Whilst it might seem that the tank circuit / pi
coupler / whatever is just a network of passive parts and they are all
linear, the energy that is supplied to that circuit in each cycle depends
on the resonant load impedance and traditional PA design methods suggest
that that Eout/Iout relationship is not linear for changes in load Z,
although it might be approximately linear over a small range.

I recognise a distinction between resistance (the ratio of E/I) and a
resistor (one type of component that exhibits resistance)... but I would
not claim that resistance is just a 'ratio' because it implies it is a
dimensionless ratio.

Owen


Alan Peake[_2_] June 15th 08 01:51 AM

Efficiency and maximum power transfer
 


Walter Maxwell wrote:
"Alan Peake" wrote in message


Alan, I disagree with you when you say that 'voltage to current' is not a ratio.
IMHO, your are definine 'ratio' to narrowly. Below is a quote from Google:
.............


Well, someone has redefined "ratio" since I went to school. My old maths
text book says "The term ratio is used when we wish to compare the size
ofr magnitude of two quantities (or numbers) of the same kind, i.e.,
expressed in the same units, and is measured by a fraction"
All my dictionaries say much the same thing. There is no mention of
comparing quantities of different units. That to me would be like
comparing apples with oranges.

Alan


Alan Peake[_2_] June 15th 08 02:09 AM

Efficiency and maximum power transfer
 


Richard Harrison wrote:

Some people are persuaded that resistance = loss. Not so at all.
Resistance is just a name given to the ratio of voltage to current.


If you define resistance as simply V/I with no regard to phase, then
what you say is true but if V and I aren't in phase then you have
impedance consisting of real and imaginary components - resistance AND
reactance.

Free-space has a lossless Zo of 120 pi (or 377 ohms) according to page
326 of Saveskie`s "Radio Propagation Handbook". This is a ratio which is
related to volts and amps but is actually the ratio of the electric
field strength to the magnetic field strength in an EM wave. The volts
and amps are in phase so it has the units of a pure resistance.


I suppose you could also say that a real resistor is also lossless as
the heat due to I*I*R is radiated into space and thus is not lost :)
Alan


Richard Harrison June 15th 08 03:33 AM

Efficiency and maximum power transfer
 
I found a note I intended to post but don`t see it so I suppose it was
lost in cyberspace somewhere. I was responding to Owen Duffy.

Owen wrote:
"How could such a transfer characteristic be argued to be linear?"

I responded:
Conditioning.

Class C amplifiers are used lawfully in great abundance. That is proof
enough that they are relatively free from distortion. Pulses in plate
current don`t prevent the output of the Class C amplifier from becoming
a pure sinusoid. Just as an internal combustion engine uses an almost
endless string of exlosions in its cylinders to produce a smooth uniform
rotation of its crankshaft and flywheel, the Class C amplifier uses an
almost endless series of pulses to produce a smooth sinusoid.

I will quote B. Whitfield Griffith, Jr., Principal Engineer (retired) at
Continental Electronics, Dallas Texas, builder of many of the world`s
most powerful radio transmitters. Griffith says on page 500 of
"Radio-Electronic Transmission Fundamentals", that it is important where
you couple the load to the Class C amplifier:
"Figure 56-2 shows how the class C amplifier might look in a typical
arrangement. Many refinements of the circuit, which are necessary for
practical reasons, are omitted here, since we are concerned only with
the fundamental principles of its operation at this time. The plate load
impedance consists of a tank circuit of a type similar ro that of Fig.
15-5; the difference is that the load resistor is in series with the
inductance rather than the capacitance. This is the preferred
arrangement, because the harmonic components of the plate current all
have frequencies higher than the fundamental and quite naturally tend to
follow the capacitive branch of the circuit. By extracting power from
the inductive branch, therefore we can expect to find less harmonic
energy in the output than would be present if we loaded the capacitive
branch. This load resistance may be an actual resistor, if we wish to
feed the output of this amplifier into a dummy load for measurement
purposes, or it may be the input resistance presented by some type of
impedance-matching network so arranged that the loading of the amplifier
can readily be varied. Another common method is to couple resistance
effectively into the tank inductance by means of the mutual inductance
between the tank and a secondary coil which is coupled to it
magnetically, where resistive loads appear in the secondary circuit.

There is also shown in Fig. 56-2 the r-f waveform of voltage and current
which we would expect to find at various points in the amplifier
circuit. No allowance is made in these illustrations for the differences
in potentials of various portions of the circuit; these diagrams are
merely representative of the behavior of the r-f potentials and
currents. Notice particularly that the r-f plate voltage is 180 degrees
out of phase with the r-f grid voltage. The reason for this is easily
understood. When the grid is its at its most positive potential, the
plate current is at its maximum. As the plate current is drawn through
the load impedance, the increase in plate current causes a corresponding
reduction in plate voltage. The plate voltage therefore swings downward
at the moment the grid voltage swings upward. We also see that the
current in the load resistor is lagging the r-f plate voltage by an
angle of a little less than 90 degrees. Correct operation of the tank
circuit requires that the resistance of this load resistor be much
smaller than the reactance of the coil."

Best regards, Richard Harrison, KB5WZI


Walter Maxwell June 15th 08 06:38 PM

Efficiency and maximum power transfer
 
"Richard Harrison" wrote in message
...
I found a note I intended to post but don`t see it so I suppose it was
lost in cyberspace somewhere. I was responding to Owen Duffy.

Owen wrote:
"How could such a transfer characteristic be argued to be linear?"

I responded:
Conditioning.

Class C amplifiers are used lawfully in great abundance. That is proof
enough that they are relatively free from distortion. Pulses in plate
current don`t prevent the output of the Class C amplifier from becoming
a pure sinusoid. Just as an internal combustion engine uses an almost
endless string of exlosions in its cylinders to produce a smooth uniform
rotation of its crankshaft and flywheel, the Class C amplifier uses an
almost endless series of pulses to produce a smooth sinusoid.

I will quote B. Whitfield Griffith, Jr., Principal Engineer (retired) at
Continental Electronics, Dallas Texas, builder of many of the world`s
most powerful radio transmitters. Griffith says on page 500 of
"Radio-Electronic Transmission Fundamentals", that it is important where
you couple the load to the Class C amplifier:
"Figure 56-2 shows how the class C amplifier might look in a typical
arrangement. Many refinements of the circuit, which are necessary for
practical reasons, are omitted here, since we are concerned only with
the fundamental principles of its operation at this time. The plate load
impedance consists of a tank circuit of a type similar ro that of Fig.
15-5; the difference is that the load resistor is in series with the
inductance rather than the capacitance. This is the preferred
arrangement, because the harmonic components of the plate current all
have frequencies higher than the fundamental and quite naturally tend to
follow the capacitive branch of the circuit. By extracting power from
the inductive branch, therefore we can expect to find less harmonic
energy in the output than would be present if we loaded the capacitive
branch. This load resistance may be an actual resistor, if we wish to
feed the output of this amplifier into a dummy load for measurement
purposes, or it may be the input resistance presented by some type of
impedance-matching network so arranged that the loading of the amplifier
can readily be varied. Another common method is to couple resistance
effectively into the tank inductance by means of the mutual inductance
between the tank and a secondary coil which is coupled to it
magnetically, where resistive loads appear in the secondary circuit.

There is also shown in Fig. 56-2 the r-f waveform of voltage and current
which we would expect to find at various points in the amplifier
circuit. No allowance is made in these illustrations for the differences
in potentials of various portions of the circuit; these diagrams are
merely representative of the behavior of the r-f potentials and
currents. Notice particularly that the r-f plate voltage is 180 degrees
out of phase with the r-f grid voltage. The reason for this is easily
understood. When the grid is its at its most positive potential, the
plate current is at its maximum. As the plate current is drawn through
the load impedance, the increase in plate current causes a corresponding
reduction in plate voltage. The plate voltage therefore swings downward
at the moment the grid voltage swings upward. We also see that the
current in the load resistor is lagging the r-f plate voltage by an
angle of a little less than 90 degrees. Correct operation of the tank
circuit requires that the resistance of this load resistor be much
smaller than the reactance of the coil."

Best regards, Richard Harrison, KB5WZI

Richard, I thoroughly enjoyed reading your post above on the analogy between the
action of the energy storage of the tank circuit and that of a automobile
engine, so I'd like you to read a portion of Chapter 19 from Reflections 2 to
see how I approached the same analogy for the book that I quote below:

Therefore, the pi-network must be designed to provide the equivalent
optimum resistance RL looking into the input for whatever load terminates the
output. The current pulses flowing into the network deliver bursts of electrical
energy to the network periodically, in the same manner as the spring-loaded
escapement mechanism in the pendulum clock delivers mechanical energy
periodically to the swing of the pendulum. In a similar manner, after each plate
current pulse enters the pi-network tank curcuit, the flywheel effect of the
resonant tank circuit stores the electromagnetic energy delivered by the current
pulse, and thus maintains a continuous sinusoidal flow of current throughout the
tank, in the same manner as the pendulum swings continuously and periodically
after each thrust from the escapement mechanism. The continuous swing of the
pendulum results from the inertia of the weight at the end of the pendulum, due
to the energy stored in the weight. The path inscribed by the motion of the
pendulum is a sine wave, the same as at the output of the amplifier. We will
continue the discussion of the flywheel effect in the tank circuit with a more
in-depth examination later.

.....

We now return to conduct a close examination of the vitally important
flywheel effect of the tank circuit. The energy storage (Q) in the tank produces
the flywheel effect that isolates the nonlinear pulsed energy entering the tank
at the input from the smoothed energy delivered at the output. As a result of
this isolation the energy delivered at the output is a smooth sine wave, with
linear voltage/current characteristics that support the theorems generally
restricted to linear operation. We know that the widely varying voltage/current
relationship at the tank input results in widely varying impedances, which
precludes the possibility of a conjugate match at the input of the tank circuit.
However, the energy stored in the tank provides constant impedance at the output
that supports both the Conjugate Matching and the Maximum Power-transfer
Theorems.1

The acceptance by many engineers and amateurs of the notion that the output
of the RF tank is nonlinear is a reason some readers will have difficulty in
appreciating that the output of the RF tank circuit is linear, and can thus
support the conjugate match. Valid analogies between different disciplines are
often helpful in clarifying difficulties in appreciating certain aspects of a
particular discipline. Fortunately, energy storage in the mechanical discipline
has a valid and rigorous analogous relationship with energy storage in LC
circuitry that makes it appropriate to draw upon a mechanical example to clarify
the effect of energy storage in the RF tank circuit. (A further convincing
analogy involving water appears later in the Chapter, in which the origin of the
term 'tank circuit' is revealed.)

The smoothing action of the RF energy stored in the tank circuit is
rigorously analogous to the smoothing action of the energy stored in the
flywheel in the automobile engine. In the automobile engine the flywheel smooths
the pulses of energy delivered to the crankshaft by the thrust of the pistons.
As in the tank circuit of the amplifier, the automobile flywheel is an energy
storage device, and the smoothing of the energy pulses from the pistons is
achieved by the energy stored in the flywheel. In effect, it is the flywheel
that delivers the energy to the transmission. The energy storage capacity
required of the flywheel to deliver smooth energy to the transmission is
determined by the number of piston pulses per revolution of the crankshaft. The
greater the number of pistons, the less storage capacity is required to achieve
a specified level of smoothness in the energy delivered by the flywheel. The
storage capacity of the flywheel is determined by its moment of inertia, and the
storage capacity of the tank circuit in the RF amplifier is determined by its Q.



Owen Duffy June 15th 08 10:58 PM

Efficiency and maximum power transfer
 
(Richard Harrison) wrote in news:26406-
:

....
Class C amplifiers are used lawfully in great abundance. That is proof
enough that they are relatively free from distortion. Pulses in plate
current don`t prevent the output of the Class C amplifier from becoming
a pure sinusoid.


.... a very long dissertation on Class C amplifiers snipped.

Richard, analysis of the Class C amplifier excited with a constant
amplitude single frequency sine wave is revealing about their transfer
linearity.

I do not disagree that a Class C amplifier excited with a constant
amplitude single frequency sine wave driving a resonant load produces a
low distortion constant amplitude single frequency sine wave output.

But the absence of harmonic distortion in such an amplifier is not
evidence that the amplifier transfer characteristic is linear. You may be
able to use harmonic distortion to detect non-linearity in, for example,
audio amplifiers... but not in RF amplifiers with a resonant load... for
the reasons set out in your quotation.

A Class C amplifier is unsuited to amplfying SSB telephony because it is
manifestly non-linear. In fact, a Class C amplifier is so non-linear that
it is well suited to use as a relatively efficient harmonic multiplier.

Class B and AB RF amplifiers are extremely sensitive to non-linearity in
the region near cut-off and must have sufficient idle current in every
active device (which means conduction ange is 180°) so that distortion
products are sufficiently low. This means that the theoretical conduction
angle of 180° for Class B is just not realisable because of distortion,
much less 120°.

Owen


Walter Maxwell June 16th 08 04:11 AM

Efficiency and maximum power transfer
 

"Owen Duffy" wrote in message
...
(Richard Harrison) wrote in news:26406-
:

...
Class C amplifiers are used lawfully in great abundance. That is proof
enough that they are relatively free from distortion. Pulses in plate
current don`t prevent the output of the Class C amplifier from becoming
a pure sinusoid.


... a very long dissertation on Class C amplifiers snipped.

Richard, analysis of the Class C amplifier excited with a constant
amplitude single frequency sine wave is revealing about their transfer
linearity.

I do not disagree that a Class C amplifier excited with a constant
amplitude single frequency sine wave driving a resonant load produces a
low distortion constant amplitude single frequency sine wave output.

But the absence of harmonic distortion in such an amplifier is not
evidence that the amplifier transfer characteristic is linear. You may be
able to use harmonic distortion to detect non-linearity in, for example,
audio amplifiers... but not in RF amplifiers with a resonant load... for
the reasons set out in your quotation.

A Class C amplifier is unsuited to amplfying SSB telephony because it is
manifestly non-linear. In fact, a Class C amplifier is so non-linear that
it is well suited to use as a relatively efficient harmonic multiplier.

Class B and AB RF amplifiers are extremely sensitive to non-linearity in
the region near cut-off and must have sufficient idle current in every
active device (which means conduction ange is 180°) so that distortion
products are sufficiently low. This means that the theoretical conduction
angle of 180° for Class B is just not realisable because of distortion,
much less 120°.

Owen

Sorry about the 'long dissertation on Class C amps', Owen, but I thought it
appropriate to include it in view of Richard's similar discussion on the
automotive engine analogy to the RF tank circuit. I'll try to keep my comments
shorter from now on.

Walt, W2DU



Walter Maxwell June 16th 08 04:11 AM

Efficiency and maximum power transfer
 

"Owen Duffy" wrote in message
...
(Richard Harrison) wrote in news:26406-
:

...
Class C amplifiers are used lawfully in great abundance. That is proof
enough that they are relatively free from distortion. Pulses in plate
current don`t prevent the output of the Class C amplifier from becoming
a pure sinusoid.


... a very long dissertation on Class C amplifiers snipped.

Richard, analysis of the Class C amplifier excited with a constant
amplitude single frequency sine wave is revealing about their transfer
linearity.

I do not disagree that a Class C amplifier excited with a constant
amplitude single frequency sine wave driving a resonant load produces a
low distortion constant amplitude single frequency sine wave output.

But the absence of harmonic distortion in such an amplifier is not
evidence that the amplifier transfer characteristic is linear. You may be
able to use harmonic distortion to detect non-linearity in, for example,
audio amplifiers... but not in RF amplifiers with a resonant load... for
the reasons set out in your quotation.

A Class C amplifier is unsuited to amplfying SSB telephony because it is
manifestly non-linear. In fact, a Class C amplifier is so non-linear that
it is well suited to use as a relatively efficient harmonic multiplier.

Class B and AB RF amplifiers are extremely sensitive to non-linearity in
the region near cut-off and must have sufficient idle current in every
active device (which means conduction ange is 180°) so that distortion
products are sufficiently low. This means that the theoretical conduction
angle of 180° for Class B is just not realisable because of distortion,
much less 120°.

Owen

Sorry about the 'long dissertation on Class C amps', Owen, but I thought it
appropriate to include it in view of Richard's similar discussion on the
automotive engine analogy to the RF tank circuit. I'll try to keep my comments
shorter from now on.

Walt, W2DU




Owen Duffy June 16th 08 04:32 AM

Efficiency and maximum power transfer
 
"Walter Maxwell" wrote in
:

Sorry about the 'long dissertation on Class C amps', Owen, but I
thought it appropriate to include it in view of Richard's similar
discussion on the automotive engine analogy to the RF tank circuit.
I'll try to keep my comments shorter from now on.


Walt, it wasn't so much that it was long, but it was long and for all
that was said, it didn't address the linearity issue.

I understand your position to be that the behaviour of the tank circuit
is independent of the transfer linearity of the active device... but
asserting that 'things' are linear because there are no harmonics is
wrong and being so, is no support for your argument.

I am wary of analogies, the switch analogy that was raised is not a good
approximation and I haven't even thought about the car engine.

I am genuinely insterested in your argument. I don't accept it (yet?) as
you know, and I have spent some time over the last 18 months or so
exploring the concept you describe.

Fundamentally, I am trying to reconcile what you say with the techniques
commonly accepted for designing such a PA. Those design techniques give
us a method of predicting power output at different load impedances, and
the E/I characteristic for different loads is not always a straight line
(as it would be if a Thevenin equivalent circuit exists), though it might
appear fairly straight over a narrow domain. Since working from
characteristic curves is so prone to error, my modelling has been based
on an idealised triode transfer characteristic, but with similar
behaviour to an 811A. The analysis is waiting for me to build the
analytical equations for the negative feedback due to cathode
degeneration in a grounded grid configuration. I need to apply more time
to it, and the revived discussion might focus me for a bit!

Owen

Richard Clark June 16th 08 07:07 AM

Efficiency and maximum power transfer
 
On Mon, 16 Jun 2008 03:32:23 GMT, Owen Duffy wrote:

The analysis is waiting for me to build the
analytical equations for the negative feedback due to cathode
degeneration in a grounded grid configuration.


Hi Owen,

Consult the work of H.W. Bode taken from his lectures at Bell Labs ca.
1939, and then rendered into text as:
Network Analysis and Feedback Amplifier Design,
Chapter IV Mathematical Definition of Feedback
4.2 Return Voltage and Reduction in Effect of Tube Variations p 46
It attends specifically (grounded grid triode) what you call out
above.

In a nutshell, Output (or Input) Z can be tailored by what is called
the "noise gain" of an amplifier. In today's parlance, that is that
portion of Open loop gain that is fed back to the input to create what
is called closed loop gain ("noise gain" is simply the difference when
all gains are expressed as dB). The higher the "noise gain" the lower
the output Z (or higher the input Z) compared to the native (open
loop) Z. There are a host of other characteristics improvements that
flow from this same boon offered by "noise gain" (dynamic range, noise
rejection, linearity, CMRR, PSRR, and so on).

This shorthand can be found expanded in discussion in
5.5 Effect of Feedback on Input and Output Impedances of
Amplifiers
bullets 1. through 4. but it serves the reader to really stick with
the first 4 chapters to gain the proficiency to tackle the remaining
15 as the text is heavily cross-referential.

The general formula can be found at:
5.11 Exact Formula for External Gain with Feedback (5-30)

Bode was not simply a chalk-and-talk theorist wholly ignorant of the
practical realities as are evidenced in several chapter headings:
Chapter VII Stability and Physical Realizability

Chapter IX Physical Representation of Driving Point Impedance
Functions

Chapter XI Physical Representation of transfer Impedance Functions

Chapter XIII General Restrictions on Physical Network
Characterizations

Ultimately, it takes very little reading applied to the conventional
designs found in Amateur class amplifiers to discover there is really
very, very little modification of amplifier characteristics offered
through negative feedback design (it costs too much). In fact, I
would say none whatever - hence the heavy filtering at the outputs and
the customers' universal acceptance of barely mediocre performance. It
might be said that every transmitter owned by hams is a museum of
1930s performance. And for those who mistake the feedback of
stabilization (barely found in those same cheap designs) - this is not
negative feedback, it is compensation. It too has scant effect on
tailoring (reducing/increasing) impedances.

As I am undoubtedly the only copy holder of this book in this group,
access can be obtained through:

http://books.google.com/books?client...G=Search+Books
which will provide a surplus of leads, if not the exact title. Some
links might provide a pdf, others full access, yet others limited
access, and most have links to copies in the market place.

Given the usual confusion over what constitutes a Conjugate match
(when most argue an Impedance match in its place) says discussion of
"Efficiency and maximum power transfer" without more rigorous
resources fails to even reach the level of tepid conjecture.

Bottom line is the source presents a real resistance and no appeal to
ratios, linearity, load lines, fly-wheels, or partial cycles is
necessary to arrive at a definitive value (which, to this point has
been notably absent in the face of obviously localized heat and loss).
There is plenty of discussion of what it is NOT, but none seem to know
what it IS. That the typical Amateur amplifier source Z is
demonstrable is embarrassment enough to this shortfall of expertise.
(The pile of theories, books and formulas merely support the obvious,
not replace it.)

73's
Richard Clark, KB7QHC

Tom Donaly June 16th 08 08:08 AM

Efficiency and maximum power transfer
 
Richard Clark wrote:
On Mon, 16 Jun 2008 03:32:23 GMT, Owen Duffy wrote:

The analysis is waiting for me to build the
analytical equations for the negative feedback due to cathode
degeneration in a grounded grid configuration.


Hi Owen,

Consult the work of H.W. Bode taken from his lectures at Bell Labs ca.
1939, and then rendered into text as:
Network Analysis and Feedback Amplifier Design,
Chapter IV Mathematical Definition of Feedback
4.2 Return Voltage and Reduction in Effect of Tube Variations p 46
It attends specifically (grounded grid triode) what you call out
above.

In a nutshell, Output (or Input) Z can be tailored by what is called
the "noise gain" of an amplifier. In today's parlance, that is that
portion of Open loop gain that is fed back to the input to create what
is called closed loop gain ("noise gain" is simply the difference when
all gains are expressed as dB). The higher the "noise gain" the lower
the output Z (or higher the input Z) compared to the native (open
loop) Z. There are a host of other characteristics improvements that
flow from this same boon offered by "noise gain" (dynamic range, noise
rejection, linearity, CMRR, PSRR, and so on).

This shorthand can be found expanded in discussion in
5.5 Effect of Feedback on Input and Output Impedances of
Amplifiers
bullets 1. through 4. but it serves the reader to really stick with
the first 4 chapters to gain the proficiency to tackle the remaining
15 as the text is heavily cross-referential.

The general formula can be found at:
5.11 Exact Formula for External Gain with Feedback (5-30)

Bode was not simply a chalk-and-talk theorist wholly ignorant of the
practical realities as are evidenced in several chapter headings:
Chapter VII Stability and Physical Realizability

Chapter IX Physical Representation of Driving Point Impedance
Functions

Chapter XI Physical Representation of transfer Impedance Functions

Chapter XIII General Restrictions on Physical Network
Characterizations

Ultimately, it takes very little reading applied to the conventional
designs found in Amateur class amplifiers to discover there is really
very, very little modification of amplifier characteristics offered
through negative feedback design (it costs too much). In fact, I
would say none whatever - hence the heavy filtering at the outputs and
the customers' universal acceptance of barely mediocre performance. It
might be said that every transmitter owned by hams is a museum of
1930s performance. And for those who mistake the feedback of
stabilization (barely found in those same cheap designs) - this is not
negative feedback, it is compensation. It too has scant effect on
tailoring (reducing/increasing) impedances.

As I am undoubtedly the only copy holder of this book in this group,
access can be obtained through:

http://books.google.com/books?client...G=Search+Books
which will provide a surplus of leads, if not the exact title. Some
links might provide a pdf, others full access, yet others limited
access, and most have links to copies in the market place.

Given the usual confusion over what constitutes a Conjugate match
(when most argue an Impedance match in its place) says discussion of
"Efficiency and maximum power transfer" without more rigorous
resources fails to even reach the level of tepid conjecture.

Bottom line is the source presents a real resistance and no appeal to
ratios, linearity, load lines, fly-wheels, or partial cycles is
necessary to arrive at a definitive value (which, to this point has
been notably absent in the face of obviously localized heat and loss).
There is plenty of discussion of what it is NOT, but none seem to know
what it IS. That the typical Amateur amplifier source Z is
demonstrable is embarrassment enough to this shortfall of expertise.
(The pile of theories, books and formulas merely support the obvious,
not replace it.)

73's
Richard Clark, KB7QHC


Hi Richard,
A more modern treatment is _High Linearity RF Amplifier
Design_ by Peter B. Kenington. ISBN 1-58053-143-1. I think Amazon
still carries it.
73,
Tom Donaly, KA6RUH

Jim Lux June 16th 08 04:32 PM

Efficiency and maximum power transfer
 
Owen Duffy wrote:
(Richard Harrison) wrote in news:23000-
:

Jim Lux wrote:
"in a linear system"

It produces no significant harmonics, so the system is linear.


That is a new / unconventional definition of 'linear'.

The term is usually used in this context to mean a linear transfer
characteristic, ie PowerOut vs PowerIn is linear.


Or, as I used it, that superposition holds.
One can build an amplifier or other device where the Pout(Pin) =straight
line, but is not linear in the formal sense. Say you built a widget that
measured the input frequency and amplitude, then drove a synthesizer at
that frequency and amplitude = 2*input amplitude.


Considering a typical valve Class C RF amplifier with a resonant load:

Conduction angle will typically be around 120°, and to achieve that, the
grid bias would be around twice the cutoff voltage.

If you attempted to pass a signal such as SSB though a Class C amplifier
that was biased to twice the cutoff value, there would be no output
signal when the peak input was less than about 50% max drive voltage, or
about 25% power, and for greater drive voltage there would be output. How
could such a transfer characteristic be argued to be linear?


It would not be.You're right

The active device isn't linear.
neither is the whole assembly.

I think, though, that sometimes we take a more casual view of linear
(e.g. people talk about the linearity of a log detector.. referring to
the deviation from a Voltage out=dBm in straight line.)

And, some confusion about nonlinear devices in a building block that is,
by and large, linear (e.g. a power op amp with an AB2 output stage and a
fair amount of negative feedback) with some constraints on frequency and
amplitude.

Owen


Jim Lux June 16th 08 04:42 PM

Efficiency and maximum power transfer
 
Richard Clark wrote:

Ultimately, it takes very little reading applied to the conventional
designs found in Amateur class amplifiers to discover there is really
very, very little modification of amplifier characteristics offered
through negative feedback design (it costs too much). In fact, I
would say none whatever - hence the heavy filtering at the outputs and
the customers' universal acceptance of barely mediocre performance. It
might be said that every transmitter owned by hams is a museum of
1930s performance. And for those who mistake the feedback of
stabilization (barely found in those same cheap designs) - this is not
negative feedback, it is compensation. It too has scant effect on
tailoring (reducing/increasing) impedances.



probably not "every transmitter", but certainly the vast majority of
designs, particularly those for HF based on tubes in the ARRL handbook
(and by extension, those sold to readers of the handbook).

Cost *is* a factor. The Harris PWM modular transmitters are very cool,
but beyond the means of most hams as a commercially manufactured item
(in that, the NRE for a consumer mfr to get there would be prohibitively
high)


One should also not neglect that the hobby aspect of ham radio provides
an incentive (for some) to preserve fine (or not so fine) examples of
past radio art. No more unusual than steam train fans or classic auto
collectors. There is a visceral satisfaction of seeing those glowing
tubes with the plates changing color, notwithstanding that the RF
performance, in objective terms, is horrid.





As I am undoubtedly the only copy holder of this book in this group,
access can be obtained through:

I'll bet not..grin

Richard Harrison June 16th 08 05:59 PM

Efficiency and maximum power transfer
 
Owen Duffy wrote:
"... but asserting that things are linear because there are no harmonics
is wrong and being so, is no support for your atgument."

No one is arguing that an amplitude modulated wave can be amplified by a
Class C amplifier stage unimpaired by amplitude distortion.

Terman wrote on page 525 0f his 1955 opus:
"Amplitude distortion exists when the modulation envelope contains
frequency components not present in the modulating signal. Thus if the
modulating signal is a sine wave, then amplitude distortion will cause
the envelope to contain harmonics of the modulating signal, which in
turn denotes the presence of high-order sideband components that differ
from the carrier frequency by harmonics of the modulating frequency."

I`ve used microwave system performance monitors which alarmed on this
principle.

If there are no harmonics there is no distortion no matter how lousy the
transfer function. It is legal to filter out noise and distortion.

Best regards, Richard Harrison, KB5WZI


Michael Coslo June 16th 08 07:44 PM

Efficiency and maximum power transfer
 
Richard Clark wrote:
On Mon, 16 Jun 2008 03:32:23 GMT, Owen Duffy wrote:

The analysis is waiting for me to build the
analytical equations for the negative feedback due to cathode
degeneration in a grounded grid configuration.


Hi Owen,

Consult the work of H.W. Bode taken from his lectures at Bell Labs ca.
1939, and then rendered into text as:



Hi Richard,

In this group, would not the work of Vaughn Bode be more appropriate?


- 73 de Mike N3LI -

Walter Maxwell June 16th 08 07:56 PM

Efficiency and maximum power transfer
 

"Jim Lux" wrote in message
...
Owen Duffy wrote:
(Richard Harrison) wrote in news:23000-
:

Jim Lux wrote:
"in a linear system"

It produces no significant harmonics, so the system is linear.


That is a new / unconventional definition of 'linear'.

The term is usually used in this context to mean a linear transfer
characteristic, ie PowerOut vs PowerIn is linear.


Or, as I used it, that superposition holds.
One can build an amplifier or other device where the Pout(Pin) =straight
line, but is not linear in the formal sense. Say you built a widget that
measured the input frequency and amplitude, then drove a synthesizer at
that frequency and amplitude = 2*input amplitude.


Considering a typical valve Class C RF amplifier with a resonant load:

Conduction angle will typically be around 120°, and to achieve that, the
grid bias would be around twice the cutoff voltage.

If you attempted to pass a signal such as SSB though a Class C amplifier
that was biased to twice the cutoff value, there would be no output
signal when the peak input was less than about 50% max drive voltage, or
about 25% power, and for greater drive voltage there would be output. How
could such a transfer characteristic be argued to be linear?


It would not be.You're right

The active device isn't linear.
neither is the whole assembly.

I think, though, that sometimes we take a more casual view of linear
(e.g. people talk about the linearity of a log detector.. referring to
the deviation from a Voltage out=dBm in straight line.)

And, some confusion about nonlinear devices in a building block that is,
by and large, linear (e.g. a power op amp with an AB2 output stage and a
fair amount of negative feedback) with some constraints on frequency and
amplitude.

Owen


Owen, I didn't realize that this thread was specific to 'linear transfer
characteristic'. I thought the thread topic was sufficiently broad so as to
include the subject of linearity of the output of the tank circuit that permits
the use of theorems that require the output to be linear. Richard H's and my
posts were simply reminders that the energy storage in the tank circuit is the
reason for the linear relation between voltage and current at the output of both
Class B and C amplifiers that results in a sine wave. From that perspective I
believed our posts were legitimate to the thread topic. Apparently we were
wrong.

And Owen, I'm somewhat surprised that you don't agree with the flywheel analogy
with respect to the smoothing effect of the energy storage in the tank circuit.
This analogy has been around for decades--it's not my invention. IMHO, the
periodic energy spurts from the pistons entering the flywheel is precisely an
analog of the energy spurts of the periodic current pulses entering the tank
citcuit. Why do you not agree? Even the pendulum swing is appropriate, because
if you trace the position of the pendulum with respect to time you'll discover
the trace is a perfect sine wave, while the short spurt of energy supplied by
the spring at the beginning of each cycle is just sufficient to overcome the
energy dissipated due to friction at the axis plus the aerodynamic resistance.
How could this not be an appropriate analogy? Sorry to have forced you away from
the thread topic with questions not pertaining to the thread.

I am also curious as to why the subject of 'linear transfer characteristic' with
respect to Class C amps was even considered, because the Class C amp has always
been known to have a distorted output relative to its input. I would agree that
the subject is appropriate when considering Class AB and B amplifiers, but not
C.

Walt, W2DU



Richard Clark June 16th 08 08:47 PM

Efficiency and maximum power transfer
 
On Mon, 16 Jun 2008 00:08:14 -0700, "Tom Donaly"
wrote:

Hi Richard,
A more modern treatment is _High Linearity RF Amplifier
Design_ by Peter B. Kenington. ISBN 1-58053-143-1. I think Amazon
still carries it.
73,
Tom Donaly, KA6RUH


Thanx Tom.

73's
Richard Clark, KB7QHC

Owen Duffy June 16th 08 10:13 PM

Efficiency and maximum power transfer
 
Jim Lux wrote in
:

....
That is a new / unconventional definition of 'linear'.

The term is usually used in this context to mean a linear transfer
characteristic, ie PowerOut vs PowerIn is linear.


Or, as I used it, that superposition holds.
One can build an amplifier or other device where the Pout(Pin)
=straight line, but is not linear in the formal sense. Say you built a
widget that measured the input frequency and amplitude, then drove a
synthesizer at that frequency and amplitude = 2*input amplitude.


Yes Jim, I should have written Vout/Vin is linear, that Vout(Vin) has no
significant terms higher than first order.

Noting that a single ended Class B or AB amplifier can only be linear
when a resonant load or suitable filter is included as part of the
system.

Elsewhere it was suggested that I do not accept the 'flywheel'
explanation of the tank circuit. That is not true, but it is a limited
explanation, simple, and appealing, but limited.

Another explanation is to view the anode current waveform as containing a
DC component, a fundamental component and harmonic components and a
filter that adequately reduces the undesired components provides the
solution to a single ended Class B or AB linear amplifier. The filter is
not restricted to a resonant 'tank' circuit.

I have modelled the operating characteristics of my HF linear using 4
572B in AB2. An FFT of the anode current reveals the spectral content, it
is plotted at http://www.vk1od.net/lost/572BIaSpectrum.png . Of course,
the output filter must only select the fundamental component for linear
operation, selection of a harmonic would not be acceptable for a complex
input waveform because it would destroy the absolute relationship between
different frequency components of the input.

Owen

Owen Duffy June 16th 08 10:14 PM

Efficiency and maximum power transfer
 
"Walter Maxwell" wrote in
:


"Jim Lux" wrote in message
...
Owen Duffy wrote:
(Richard Harrison) wrote in news:23000-
:

Jim Lux wrote:
"in a linear system"

It produces no significant harmonics, so the system is linear.

That is a new / unconventional definition of 'linear'.

The term is usually used in this context to mean a linear transfer
characteristic, ie PowerOut vs PowerIn is linear.


Or, as I used it, that superposition holds.
One can build an amplifier or other device where the Pout(Pin)
=straight line, but is not linear in the formal sense. Say you built
a widget that measured the input frequency and amplitude, then drove
a synthesizer at that frequency and amplitude = 2*input amplitude.


Considering a typical valve Class C RF amplifier with a resonant
load:

Conduction angle will typically be around 120°, and to achieve
that, the grid bias would be around twice the cutoff voltage.

If you attempted to pass a signal such as SSB though a Class C
amplifier that was biased to twice the cutoff value, there would be
no output signal when the peak input was less than about 50% max
drive voltage, or about 25% power, and for greater drive voltage
there would be output. How could such a transfer characteristic be
argued to be linear?


It would not be.You're right

The active device isn't linear.
neither is the whole assembly.

I think, though, that sometimes we take a more casual view of linear
(e.g. people talk about the linearity of a log detector.. referring
to the deviation from a Voltage out=dBm in straight line.)

And, some confusion about nonlinear devices in a building block that
is, by and large, linear (e.g. a power op amp with an AB2 output
stage and a fair amount of negative feedback) with some constraints
on frequency and amplitude.

Owen


Owen, I didn't realize that this thread was specific to 'linear
transfer characteristic'. I thought the thread topic was sufficiently


Richard stated "It produces no significant harmonics, so the system is
linear." It is that with which I disagree.

....
And Owen, I'm somewhat surprised that you don't agree with the
flywheel analogy with respect to the smoothing effect of the energy
storage in the tank circuit. ...


I have not disagreed with that in anything that I wrote.

...
I am also curious as to why the subject of 'linear transfer
characteristic' with respect to Class C amps was even considered,
because the Class C amp has always been known to have a distorted
output relative to its input. I would agree that the subject is
appropriate when considering Class AB and B amplifiers, but not C.


Because Richards statement quoted above (which must be about transfer
linearity) is being used to support your assertion that the PA is linear
in its terminal V/I response with changing load.

Walt, the thread has become muddled with helpers muddying the water. Your
proposition needs to be argued with a single logically developed sound
argument. Your Chapter 19 tries to do that.

I have already stated that (as yet?) I am unconvinced, and I make the
observation that I am not alone. I will work through resolving the
apparent inconsistencies in my own time and without the confusion of
whether or not harmonics exist or more correctly the extent to which they
exist, and what that might mean.

Owen

Jim Kelley June 17th 08 12:08 AM

Efficiency and maximum power transfer
 


Cecil Moore wrote:
wrote:

R is by definition a physical "property of conductors which depends on
dimensions, material, and temperature".



That's only one definition. From "The IEEE Dictionary",
the above is definition (A). Definition (B) is simply
"the real part of impedance" with the following Note:
"Definitions (A) and (B) are not equivalent but are
supplementary. In any case where confusion may arise,
specify definition being used."

Definition (B) covers Walt's non-dissipative resistance.
A common example is the characteristic impedance of
transmission line. In an ideal matched system V^2/Z0, I^2*Z0,
or V*I is the power being transferred under non-dissipative
conditions.


Yes. I agree with that, Cecil. But that's not the claim to which I
responded.

73, ac6xg


Richard Harrison June 17th 08 01:43 AM

Efficiency and maximum power transfer
 
Owen Duffy wrote:
"Richard stated "It produces no significant harmonics, so the system is
linear." It is that with which I disagree."

A clear statement. Congratulations. Too bad it is wrong.

Terman wrote:
"Amplitude distortion exists when the modulation envelope contains
frequency components not present in the modulating signal."

It is also true that absence of of harmonics is proof of linearity, as
in my microwave monitoring system alarm. No alarm, a linear system. An
alarm, a nonlinear system. I agree with Terman.

I challenge you to prove a mistake in Terman`s writings.

Best regards, Richard Harrison, KB5WZI


Owen Duffy June 17th 08 06:37 AM

Efficiency and maximum power transfer
 
(Richard Harrison) wrote in news:20731-
:

Owen Duffy wrote:
"Richard stated "It produces no significant harmonics, so the system is
linear." It is that with which I disagree."

A clear statement. Congratulations. Too bad it is wrong.

Terman wrote:
"Amplitude distortion exists when the modulation envelope contains
frequency components not present in the modulating signal."


Fine.

It is also true that absence of of harmonics is proof of linearity,


That is not a logical implication of your quote from Terman, it is
entirely your statement, and without splitting hairs over the absolute
meaning of 'absence', it is wrong when applied to a Class C amplifier
with pure sine wave excitation and a resonant load.

The converse is not logically equivalent to the original.

...
I challenge you to prove a mistake in Terman`s writings.


I have no problems with the statement you attribute to Terman and haven't
said anything contrary to that during the discussion.

Richard, I accept that you are committed to your view, lets leave it at
that. I don't think your statements on the matter support Walt's
proposition, rather since they are in my view flawed, I think they weaken
the body of evidence.

Owen

Walter Maxwell June 17th 08 09:50 PM

Efficiency and maximum power transfer
 

"Owen Duffy" wrote in message
...
(Richard Harrison) wrote in news:20731-
:

Owen Duffy wrote:
"Richard stated "It produces no significant harmonics, so the system is
linear." It is that with which I disagree."

A clear statement. Congratulations. Too bad it is wrong.

Terman wrote:
"Amplitude distortion exists when the modulation envelope contains
frequency components not present in the modulating signal."


Fine.

It is also true that absence of of harmonics is proof of linearity,


That is not a logical implication of your quote from Terman, it is
entirely your statement, and without splitting hairs over the absolute
meaning of 'absence', it is wrong when applied to a Class C amplifier
with pure sine wave excitation and a resonant load.

The converse is not logically equivalent to the original.

...
I challenge you to prove a mistake in Terman`s writings.


I have no problems with the statement you attribute to Terman and haven't
said anything contrary to that during the discussion.

Richard, I accept that you are committed to your view, lets leave it at
that. I don't think your statements on the matter support Walt's
proposition, rather since they are in my view flawed, I think they weaken
the body of evidence.

Owen


Owen, as I view your last paragraph above it seems apparent that you do not
believe Richard's and my position that the output of a Class C amplifier can be
linear. We're talking about at the 'output', not the 'thruput'. How can you
refute the evidence of a nearly pure sine wave at the output terminals of the
pi-network?

Walt, W2DU



Walter Maxwell June 17th 08 09:51 PM

Efficiency and maximum power transfer
 

"Owen Duffy" wrote in message
...
(Richard Harrison) wrote in news:20731-
:

Owen Duffy wrote:
"Richard stated "It produces no significant harmonics, so the system is
linear." It is that with which I disagree."

A clear statement. Congratulations. Too bad it is wrong.

Terman wrote:
"Amplitude distortion exists when the modulation envelope contains
frequency components not present in the modulating signal."


Fine.

It is also true that absence of of harmonics is proof of linearity,


That is not a logical implication of your quote from Terman, it is
entirely your statement, and without splitting hairs over the absolute
meaning of 'absence', it is wrong when applied to a Class C amplifier
with pure sine wave excitation and a resonant load.

The converse is not logically equivalent to the original.

...
I challenge you to prove a mistake in Terman`s writings.


I have no problems with the statement you attribute to Terman and haven't
said anything contrary to that during the discussion.

Richard, I accept that you are committed to your view, lets leave it at
that. I don't think your statements on the matter support Walt's
proposition, rather since they are in my view flawed, I think they weaken
the body of evidence.

Owen


Owen, as I view your last paragraph above it seems apparent that you do not
believe Richard's and my position that the output of a Class C amplifier can be
linear. We're talking about at the 'output', not the 'thruput'. How can you
refute the evidence of a nearly pure sine wave at the output terminals of the
pi-network?

Walt, W2DU




Owen Duffy June 17th 08 10:35 PM

Efficiency and maximum power transfer
 
"Walter Maxwell" wrote in
:
....
Owen, as I view your last paragraph above it seems apparent that you
do not believe Richard's and my position that the output of a Class C
amplifier can be linear. We're talking about at the 'output', not the
'thruput'. How can you refute the evidence of a nearly pure sine wave
at the output terminals of the pi-network?


Walt, you have posted this twice.

There are subtle word shifts here, you are saying "a Class C
amplifier can be linear" rather than is (always) linear.

It is true that a Class C amplifier with resonant load and a constant
amplitude sine wave drive may appear linear when comparing Vout to Vin.

But, as I explained earlier, if you vary the drive amplitude, it is
clearly not linear... in typical cases output will cease below about 25%
of the drive level required for maximum output.

Further, if you drive it with a complex waveform, it is clearly non
linear at any drive level.

Richard's solution to detecting RF PA distortion by monitoring harmonics
is an interesting one, because it suffers the disadvantage of output
filtering masking the harmonics (unless the monitor point was prior to
filtering).

The most widely accepted test for linearity (Vout/Vin) of an RF PA is the
'two tone test', where the drive is a complex waveform (the sum of two
equal amplitude sine waves quite close in frequency) and at least some of
the distortion products due to third order and fifth order etc transfer
terms appears in-band in the output after all output filtering, and where
they can be reliably compared in amplitude to the desired signals. A
Class C RF PA will not appear to be linear under such a test at any drive
level.

I suspect that the issue of transfer linearity is a red herring to your
proposition about the Thevenin equivalent of an RF PA, but if you do
depend on arguing that the transfer characteristic of a Class C RF PA is
linear, I think you are on shaky ground.

Owen

Walter Maxwell June 17th 08 10:59 PM

Efficiency and maximum power transfer
 

"Owen Duffy" wrote in message
...
"Walter Maxwell" wrote in
:
...
Owen, as I view your last paragraph above it seems apparent that you
do not believe Richard's and my position that the output of a Class C
amplifier can be linear. We're talking about at the 'output', not the
'thruput'. How can you refute the evidence of a nearly pure sine wave
at the output terminals of the pi-network?


Walt, you have posted this twice.

There are subtle word shifts here, you are saying "a Class C
amplifier can be linear" rather than is (always) linear.

It is true that a Class C amplifier with resonant load and a constant
amplitude sine wave drive may appear linear when comparing Vout to Vin.


Owen, with a Class C amplifier biased beyond cutoff the grid is never going to
see a constant amplitude sine wave, even if the constant amplitude sine wave
were impressed on the grid. How then can the transfer linearity ever occur under
these conditions? I maintain that it cannot.

But, as I explained earlier, if you vary the drive amplitude, it is
clearly not linear... in typical cases output will cease below about 25%
of the drive level required for maximum output.

Further, if you drive it with a complex waveform, it is clearly non
linear at any drive level.

Richard's solution to detecting RF PA distortion by monitoring harmonics
is an interesting one, because it suffers the disadvantage of output
filtering masking the harmonics (unless the monitor point was prior to
filtering).

The most widely accepted test for linearity (Vout/Vin) of an RF PA is the
'two tone test', where the drive is a complex waveform (the sum of two
equal amplitude sine waves quite close in frequency) and at least some of
the distortion products due to third order and fifth order etc transfer
terms appears in-band in the output after all output filtering, and where
they can be reliably compared in amplitude to the desired signals. A
Class C RF PA will not appear to be linear under such a test at any drive
level.

I suspect that the issue of transfer linearity is a red herring to your
proposition about the Thevenin equivalent of an RF PA, but if you do
depend on arguing that the transfer characteristic of a Class C RF PA is
linear, I think you are on shaky ground.

Owen


Owen, you are either twisting my words, or you're not listening. I've made it
very clear that I'm NOT talking about 'transfer linearity', and never have. My
position is only that the OUTPUT of the pi-network is linear. The linearity at
the output is irrelevant to the waveform at the input of the tank circuit in
Class C amplifiers. I don't even understand why the discussion concerning
'transfer linearity' with respect to Class C amplifiers should have come up.

Walt, W2DU

PS--I didn't send two identical emails--something must have happened at the
server to have caused it.



Richard Harrison June 17th 08 11:08 PM

Efficiency and maximum power transfer
 
Owen Duffy wrote:
"Richard, I accept that you are committed to your view. Let`s leave it
at that."

Owen is "throwing in the towel' but not admitting error.

I have no allegiance to a particular view. I am happy to view things
from another`s perspective. Owen mught do the same.

Owen Duffy also wrote:
"I understand your position to be that the behavior of a tank circuit is
independent of the transfer linearity of the active device...but
asserting that things are linear because there are no harmonics is wrong
and saying so is no support for your argument."

Owen has it wrong. The final amplifier is linear because its output is
an exact replica of its input except for amplitude, or close enough so.

When the waveshape of the output signal from an amplifier varies in any
respect other than amplitude from the waveshape of the signal feeding
the amplifier, the amplifier is distorting the signal.

Sinewave a-c is considered the perfect waveform. It consists of a single
frequency. Any other waveform consists of more than one frequency, So
the presence or absence of harmonics in addition to the fundamental is a
clear indication of distortion. Anyone can confirm waveform using an
oscilloscope.

Best regards, Richard Harrison, KB5WZI



Jim Lux June 17th 08 11:46 PM

Efficiency and maximum power transfer
 
Owen Duffy wrote:


The most widely accepted test for linearity (Vout/Vin) of an RF PA is the
'two tone test', where the drive is a complex waveform (the sum of two
equal amplitude sine waves quite close in frequency) and at least some of
the distortion products due to third order and fifth order etc transfer
terms appears in-band in the output after all output filtering, and where
they can be reliably compared in amplitude to the desired signals. A
Class C RF PA will not appear to be linear under such a test at any drive
level.


Actually, in modern systems with very complex signals, there are more
meaningful tests like noise power ratio with a notch that look for
spectral regrowth. The two tone test has the advantage of being
moderately easy to perform for middling performance amplifiers/devices.
But if you're looking for very high performance, such things as
generating the two tones without one generator interfering with the
other get to be challenging.



I suspect that the issue of transfer linearity is a red herring to your
proposition about the Thevenin equivalent of an RF PA, but if you do
depend on arguing that the transfer characteristic of a Class C RF PA is
linear, I think you are on shaky ground.


I don't know that the concept of a Thevenin equivalent (a linear circuit
theory concept) really has applicability to "box level" models, except
over a very restricted range, where one can wave one's hands and ignore
the nonlinearities as irrelevant to the question at issue. Sure, over a
restricted dynamic range and bandwidth and restricted class of input
signals, a Class C (or class E or Class F or E/F1, or a fancy EER
system) can be adequately modeled as a linear ideal amplifier.


The real question is what is the value of that model. If the model
provides conceptual understanding of some underlying problem, great. For
instance, it might help with a link budget. If the model helps design a
better amplifier, great. The model might allow prediction of behavior;
so that you can, for instance, detect a fault by the difference between
model and actual observation, as Richard mentioned with the harmonic
energy detector.




Owen


Richard Clark June 17th 08 11:47 PM

Efficiency and maximum power transfer
 
On Tue, 17 Jun 2008 17:08:12 -0500, (Richard
Harrison) wrote:

Owen has it wrong. The final amplifier is linear because its output is
an exact replica of its input except for amplitude, or close enough so.


Hi Richard,

This is a presumption that is either not in evidence, or it is forced
by the necessity of your argument. Consider:

When the waveshape of the output signal from an amplifier varies in any
respect other than amplitude from the waveshape of the signal feeding
the amplifier, the amplifier is distorting the signal.


The presumption (forced, or otherwise) is that the input is
sinusoidal. In fact, the cathode current of the amplifier proves
quite positively that only a pulse in, 120 degrees of the sinewave, or
even less, is sufficient to generate a remarkably clean sinewave at
the final's output.

Simply put, a pulse with a 33% duty cycle, and having sufficient
amplitude (and steep skirts) would present an output that was wholly
non-linear in relation to the pulse excitation. Looking only at the
output, you couldn't possibly say if the input was a complete 360
degrees of sine wave, or 33% DC of a rectangular wave. Not unless new
constraints are added that push the argument away from current issues.

To extend an analogy, the circular motion of the car's wheels prove
there is a non-linear relationship to the explosion of the gas mixture
in the compression cylinder.

Or to further decimate the argument, an oscillator produces as pure a
signal to no input at all (barring the excitation of noise that
engenders a selectively reinforced oscillation).

But the debate over linearity is window dressing to answering the
practical question:
What is the source resistance of any power amplifier?

I am not interested in the values that are NOT the source resistance.
I am content that those who have not responded to this specific and
observable characteristic don't know. However, given the thrashing of
this topic, someone (besides me) should.

73's
Richard Clark, KB7QHC

Owen Duffy June 18th 08 05:56 AM

Efficiency and maximum power transfer
 
Jim Lux wrote in
:

Owen Duffy wrote:

....
Actually, in modern systems with very complex signals, there are more
meaningful tests like noise power ratio with a notch that look for
spectral regrowth. The two tone test has the advantage of being
moderately easy to perform for middling performance
amplifiers/devices.
But if you're looking for very high performance, such things as
generating the two tones without one generator interfering with the
other get to be challenging.

Noted.


I suspect that the issue of transfer linearity is a red herring to
your proposition about the Thevenin equivalent of an RF PA, but if
you do depend on arguing that the transfer characteristic of a Class
C RF PA is linear, I think you are on shaky ground.


I don't know that the concept of a Thevenin equivalent (a linear
circuit theory concept) really has applicability to "box level"
models, except over a very restricted range, where one can wave one's
hands and ignore the nonlinearities as irrelevant to the question at
issue. Sure, over a restricted dynamic range and bandwidth and
restricted class of input signals, a Class C (or class E or Class F or
E/F1, or a fancy EER system) can be adequately modeled as a linear
ideal amplifier.


I agree with you. I am not implying that you cannot design a PA with
controlled equivalent source impedance, but you don't do they way most
ham PAs are designed.

As I understand it, Walt's proposition is that the Thevinin equivalent
source impedance (at the device terminals) of the PA is equal to the
conjugate of Zl (at the device terminals) as a consequence of adjustment
of the PA for maximum power output, a twist on the Jacobi MPT theorem.
For that model to be generally useful in explaining behaviour of the PA
in the presense of 'reflections', it would need to be true for a wide
range of load impedances.



The real question is what is the value of that model. If the model
provides conceptual understanding of some underlying problem, great.
For instance, it might help with a link budget. If the model helps
design a better amplifier, great. The model might allow prediction of
behavior; so that you can, for instance, detect a fault by the
difference between model and actual observation, as Richard mentioned
with the harmonic energy detector.


I think it goes to whether Walt's proposition and observations apply in
general, and then a valid explanation for what happens.

Owen


Tom Donaly June 18th 08 06:37 AM

Efficiency and maximum power transfer
 
Richard Harrison wrote:
Owen Duffy wrote:
"Richard, I accept that you are committed to your view. Let`s leave it
at that."

Owen is "throwing in the towel' but not admitting error.

I have no allegiance to a particular view. I am happy to view things
from another`s perspective. Owen mught do the same.

Owen Duffy also wrote:
"I understand your position to be that the behavior of a tank circuit is
independent of the transfer linearity of the active device...but
asserting that things are linear because there are no harmonics is wrong
and saying so is no support for your argument."

Owen has it wrong. The final amplifier is linear because its output is
an exact replica of its input except for amplitude, or close enough so.

When the waveshape of the output signal from an amplifier varies in any
respect other than amplitude from the waveshape of the signal feeding
the amplifier, the amplifier is distorting the signal.

Sinewave a-c is considered the perfect waveform. It consists of a single
frequency. Any other waveform consists of more than one frequency, So
the presence or absence of harmonics in addition to the fundamental is a
clear indication of distortion. Anyone can confirm waveform using an
oscilloscope.

Best regards, Richard Harrison, KB5WZI



From _Filtering in the Time and Frequency Domains_ by Herman J.
Blinchikov and Anatol I. Zverev: "A system is linear if the input
c1f1(t)+ c2f2(t) produces and output c1g1(t)+ c2g2(t) for all
f1(t) and f2(t), when it is known that an input f1(t) produces an
output g1(t) and an input f2(t) produces and output g2(t). The c1 and
c2 are arbitrary constants but may be complex numbers. This property of
superposition is characteristic of linear systems." You're ignoring the
addition part of the concept of linearity, Richard. Moreover, the
functions f1(t) and f2(t) don't have to be sine waves; the concept
is more general than that. Finally, read Richard Clark's post.
A sine wave out doesn't prove a sine wave in.
73,
Tom Donaly KA6RUH

Richard Harrison June 18th 08 09:39 AM

Efficiency and maximum power transfer
 
Richard Clark wrote:
"The presumption (forced or otherwise) is that the output is sinusoidal.
In fact, the cathode current of the amplifier proves quite positively
that only a pulse in, 180 degrees of sinewave, or even less, is
sufficient to generate a remarkably clean sinewave at the final`s
output."

That is a remarkably clear statement of the behavior of a Class C
amplifier. The amplifier acts as a generator of a sinewave which is
synchronized by its input signal instead of being an accurate reproducer
of the waveform at its input.

The less than half wave of current flow of the Class C amplifier allows
an efficiency exceeding 50%. Walt Maxwell`s tests show that the Class C
amplifier sticks to the parameters of a Thevenin source.

The question of "what is the source impedance" presented to a load by
the amplifier? is answered, not by magic, but by the maximum power
transfer theorem. The amplifier must be adjusted to deliver all its
available power. Then, the output impedance of the amplifier is simply
the conjugate of the load impedance which is easily measured.

Best regards, Richard Harrison, KB5WZI


Richard Clark June 18th 08 04:33 PM

Efficiency and maximum power transfer
 
On Wed, 18 Jun 2008 03:39:54 -0500, (Richard
Harrison) wrote:

The question of "what is the source impedance" presented to a load by
the amplifier? is answered, not by magic, but by the maximum power
transfer theorem. The amplifier must be adjusted to deliver all its
available power. Then, the output impedance of the amplifier is simply
the conjugate of the load impedance which is easily measured.


Hi Richard,

MPT Conjugate Match Z Match

You can NOT achieve the COMBINATION of any two, much less all three
with a Class C amplifier. This is like checking all three possible
answers on a multiple choice exam. It follows that source impedance
has not been answered here as a qualifiable (which is certainly not
what I was looking for).

I will take it that you don't know what the source impedance is as a
quantifiable either. That is, unless you unwind all the confounding
statements and remove those in error. There cannot be three,
simultaneous quantifiables of differing values.

73's
Richard Clark, KB7QHC

Walter Maxwell June 18th 08 04:42 PM

Efficiency and maximum power transfer
 

"Owen Duffy" wrote in message
...
Jim Lux wrote in
:

Owen Duffy wrote:

...
Actually, in modern systems with very complex signals, there are more
meaningful tests like noise power ratio with a notch that look for
spectral regrowth. The two tone test has the advantage of being
moderately easy to perform for middling performance
amplifiers/devices.
But if you're looking for very high performance, such things as
generating the two tones without one generator interfering with the
other get to be challenging.

Noted.


I suspect that the issue of transfer linearity is a red herring to
your proposition about the Thevenin equivalent of an RF PA, but if
you do depend on arguing that the transfer characteristic of a Class
C RF PA is linear, I think you are on shaky ground.


I don't know that the concept of a Thevenin equivalent (a linear
circuit theory concept) really has applicability to "box level"
models, except over a very restricted range, where one can wave one's
hands and ignore the nonlinearities as irrelevant to the question at
issue. Sure, over a restricted dynamic range and bandwidth and
restricted class of input signals, a Class C (or class E or Class F or
E/F1, or a fancy EER system) can be adequately modeled as a linear
ideal amplifier.


I agree with you. I am not implying that you cannot design a PA with
controlled equivalent source impedance, but you don't do they way most
ham PAs are designed.

As I understand it, Walt's proposition is that the Thevinin equivalent
source impedance (at the device terminals) of the PA is equal to the
conjugate of Zl (at the device terminals) as a consequence of adjustment
of the PA for maximum power output, a twist on the Jacobi MPT theorem.
For that model to be generally useful in explaining behaviour of the PA
in the presense of 'reflections', it would need to be true for a wide
range of load impedances.



The real question is what is the value of that model. If the model
provides conceptual understanding of some underlying problem, great.
For instance, it might help with a link budget. If the model helps
design a better amplifier, great. The model might allow prediction of
behavior; so that you can, for instance, detect a fault by the
difference between model and actual observation, as Richard mentioned
with the harmonic energy detector.


I think it goes to whether Walt's proposition and observations apply in
general, and then a valid explanation for what happens.

Owen

Owen, on whether my observations apply in general, if you re-read the
summarizing paragraph on my Chapter 19A you'll see that I've made measurements
of the source impedance of two different xmtrs with several different complex
impedance loads. All measurements showed the source impedance equal to the load
impedance when all available power is delivered to the load.

As to the explanation, Richard H said it well. When all available power is
delivered, according to the maximum power transfer theorem the source impedance
equals the load impedance. My measurements have proved this to be true in
determining the source impedance of the xmtrs I measured.

Walt, W2DU



Walter Maxwell June 18th 08 04:59 PM

Efficiency and maximum power transfer
 

"Richard Clark" wrote in message
...
On Wed, 18 Jun 2008 03:39:54 -0500, (Richard
Harrison) wrote:

The question of "what is the source impedance" presented to a load by
the amplifier? is answered, not by magic, but by the maximum power
transfer theorem. The amplifier must be adjusted to deliver all its
available power. Then, the output impedance of the amplifier is simply
the conjugate of the load impedance which is easily measured.


Hi Richard,

MPT Conjugate Match Z Match

You can NOT achieve the COMBINATION of any two, much less all three
with a Class C amplifier. This is like checking all three possible
answers on a multiple choice exam. It follows that source impedance
has not been answered here as a qualifiable (which is certainly not
what I was looking for).

I will take it that you don't know what the source impedance is as a
quantifiable either. That is, unless you unwind all the confounding
statements and remove those in error. There cannot be three,
simultaneous quantifiables of differing values.

73's
Richard Clark, KB7QHC


Hi Richard C,

Am I hearing you correctly? Are you disagreeing with Richard H? Are you saying
that maximum power transfer, conjugate match at the output, and Z match cannot
occur simultaneously? Are you serious? As I understand Everitt's statement of
the maximum-power-transfer theorem, when the maximum available power is being
transferred to the load there is a conjugate match. Does this not also mean
there is a 'Z' match? Can't 'Z' be assumed to be the impedance of the source as
well as the load?

Walt, W2DU



Richard Harrison June 18th 08 06:09 PM

Efficiency and maximum power transfer
 
Richard Clark wrote:
"I will take it that you don`t know what the source impedance is as a
quantifiable either."

Terman wrote on page 76 of his 1955 opus:
"Alternatively, a load impedance may be matched to a source of power in
such a way as to make the power delivered to the load a maximum. (The
power delivered under these conditions is termed the "available power"
of the power source.) This is accomplished by making the load impedance
the conjugate of the generator as defined by Thevenin`s theorem. That
is, the load impedance must have the same magnitude as the generator
impedance, but the phase angle of the load is the negative of the phase
angle of the generator impedance."

Best regards, Richard Harrison, KB5WZI


Richard Clark June 18th 08 07:44 PM

Efficiency and maximum power transfer
 
On Wed, 18 Jun 2008 11:59:40 -0400, "Walter Maxwell"
wrote:

Hi Richard C,

Am I hearing you correctly? Are you disagreeing with Richard H? Are you saying
that maximum power transfer, conjugate match at the output, and Z match cannot
occur simultaneously?


Hi Walt,

For a Class C tube amplifier.

All descriptions of tune-up for a Class C tube amplifier describe a
qualitative MPT as this classic method offers absolutely no
information about the quantitative degree of initial mismatch, nor
subsequent proximate match. In other words, there are no quantitative
values of load impedance revealed by this method. It may even be said
that the classic tune-up only describes "an attempt" at MPT; as it
may, in fact, not even achieve anything more than Mediocre Power
Transfer. After peaking the grid and dipping the plate, I have
observed many different peaks and dips for many various loads to know
that not all loads obtained all available power.

The classic description of a tune-up is based on qualitative
assumptions and the amplifier is brought into its best attempt, which
is not demonstrably efficient, nor even proven to be "matched"
conjugately or by impedance. This takes more information (so far
unrevealed) obtained by current into the known load (unrevealed), and
power into the source (unrevealed). No one other than myself has
expressed the loss of the source because no one else has ever
enumerated its resistance (a topic commonly hedged and avoided) Hence
discussion of efficiency is lost in the woods and correlation to
MPT/Z/Conjugation is equally doomed to ambiguity.

Are you serious? As I understand Everitt's statement of


Everitt notwithstanding, Lord Kelvin trumps him with
"when you cannot express it in numbers, your knowledge is of a
meagre and unsatisfactory kind"
This thread has suffered from a lack of measurables that are not that
difficult to obtain.

So, to return to my very specific question:
What is the source resistance of any power amplifier?
I will further loosen constraints (if that isn't loose enough)
For any match?

One complex number is sufficient, and certainly that value will
resolve all imponderabilities is what I am asking for.

73's
Richard Clark, KB7QHC

Walter Maxwell June 18th 08 07:47 PM

Efficiency and maximum power transfer
 

"Richard Harrison" wrote in message
...
Richard Clark wrote:
"I will take it that you don`t know what the source impedance is as a
quantifiable either."

Terman wrote on page 76 of his 1955 opus:
"Alternatively, a load impedance may be matched to a source of power in
such a way as to make the power delivered to the load a maximum. (The
power delivered under these conditions is termed the "available power"
of the power source.) This is accomplished by making the load impedance
the conjugate of the generator as defined by Thevenin`s theorem. That
is, the load impedance must have the same magnitude as the generator
impedance, but the phase angle of the load is the negative of the phase
angle of the generator impedance."

Best regards, Richard Harrison, KB5WZI

That's the way I understand it too, Richard. But also works in the opposite
direction too, by adjusting the source impedance to have the same magnitude and
opposite phase of the load impedance. This is the procedure I used to prove the
value of the source impedance.

Walt, W2DU



Walter Maxwell June 18th 08 10:16 PM

Efficiency and maximum power transfer
 

"Richard Clark" wrote in message
...
On Wed, 18 Jun 2008 11:59:40 -0400, "Walter Maxwell"
wrote:

Hi Richard C,

Am I hearing you correctly? Are you disagreeing with Richard H? Are you

saying
that maximum power transfer, conjugate match at the output, and Z match

cannot
occur simultaneously?


Hi Walt,

For a Class C tube amplifier.

All descriptions of tune-up for a Class C tube amplifier describe a
qualitative MPT as this classic method offers absolutely no
information about the quantitative degree of initial mismatch, nor
subsequent proximate match. In other words, there are no quantitative
values of load impedance revealed by this method. It may even be said
that the classic tune-up only describes "an attempt" at MPT; as it
may, in fact, not even achieve anything more than Mediocre Power
Transfer. After peaking the grid and dipping the plate, I have
observed many different peaks and dips for many various loads to know
that not all loads obtained all available power.

The classic description of a tune-up is based on qualitative
assumptions and the amplifier is brought into its best attempt, which
is not demonstrably efficient, nor even proven to be "matched"
conjugately or by impedance. This takes more information (so far
unrevealed) obtained by current into the known load (unrevealed), and
power into the source (unrevealed). No one other than myself has
expressed the loss of the source because no one else has ever
enumerated its resistance (a topic commonly hedged and avoided) Hence
discussion of efficiency is lost in the woods and correlation to
MPT/Z/Conjugation is equally doomed to ambiguity.

Are you serious? As I understand Everitt's statement of


Everitt notwithstanding, Lord Kelvin trumps him with
"when you cannot express it in numbers, your knowledge is of a
meagre and unsatisfactory kind"
This thread has suffered from a lack of measurables that are not that
difficult to obtain.


Richard, are you inferring that I have not submitted the measurables required to
determine the source impedances of the xmtrs I measured? What additional
measureables that I haven't already submitted are you asking for to prove the
source impedances that I've already submitted are valid?

So, to return to my very specific question:
What is the source resistance of any power amplifier?


Richard, the source impedance of one of the xmtrs I measured with load impedance
of 17.98 + j8.77 ohms measured 18 - j8 ohms. Considering measurement error,
wouldn't you agree that these two impedances qualify for a conjugate match, and
that this value of source impedance is valid at least within the realm of
possibility?

For any match?

One complex number is sufficient, and certainly that value will
resolve all imponderabilities is what I am asking for.


OK, Richard, is impedance 18 - j8 ohms sufficient?

Richard Clark, KB7QHC


Walt,W2DU




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