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Old September 17th 08, 08:09 PM posted to rec.radio.amateur.antenna
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Default Equilibrium and Ham examinations

On Sep 17, 3:25*am, Jeff Liebermann wrote:
On Wed, 17 Sep 2008 00:13:47 -0700, Jeff Liebermann
wrote:





On Tue, 16 Sep 2008 17:58:35 -0700, Richard Clark
wrote:


No Newtonians in this crowd. *Perhaps it was the relativistic term
"speed of light" that confused this group so much. *Let's restate it
in units that Newton could have appreciated.


We know that we can accelerate an electron to *167,770 miles/s - it
happens every femtosecond in one of any 100 billion crt
displays still glowing in the world. *Some of us know its mass at this
speed. *A question for the Newtonian philosopherz:
* * * *"What is the mass of a photon traveling at 167,770 miles/s?"


Google to the rescue:
http://asistm.duit.uwa.edu.au/synchrotron/downloads/pdfs/chapter11_7.pdf


mr / mo = 1 / (1 - (v^2/c^2))^0.5


whe
*mr = relativistic mass
*mo = mass at rest
*v *= velocity of particle
*c *= speed-o-light = 186,000 miles/sec


For v = 167,700 miles/sec
*mr/mo = 1/ (1 - (167,700^2 / 186,000^2))^0.5
*mr/mo = 1/ 1 - 0.813^0.5 = 1/ (1 - 0.902) = 1/ 0.0984 = 10.2


So, the mass of the particle at 90% the speed-o-light is 10 times that
of the particle at rest. *It doesn't matter what particle. *Do I get a
gold star?


(Somebody please check my arithmetic as I forgot to eat dinner, it's
after midnight, my brain is mush, and my calculator battery is fading
fast).


All wrong. *No gold star for that mess. *I just hate it when I click
"send" and only then discover my arithmetic error. *Rev 1.0 follows:

mr / mo = 1 / (1 - (v^2/c^2))^0.5

whe
* mr = relativistic mass
* mo = mass at rest
* v *= velocity of particle
* c *= speed-o-light = 186,000 miles/sec

For v = 167,700 miles/sec
* mr/mo = 1/ (1 - (167,700^2 / 186,000^2))^0.5
* mr/mo = 1/ (1 - 0.813)^0.5 = 1/ (0.187)^0.5 = 1/ 0.432 = 2.31

So, the mass of the particle at 90% the speed-o-light is 2.3 times
that of the particle at rest. *It doesn't matter what particle. *Maybe
a silver star?

--
# Jeff Liebermann 150 Felker St #D Santa Cruz CA 95060
# 831-336-2558 * * * * *
#http://802.11junk.com* * * * * * *
#http://www.LearnByDestroying.com* * * * * * * AE6KS- Hide quoted text -

- Show quoted text -


Not correct. It's not quite as simple as e = m*c**2. You must use the
Lorentz transformation.

Using the same values you have assiged to c and v, the correct
equation would be:

mr = mo/SQRT(1 - v**2/c**2)

As v = c, mr must = infinity (therefore no mass can reach c)
 
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