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Equilibrium and Ham examinations
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September 18th 08, 03:28 AM posted to rec.radio.amateur.antenna
Jeff Liebermann[_2_]
external usenet poster
First recorded activity by RadioBanter: Jun 2007
Posts: 1,336
Equilibrium and Ham examinations
On Wed, 17 Sep 2008 12:09:44 -0700 (PDT),
wrote:
On Sep 17, 3:25*am, Jeff Liebermann wrote:
wrote:
mr / mo = 1 / (1 - (v^2/c^2))^0.5
whe
* mr = relativistic mass
* mo = mass at rest
* v *= velocity of particle
* c *= speed-o-light = 186,000 miles/sec
For v = 167,700 miles/sec
* mr/mo = 1/ (1 - (167,700^2 / 186,000^2))^0.5
* mr/mo = 1/ (1 - 0.813)^0.5 = 1/ (0.187)^0.5 = 1/ 0.432 = 2.31
So, the mass of the particle at 90% the speed-o-light is 2.3 times
that of the particle at rest. *It doesn't matter what particle. *Maybe
a silver star?
Not correct. It's not quite as simple as e = m*c**2. You must use the
Lorentz transformation.
I didn't use e = m * c^2
Using the same values you have assiged to c and v, the correct
equation would be:
mr = mo/SQRT(1 - v**2/c**2)
That's exactly the same equation I used but with different notation.
It's still the square root:
SQRT(whatever) = (whatever)^0.5
Is there a standard notation or style for arithmetic and
exponentiation for usenet posting? I've been switching around using
different styles almost at random over the years.
I also divided both sides of the equation by mo to get the ratio of
relativistic mass to the at rest mass.
As v = c, mr must = infinity (therefore no mass can reach c)
Yep.
Go FTL (faster than light), and you get a cosmic speeding ticket.
--
Jeff Liebermann
150 Felker St #D
http://www.LearnByDestroying.com
Santa Cruz CA 95060
http://802.11junk.com
Skype: JeffLiebermann AE6KS 831-336-2558
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