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On Oct 24, 1:29*pm, wrote:
On Oct 24, 6:48 am, Michael Coslo wrote: Trying to make a "readers Digest" version here.... If I'm following so far: The lowered frequency of resonance is due to changes in the velocity factor. so as the wire gets thicker the C per unit length goes up at some rate and the L per unit length goes down at some other rate, fine so that reduces the characteistic Z by some rate....but none of that changes the wave velocity as was pointed out above in the coax example. I think the shortening effect may all be due to the extra C of the end surface, i.e it iss end effect. For a thick wire, the end is a circle that has C and this is all extra C that is not present for the thin wire. Is this extra C alone enough to create the shortening effect? Mark |
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