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Jim Kelley wrote:
I understand it well enough to note that it fails to make your point for you. You obviously don't understand why a signal that doesn't change phase cannot be used to measure a delay based on phase shift either through a wire or a coil. 1. Every reference says a pure standing wave does not change phase. 2. The current on a 75m mobile antenna is at least 90% standing wave current. 3. Therefo The phase of the current on a 75m mobile antenna cannot be used to measure the delay through the loading coil or even through the straight wire parts of the antenna. 4. Yet, this is exactly the current that w7el and w8ji used in their measurements which yielded "no detectable phase shift" completely unrelated to delay. Here's a question for you: What is the phase shift in the current in 90 degrees of an ideal lossless 1/4WL stub? Until you can provide a valid direct answer to that direct question, you will never understand. -- 73, Cecil, IEEE, OOTC, http://www.w5dxp.com |
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Cecil Moore wrote:
If that will keep your panties from getting bunched up, I am all for it. I'd really prefer that you refrained from commenting about my underwear - or even thinking about them. :-) ac6xg |
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Cecil Moore wrote:
Jim Kelley wrote: I understand it well enough to note that it fails to make your point for you. You obviously don't understand why a signal that doesn't change phase cannot be used to measure a delay based on phase shift either through a wire or a coil. 1. Every reference says a pure standing wave does not change phase. Certainly not as a function of time. Which means it's not an alternating current, and which is why it not considered an actual wave. 2. The current on a 75m mobile antenna is at least 90% standing wave current. And what's the other 10% supposed to be? Please explain how one would go about getting "standing wave current" to flow through something - anything - like a measuring instrument for example. 3. Therefo The phase of the current on a 75m mobile antenna cannot be used to measure the delay through the loading coil or even through the straight wire parts of the antenna. Have you tried pulsing a current through one? I can't imagine there wouldn't be a delay in getting from one end to the other and back. 4. Yet, this is exactly the current that w7el and w8ji used in their measurements No, it is not. Here's a question for you: What is the phase shift in the current in 90 degrees of an ideal lossless 1/4WL stub? I'm reminded of the troll at the bridge. To what phase shift do you refer? With respect to voltage, from one point to another, out and back - you need to be considerably less imprecise if you expect someone to bother to answer (to) you. ac6xg |
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Jim Kelley wrote:
A standing wave interference pattern is a result of the presence of traveling waves. One does not replace the other. Exactly what I have been saying for years against some stiff opposition - welcome aboard. You missed the point which is: If one parses all the energy to the standing wave, it cannot separately be parsed to the traveling waves. Doing so would violate the conservation of energy principle. I you were producing numbers which made sense and were correct, we wouldn't be having this discussion, Cecil. A wave is at various phases along it's length. The phase varies from 0 to 360 every complete cycle. This includes standing waves. Its phase is not "zero" at every point. You obviously don't understand. Whatever the actual phase angle is, for a pure standing wave, at any instant of time, it is constant all up and down the standing wave. NOBODY HAS EVER SAID IT IS ZERO AT EVERY POINT!!! Such an allegation is a ridiculous blowing of smoke. The EZNEC results you refer to are an archetypal example of the effect. The EZNEC results are what they are and have been confirmed by w7el himself. All I can say is: Please correct your mistaken concepts and then rejoin the discussion. What is it about the following EZNEC results that you don't understand? Do you need help in comprehending that a 2.71 degree phase shift in 90 degrees of antenna is a shortfall of 87.29 degrees? EZNEC+ ver. 4.0 thin-wire 1/4WL vertical 4/17/2009 2:57:42 PM --------------- CURRENT DATA --------------- Frequency = 7.29 MHz Wire No. 1: Segment Conn Magnitude (A.) Phase (Deg.) 1 Ground 1 0.00 2 .97651 -0.42 3 .93005 -0.83 4 .86159 -1.19 5 .77258 -1.50 6 .66485 -1.78 7 .54059 -2.04 8 .40213 -2.28 9 .25161 -2.50 10 Open .08883 -2.71 If w7el "measures" the phase shift between segment 3 and segment 7, he will "measure" 1.21 degrees. The actual delay between segment 3 and segment 7 is about 36 degrees. When will anyone understand that fact of physics? -- 73, Cecil, IEEE, OOTC, http://www.w5dxp.com |
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Jim Kelley wrote:
2. The current on a 75m mobile antenna is at least 90% standing wave current. And what's the other 10% supposed to be? The other 10% is the traveling wave that gets radiated of course (neglecting losses). Please explain how one would go about getting "standing wave current" to flow through something - anything - like a measuring instrument for example. Opps, standing wave current doesn't flow so you must have meant how does one eliminate reflections so that nothing except traveling wave current is present. Do you need that explained to you? Have you tried pulsing a current through one? I can't imagine there wouldn't be a delay in getting from one end to the other and back. Exactly, but some would say that's digital, not RF, or that is not steady-state conditions. 4. Yet, this is exactly the current that w7el and w8ji used in their measurements No, it is not. Sorry, you are wrong about that. w7el described in detail what he had measured and it was "total current" which was about 90% standing wave current. Here's what he said: "The result from the second test was a current difference of 5.4%, again with no measurable phase shift." All using the total antenna current which is about 90% standing wave current. What he didn't realize is that a current difference of 5.4% is a calculated phase shift of ~19 degrees, i.e. ARCCOS(1-.054) = ~19 degrees, to which you have previously alluded. Here's a question for you: What is the phase shift in the current in 90 degrees of an ideal lossless 1/4WL stub? I'm reminded of the troll at the bridge. I'm reminded of people who refuse to answer simple questions. One wonders why? The answer is zero degrees. To what phase shift do you refer? With respect to voltage, from one point to another, out and back - you need to be considerably less imprecise if you expect someone to bother to answer (to) you. The context was specified as current. Here is an EZNEC simulation which should help you. http://www.w5dxp.com/stub_dip.EZ Click on currents. You will see that the current phase varies by ~2 degrees end to end in 90 degrees of stub just as it does in a 1/4WL monopole over ground. -- 73, Cecil, IEEE, OOTC, http://www.w5dxp.com |
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Cecil Moore wrote:
The other 10% is the traveling wave that gets radiated of course (neglecting losses). Absurd. Current does not "get radiated". Please explain how one would go about getting "standing wave current" to flow through something - anything - like a measuring instrument for example. Opps, standing wave current doesn't flow so you must have meant how does one eliminate reflections so that nothing except traveling wave current is present. Do you need that explained to you? You claim that W7EL measured the phase shift of standing wave current. He of course made no such claim. So yes, I need you to explain how it is possible for someone do measure a "current" that does not flow. This should be good. ac6xg |
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Jim Kelley wrote:
Cecil Moore wrote: The other 10% is the traveling wave that gets radiated of course (neglecting losses). Absurd. Current does not "get radiated". It's *energy* in the traveling wave that gets radiated. Less energy indeed lowers the current amplitude. The Method Of Moments used by NEC assumes the radiated fields originate from the current in each segment of the antenna. Current is certainly attenuated by radiation as it is by dissipation in lossy transmission lines. In fact, the same attenuation factor is applied to the current equation as is applied to the voltage equation. The difference in the forward current vs the reflected current on the standing-wave antenna at the antenna feedpoint is due to energy lost to radiation. Radiation from an antenna indeed does lower the current on the antenna. The conservation of energy principle strikes again. You can prove it for yourself by modeling a terminated rhombic using EZNEC. The current amplitude in the traveling wave antenna slowly falls as the energy is radiated. Or put in one amp of 70cm current at one end of 200 feet of RG-58 and see how much current you get out at the other end. You don't really think that lumped circuit model assumptions apply to distributed networks, do you? You claim that W7EL measured the phase shift of standing wave current. He of course made no such claim. So yes, I need you to explain how it is possible for someone do measure a "current" that does not flow. This should be good. My point exactly. w7el "measured" the phase shift in current that doesn't flow. That was his entire problem. One cannot measure phase shift in current that doesn't flow, yet that's exactly what w7el and w8ji reported doing. -- 73, Cecil, IEEE, OOTC, http://www.w5dxp.com |
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Cecil Moore wrote:
Jim Kelley wrote: Cecil Moore wrote: The other 10% is the traveling wave that gets radiated of course (neglecting losses). Absurd. Current does not "get radiated". It's *energy* in the traveling wave that gets radiated. Less energy indeed lowers the current amplitude. Agreed. But when discussing current, one should recognize that, with the exception of "non-flowing current" whatever that is, all currents produce a field. Field cancellation is what prevents the transfer of energy. Any of this sounding familiar to you? The standing wave pattern is useful for illustrating what the field interference pattern might look like. w7el "measured" the phase shift in current that doesn't flow. :-) He's good, but he ain't that good. Besides, his meter is the same as yours in that it only responds to waves that travel and currents that flow. The difference I suspect, is in the desired outcome and the rhetoric. I've said my piece. 73, ac6xg |
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Jim Kelley wrote:
You claim that W7EL measured the phase shift of standing wave current. He of course made no such claim. So yes, I need you to explain how it is possible for someone do measure a "current" that does not flow. This should be good. I measured current (of which the definition is well understood except apparently by Cecil), and took a lot of care to do it right. Cecil doesn't like the result, so he's created an imaginary quantity he calls "standing wave current" as an attempt to invalidate the results and promote his imaginative theories. Since it's wholly his creation, its properties are free to be modified as the immediate argument requires. As I, Jim, other posters, and all good texts have explained, a standing wave describes the amplitude envelope of a voltage or current, as a function of position, which results from interference between traveling waves. There's no such thing as "standing wave current". You'll find no references to this fictitious entity in any electromagnetics text. Roy Lewallen, W7EL |
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"Art Unwin" wrote in message ... On Apr 16, 9:48 pm, Cecil Moore wrote: I don't worry about it Cecil but I am concerned at the number of people who consider themselves engineers. Remember that nobody on this group has a true understanding of Maxwells equations! Nobody has proved Maxwell's laws can be proved by adding a time varing field to the Gaussian law of Statics. In fact, it is denied by ALL on this group, Engineers? yes art, electrical engineers, like me, do understand maxwell's equations. and any of them worth their salt will explain, like i have done many times, that it is unecessary to add an explicit time variable to the equations because they are valid at every instant of time... so you end up with f(t)=f(t) which is redundant and doesn't help with the solution of the fields and waves. you have admitted that you don't know fields and waves and that you are not an ee, yet you continue to try to put down those who show a true understanding of the equations and their underlying assumptions. you further demonstrate this by talking about lumped impedances in reference to maxwell's equations and antennas. maxwell's equations describe fields and waves, not the conductors and elements that generate them. they reference the currents and fields, not the wires, capacitors, and inductors. you can derive the properties of inductors and capacitors from maxwell's equations, but you have to look deep inside them and apply the basic laws that make up maxwell's equation to describe the lumped elements. you have yet to explain where equilibrium is required in maxwell's equations. by definition they rely on non-equilibrium conditions to set up waves. you can't have a wave while you are in equilibrium, something has to be putting energy into the system and something has to be moving, that sounds like non-equilibrium to me. |
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