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#1
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Richard Harrison wrote:
The double-page figure is arranged into (8) vertical columns of radiation patterns. Each column is for a different physical spacing between the two parallel elements. All of the (5) patterns in a vertical column have the same physical space between elements. The only change between patterns in a vertical column is the phase angle between the two elements. Are they assuming equal currents into each element? That's the real trick. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#2
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Cecil, W5DXP wrote:
"Are they assuming equal currents into each element? That`s the real trick." The subscript says: "The two elements are assumed to be thin and self-resonant, with equal-amplitude currents flowing at the feed-point." If everything is symmetrical, the self-impedances and the mutual impedances of the two elements should be equal, producing equal powers into each element. Roy Lewallen may have been the source of a caution on phasing errors which appears on page 8-13 of the 19th edition of the ARRL Antenna Book. Roy is named on page 8-12. Kraus says on page 284 of the 1950 edition of "Antennas": "It is important that the antenna power W be considered constant.---Until the antenna power was considered constant by G.H. Brown (Proc. I.R.E., January 1937) the advantages of closely spaced elements were not apparent. Prior to this time the antenna current had usually been considered constant." Kraus took a G.H. Brown idea and ran with it producing the W8JK antenna. He had a lot of trouble gettinng the W8JK antenna story published due to naysayers. But it works despite its low impedance. Best regards, Richard Harrison, KB5WZI |
#3
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Richard Harrison wrote:
If everything is symmetrical, the self-impedances and the mutual impedances of the two elements should be equal, producing equal powers into each element. Unfortunately, it is not that easy except under special circumstances. The element with leading phase often has a different feedpoint impedance than the element with lagging phase. For instance: Given two 1/4WL monopoles, 1/4WL apart, and fed 90 degrees apart with one amp each will exhibit a gain of 3 dBi in one direction. However, the feedpoint of one element is 20-j20 and the feedpoint of the other element is 50+j20. The feedpoint voltages are obviously not equal so to equalize the current magnitudes takes some juggling. That' what Roy's BASIC program does - finds a solution if one exists. I once had a BASIC program that calculated the mutual impedances given the feedpoint impedance of one element alone and the feedpoint impedances of the two elements during operation but I seem to have misplaced it. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
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